Basic Integration

• I didn't look at my notes to see how to do this one.

∫ 6 x (x² +1 )² dx

• ( x² + 1)³ + C
• 3 ( x² + 1)³ + C
• ( x² + 1)¹ + C
• 6 ( x² + 1)³ + C

• A
• B
• C
• D

Find the answer of ∫ (2x-1)³dx?

• ⅛ (2x-1)² + c

• ⅛ (2x-1)⁴ + c

• ⅓ (2x-1)² + c

• 6(2x-1) + c

∫(3x⁴+2)⁴(12x³)dx

• ½(3x⁴+2)⁴+C
• (3x⁴+2)⁴+C
• ⅕(3x⁴+2)⁵+C
• ⅓(3x⁴+2)⁶+C

∫ 6 x (x² +1 )² dx

• ( x² + 1)³ + C

• 3 ( x² + 1)³ + C

• ( x² + 1)¹ + C

• 6 ( x² + 1)³ + C

∫ (2 - x)⁵ dx

• -5 (2 - x )⁴ + C

• ( 2 - x )⁶ + C

• (1/6) ( 2 - x )⁶ + C

• -(1/6) ( 2 - x )⁶ + C