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Geometria espazioan

Authored by Felicidad Jimenez

Mathematics

12th Grade

Geometria espazioan
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7 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Esan ondorengo zein zuzenetakoa den  (1,0, 3)\left(1,0,\ 3\right)  puntua

 x1=y=z3\frac{x}{1}=y=\frac{z}{3}  

 x1=y0=z3\frac{x}{1}=\frac{y}{0}=\frac{z}{3}  

 x1=y=z3x-1=y=z-3  

 x+11=y1=z+31\frac{x+1}{1}=\frac{y}{1}=\frac{z+3}{1}  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 v=(3,0,1)\overrightarrow{v}=\left(3,0,-1\right)  bektorea esan zein zuzenen NORABIDE BEKTOREA den

 x31=y2=z+11\frac{x-3}{1}=\frac{y}{2}=\frac{z+1}{1}  

 x+31=y=z15\frac{x+3}{1}=y=\frac{z-1}{5}  

 x3=y=z1\frac{x}{3}=y=\frac{z}{-1}  

 x3=y0=2z1\frac{x}{3}=\frac{y}{0}=\frac{2-z}{1}  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Esan ondorengo zein bektore den ondorengo bi planoek osatutako zuzenaren NORABIDE BEKTOREA:  
  2x+y=12x+y=1  
  x+z=3x+z=3  

 v=(1,3,0)\overrightarrow{v}=\left(1,3,0\right)  

 u=(1,1,2)\overrightarrow{u}=\left(1,1,2\right)  

 a=(1,2,3)\overrightarrow{a}=\left(1,-2,-3\right)  

 w=(1,2,1)\overrightarrow{w}=\left(1,-2,-1\right)  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kalkulatu ondorengo bi planoek osatutako zuzenaren PUNTU bat:
 2x+y=12x+y=1  
 x+z=3x+z=3  

 (1,3,1)\left(1,3,1\right)  

 (0, 1, 3)\left(0,\ 1,\ 3\right)  

 (0, 1,2)\left(0,\ 1,2\right)  

 (1, 0, 2)\left(1,\ 0,\ 2\right)  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kalkulatu  aa  parametroaren balioa  A=(1,2,0), B=(3,3,a)A=\left(1,2,0\right),\ B=\left(3,3,a\right)  eta  C=(5,4,10)C=\left(5,4,10\right)  puntua lerrokatuta egon daitezen.

 a=2a=2  

 a=0a=0  

 a=1a=1  

 a=5a=5  

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kalkulatu  kk  parametroaren balioa ondorengo bektoreak PLANOKIDEAK izan daitezen:

 a=(1,3,0)\overrightarrow{a}=\left(1,3,0\right)  
 b=(1,1,2)\overrightarrow{b}=\left(1,1,-2\right)  
 c=(1,0, a)\overrightarrow{c}=\left(1,0,\ a\right)  

 a=3a=3  

 a=3a=-3  

 a=0a=0  

 a=2a=-2  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Kalkulatu   aa  parametroaren balioa  (x,y,z)=(1,2,0)+t(1,0,4)\left(x,y,z\right)=\left(1,2,0\right)+t\left(1,0,4\right)  ZUZENA eta  xy+az=0x-y+az=0  PLANOA PARALELOAK izan daitezen.

 44  

 14\frac{-1}{4}  

 14\frac{1}{4}  

 22  

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