Quadratic Equations with Imaginary Solutions

Solve x² - 5x + 10 = 0.

• x = (5 - i√15)/2, (5 + i√15)/2

• x = (5 - √15)/2, (5 + √15)/2

• x = (5 - i√65)/2, (5 + i√65)/2

• x = (5 - √65)/2, (5 + √65)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Solve for x:

3x² - 6x + 6 = 0

• x = 1± i

• x = 3, -6

• x = 4.8, 2.7

• Undefined

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

The discriminant is

• ax² + bx + c

• b - 4ac

• b² - 4ac

• b² + 4ac

Tags

CCSS.HSA-REI.B.4B

Determine the value of the discriminant and describe the number and type roots for the following:

x² + 7x + 13

• 101; 2 real roots

• 3; 2 real roots

• -101; 2 imaginary roots

• -3; 2 imaginary roots

Tags

CCSS.HSA-REI.B.4B

Solve using the quadratic formula: f(x) = 2x² - 4x + 7

• x = (2 ± 2i√10)/2

• x = (4 ± √40)/4

• x = (2 ± i√10)√/2

• x = (2 ± 2i√40)/4

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

• no real solution

• 1 real solution

• 2 real solutions

• imaginary

• fake

• intangible

• i

• a

• e

• b

Tags

CCSS.HSN.CN.A.1

Solve using the square roots method. Write all answers in simplest form: 2x² + 9 = 1

• x = ±2i

• x = ±2

Tags

CCSS.HSA-REI.B.4B

Reorder the following steps for solving quadratics by square roots.

• REWRITE the equation as x² = n

• SIMPLIFY the radical. Place "±" to indicate both answers.

• Take the SQUARE ROOT of both sides

Tags

CCSS.HSA-REI.B.4B

g

h

i

f

-4

8

5

i

-5

√

10

-i

4

f

g

e

h

i

8

-3

-8

√

-1

3

-i