Solving Trig Equations on Different Intervals

Solve on the domain [0, 2π)
2sin x cos x = √2 cos x

• π/2, 3π/2

• 0, π/4, 3π/4

• π/2, 3π/2, π/4, 3π/4

• No solution

Which of the following is NOT
a solution to
sin θ = √(3) / 2 ?

• π / 3

• 2π / 3

• 5π / 3

• 7π / 3

Solve
cos²θ = ½ 
on θ∈[0, 2π)

• θ = π /4, 7π /4

• θ = π /4, 3π /4

• θ = 3π /4, 5π /4

• θ = π /4, 3π /4, 5π /4, 7π /4

2 sinθ+3=2

• π/6,2π/3

• 7π/6 

• 7π/6, 11π/6

Solve on the domain [0, 2π)
1/2sec x - 1 = 0

• π/6, 5π/6

• π/3, 5π/3

• 2π/3, 4π/3

• 7π/6, 11π/6

Solve on the domain [0, 2π)
cos² x + sin x + 1 = 0

• π

• 3π/2

• π/6, 5π/6, 3π/2

• No solution

Solve on the domain [0, 2π)
cos x + 2 = 3 cos x

• 0, 2π/3, 4π/3

• π

• 0

• No solution

Solve on the domain [0,2π)
1/4sin x + 1= 0

• 0

• 7π/4

• 5π/4

• No solution

Which of these is equivalent to 2cos²x − 3cosx = 0 ?

• -cos²x = 0

• cosx(2cosx + 3) = 0

• cosx(2cosx − 3) = 0

• cos x = ⅔

Which is a correct way to solve the equation

cosx(2cosx − 3) = 0?

• divide cos x from both sides

• set each factor equal to 0 and solve

• distribute cosx into the parentheses

• guess and hope for the best