Newton's Law of Cooling Problems

Given the equation T(t)=68e^-0.0174t + 72 which represents the temperature after t minutes, what would the temperature be after 1.5 hours?

• about 60^o F

• about 100^o F

• about 87^o F

• Wicked Cold

Tags

CCSS.HSF.IF.A.2

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

CCSS.HSF.LE.B.5

CCSS.HSN.Q.A.1

Given the that a hot pizza cools according to the equation P(t)=350e^-0.35t + 75 and Matt and Tyler like to eat their pizza when it is 110^o F, how long will they have to wait to eat their pizza?

• FOR-EV-ER

• about 6.5 minutes

• about 12.5 minutes

• about 1 minute

Tags

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.4

Which cooling equation correctly represents the following scenario:

Boiling soup is 100^oF when it is taken off of the stove in a 69^oF room. After 15 minutes the temperature of the soup is 95^oF.

• S(p)=31e^-0.011726t + 69

• S(p)=100e^-0.011726t + 69

• S(p)=31e^-.05435t + 100

• S(p)=31e^-.05435t + 69

Tags

CCSS.HSF.BF.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

Given the cooling equation S(t)=31e^-0.011726t + 69 where t is the amount of minutes and S(t) represents the temperature the soup, how long would it take for the soup to get to 80^oF?

• about 100 minutes

• about 46 minutes

• about 57 minutes

• about 88 minutes

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.SSE.A.1

CCSS.HSF.BF.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

Given the cooling equation S(p)=31e^-0.011726t + 69 where t is the amount of minutes and S(p) represents the temperature the soup, what would the temperature of the soup be after 2 and a half hours?

• about 64^oF

• about 74^oF

• about 84^oF

• about 94^oF

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

Which cooling equation correctly represents the following scenario:

A cooked turkey is 165^oF when it is taken out of the oven in a 75^oF room. After 30 minutes the temperature of the turkey is 145^oF.

• T(t)=90e^-0.148377t + 75

• T(t)=90e^-0.008377t + 75

• T(t)=75e^-0.148377t + 90

• T(t)=75e^-0.008377t + 90

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.2

CCSS.HSF.BF.A.1

CCSS.HSF.LE.A.1

CCSS.HSF.LE.A.2

Given the cooling equation T(t)=90e^-0.008377t + 75 where T(t) is the temperature of a turkey after t minutes, what would the temperature be after 50 minutes?

• about 200^oF

• about 164^oF

• about 134^oF

• about 104^oF

Tags

CCSS.HSA.SSE.A.1

CCSS.HSF.IF.B.5

CCSS.HSF.LE.A.1

Given the cooling equation T(t)=90e^-0.008377t + 75 where T(t) is the temperature of a turkey after t minutes, how long would it take for the turkey to reach 110^oF?

• about 101 minutes

• about 84 minutes

• about 131 minutes

• about 113 minutes

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.SSE.A.1

CCSS.HSF.LE.A.1