QUIIZ CIRCLES

What are the coordinates of the center and the radius of the circle with equation:
(x - 4)² + (y - 3)² = 25 ?

• Center (4,3)
  Radius = 5 units
• Center (4,3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 25 units
• Center (-4,-3)
  Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

What is the radius of (x + 2)² +(y - 5)² = 5

• 5
• 25
• √5
• (-2,5)

Tags

CCSS.HSG.GPE.A.1

• (x - 3)²  + (y + 4)² = 9
• (x - 3)²  + (y + 4)² = 3
• (x)²  + (y)² = 9
• (x - 1)²  + (y + 1)² = 7

Tags

CCSS.HSG.GPE.A.1

What is the center of the circle in the pictures?

• (3,2)

• (2,1)

• (1,2)

• (1,3)

Tags

CCSS.5.G.A.1

The radius of a circle is the distance from one endpoint to another endpoint through the center.

• True

• False

What is the radius of the circle based on this equation?

x²+y²=16

• 16

• 8

• 4

• 2

Tags

CCSS.HSG.GPE.A.1

• 75

• 37.5

Tags

CCSS.HSG.GPE.A.1

Write the equation of the circle in the picture.

• (x+9)²+y²=1

• (x-9)²+y²=1

• (x-9)²-y²=1

• (x+9)²-y²=1

Tags

CCSS.HSG.GPE.A.1

A circle has the equation  x² + y² - 12x + 8y + 3 = 0.  Use completing the square to write the equation in standard form.

• (x - 6)² + (y + 4)² = 49
• (x + 4)² + (y - 6)² = 49
• (x - 6)² + (y + 4)² = 55
• x² + y² = 55

Tags

CCSS.HSG.GPE.A.1

Change the following equation to standard form
x²+y²-4x+12y-8=0

• (x-2)²+(y-6)²=48
• (x-2)²+(y+6)²=48
• (x-6)²+(y-2)²=48
• (x+2)²+(y-6)²=48

Tags

CCSS.HSG.GPE.A.1