Completing the Square Concepts

Completing the Square Concepts

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Aiden Montgomery

FREE Resource

The video tutorial explains how to find the minimum value of a quadratic function by completing the square. It begins with an introduction to quadratic functions and the concept of minimum values. The method of completing the square is detailed, including common mistakes to avoid. An example problem is solved step-by-step to demonstrate the process. The lesson concludes with a summary of key points and the importance of rewriting quadratic functions to reveal minimum values.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal of rewriting a quadratic function in a different form?

To make the function more complex

To reveal the minimum value

To change the function's graph

To eliminate the x term

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in completing the square for a quadratic function?

Multiply all terms by 2

Isolate the x terms

Factor the quadratic expression

Add a constant to both sides

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When completing the square, what should you do after taking half of the middle term?

Multiply it by the leading coefficient

Square it and add inside the bracket

Add it to the constant term

Subtract it from the x term

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What common mistake do students make when completing the square?

Failing to preserve equation equality

Not isolating the x terms

Adding instead of subtracting

Forgetting to factor the trinomial

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the example y = x^2 - 12x + 49, what is the value added and subtracted during completing the square?

12

49

25

36

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the minimum value of the function y = x^2 - 12x + 49?

49

13

0

6

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What x value makes the square term zero in the function y = (x - 6)^2 + 13?

0

6

12

13

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