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WorksheetsGenetics Review
Total questions: 54
Worksheet time: 41mins
Mary has no freckles. If F for freckles, and f is for no freckles, what is Mary's genotype?
FF
Ff
ff
fF
TT x tt; T=tall & t=dwarf; What is the genotypic results?
50% TT, 50% tt
25% TT, 50% Tt, 25% tt
100% tt
100% Tt
Tt x Tt; T=tall & t=dwarf
What is the genotypic results?
50% TT, 50% tt
25% TT, 50% Tt, 25% tt
100% tt
100% Tt
Parents with the genotypes: AABb x AAbb
Which of the following genotype is NOT possible for their offspring?
AABb
Aabb
AAbb
Parents with the genotypes: AABb x AAbb
What is the possibility for them to have this offspring, AAbb?
1/2
1/4
1/8
2/16
What is the possible offspring genotypes for parents: HhTt x HhTt?
9:3:3:1
4:4:4:4
8:8
8:3:3:2
A sequence in your DNA that codes for a trait.
gene
allele
homozygous
chromosome
Different versions of the gene. For example: Eye color gene has blue, brown, hazel.
allele
gene
trait
DNA
Mendel came up with a theory that when plants are ready to reproduce, their traits are randomly shuffled before being distributed to its offspring.
Principle of Dominance
Law of Segreation
Law of Independent Assortment
homozygous x homozygous results would be...
25%, 50%, 25%
50%, 50%
100%
heterozygous x homozygous results would be...
25%, 50%, 25%
50%, 50%
100%
heterozygous x heterozygous results would be...
25%, 50%, 25%
50%, 50%
100%
The hair form gene shows incomplete dominance. Straight hair is dominant, curly hair recessive, and wavy hair is heterozygous. Mr. and Mrs. Anderson both have wavy hair. What are the phenotypic possibilities for their children? You may chose more than one answer.
25% curly
100% wavy
25% straight
50% wavy
Two cattle are crossed and 25% of the offspring are white, 25% are orange, and 50% are roan (orange and white spots). What were the parents?
Identify the pattern of inheritance from this pedigree chart.
Autosomal recessive
Autosomal dominant
X-linked recessive
X-linked dominant
This pedigree shows the inheritance of Rett's syndrome.
Which statement is TRUE based on this pedigree chart?
It only affects females in all generations.
It only affects males in only some generations.
It affects both genders and skips generations.
It affects both genders and occurs in all generations.
The traits of handedness and the condition Phenylketonuria (PKU) are found on different chromosomes. PKU is caused by a mutated recessive allele (p). A right-handed man (Rr) and a lefthanded women (rr) were both heterozygous for the PKU condition.
What are the genotypes of these two parents?
RrPp x rrPp
RrPp x RrPp
RrPP x Rrpp
RRPp x rrpp
The traits of handedness and the condition Phenylketonuria (PKU) are found on different chromosomes. PKU is caused by a mutated recessive allele (p). A right-handed man (Rr) and a lefthanded women (rr) were both heterozygous for the PKU condition.
What is the probability of a being left-handed with PKU?
1/8
1/4
3/16
1/2
This pedigree chart shows the inheritance of Hemophilia an X-linked recessive trait. Based on this pedigree, what are the genotypes of the parents (1, 2)?
XHXh x XHY
XhXh x XHY
XHXH x XHY
XHXH x XhY
This pedigree chart shows the inheritance of Hemophilia an X-linked recessive trait.
What is the probability of the daughter(3) and her husband (4) having a child with the trait?
50% for her sons, none for her daughters
50% for her sons, 25% for her daughters
50% for both sons and daughters
25% for both sons and daughters
Identify the pattern of inheritance from this pedigree chart.
Autosomal recessive
Autosomal dominant
X-linked recessive
X-linked dominant
Cactus spines: Homozygous- two or one; Heterozygous - both two & one. Flowers: Homozygous- red or yellow; Heterozygous- orange.
One cactus with two spines, orange flowers is crossed with a mixed spines, yellow flowers.
What is the probability for an offspring with two spines, yellow flowers?
1/2
1/4
1/8
1/16
Parents (1,2) have blood type O.
What is the possible genotypes of wife (4) if their child is type B?
ii
IAi
IAIB
IBi
In generation 2, their first child was heterozygous for diabetes. What is the probability that their next child will be heterozygous?
25%
50%
75%
0%
Dwarfism is dominant trait, but a homozygous dominant is lethal.
Two heterozygous individuals are expecting their first child. What is the probability the child will survive?
25%
50%
75%
0%
In the formula for Chi Sqare, the O stands for
the sum
the observed frequency
The expected frequency
the p value
In the formula for Chi Sqare, the E stands for
the sum
the observed frequency
The expected frequency
the p value
Chi square tests for
goodness of fit
test of independence
do these jean fit
does the shoe fit
If the chi square value is less than the p value then you
the null hypothesis is accepted.
the null hypothesis is rejected.
the null hypothesis neither accepted or rejected.
the null hypothesis is still in question.
The null hypothesis
states that the difference will always be the same.
states that there will be zero difference between observed & expected.
states that the difference between the observed & expected will be insignificant.
states that everything is wrong and rejected.
In a AaBb x AaBb, what is the expected phenotypic ratio?
4:4:4:4
8:8
9:3:31
10:4:3:1
Between two heterozygous dihybrids, what do you expect for the two dominant traits in 1000?
562.5
487.5
187.5
62.5
Between two heterozygous dihybrids, what do you expect for the two recessive traits in 1000?
562.5
487.5
187.5
62.5
AaBb x AaBb results in 612 A-B-, 201 A-bb, 175 aaB-, and 12 aabb. What is the chi square value? Is it acceptable with range of the expected?
4.356, acceptable
46.965, not acceptable
0.972, acceptable
40.804, not acceptable
In a Heterozygous crossed with a Homozygous, what phenotypic ratio do you expect of 100 offsprings?
4:0
3:1
2:2
9:3:3:1
Coin Toss: Ms. Aquino asked everyone in all her classes to flip a coin. There results were = 87 heads & 73 tails. Based on the chi square, is this within acceptable range of expected.
Yes w/ chi square of 0.6125
Yes w/ chi square of 1.225
No w/ chi square of 6.125
No w/ a chi square of 1.225
For the M & M chi square calculations, we counted up the colors: Brown, Blue, Orange, Red, Yellow, and Green. What is the degrees of freedom we use on the chi square critical value?
6
5
4
3
