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Trigonometry (Intermediate)

Total questions: 10

Worksheet time: 5mins

Name
Class
Date
1.

Which of the following graphs represent the function  f(x)=cos⁡(2x)f\left(x\right)=\cos\left(2x\right) ?

a)
b)
c)
d)
2.

Which of the following is true?

a)

Sine is positive in the first and third quadrants.

b)

Cosine is negative in the first and fourth quadrants.

c)

Tangent is negative in the second and fourth quadrants.

d)

Sine is negative in the second and third quadrants.

3.

Calculate the value(s) of  θ\theta such that  cos⁡(θ)=−12\cos\left(\theta\right)=-\frac{1}{2} for  0≤θ≤2π0\le\theta\le2\pi .  

a)

 θ=2π3,4π3\theta=\frac{2\pi}{3},\frac{4\pi}{3}  

b)

 θ=π3,2π3\theta=\frac{\pi}{3},\frac{2\pi}{3}  

c)

 θ=2π3\theta=\frac{2\pi}{3}  

d)

 θ=π3,5π3\theta=\frac{\pi}{3},\frac{5\pi}{3}  

4.

Calculate the value(s) of  θ\theta such that  tan⁡(2θ)=3\tan\left(2\theta\right)=\sqrt{3}  for  0≤θ≤2π0\le\theta\le2\pi . 

a)

 θ=π6,2π3\theta=\frac{\pi}{6},\frac{2\pi}{3}  

b)

 θ=π6,2π3, 7π6,6π5\theta=\frac{\pi}{6},\frac{2\pi}{3},\frac{\ 7\pi}{6},\frac{6\pi}{5}  

c)

 θ=π3,4π3, 7π3,12π5\theta=\frac{\pi}{3},\frac{4\pi}{3},\frac{\ 7\pi}{3},\frac{12\pi}{5}  

d)

 θ= 7π6,6π5\theta=\frac{\ 7\pi}{6},\frac{6\pi}{5}  

5.

Solve the equation 2sin⁡(θ)=tan⁡(θ)2\sin\left(\theta\right)=\tan\left(\theta\right) for  0∘≤θ≤360∘0^{\circ}\le\theta\le360^{\circ} . 
Note: Use the fact that tan⁡(θ)=sin⁡(θ)cos⁡(θ)\tan\left(\theta\right)=\frac{\sin\left(\theta\right)}{\cos\left(\theta\right)} .

a)

 θ=0∘,30∘,90∘,150∘,180∘\theta=0^{\circ},30^{\circ},90^{\circ},150^{\circ},180^{\circ}  

b)

 θ=0∘,180∘,360∘\theta=0^{\circ},180^{\circ},360^{\circ}  

c)

 θ=0∘,60∘,180∘,300∘,360∘\theta=0^{\circ},60^{\circ},180^{\circ},300^{\circ},360^{\circ}  

d)

 θ=0∘,300∘\theta=0^{\circ},300^{\circ}  

6.

For 0∘≤θ≤360∘0^{\circ}\le\theta\le360^{\circ} , solve  6cos⁡2(θ)+6cos⁡(θ)−1=06\cos^2\left(\theta\right)+6\cos\left(\theta\right)-1=0 . 

a)

 θ=81.6∘,120∘,240∘,278.4∘\theta=81.6^{\circ},120^{\circ},240^{\circ},278.4^{\circ}  

b)

 θ=81.6∘,120∘\theta=81.6^{\circ},120^{\circ}  

c)

 θ=240∘,120∘\theta=240^{\circ},120^{\circ}  

d)

 θ=81.6∘, 278.4∘\theta=81.6^{\circ},\ 278.4^{\circ}  

7.

Solve the equation sin⁡2(θ)+3cos⁡(2θ)=2\sin^2\left(\theta\right)+3\cos\left(2\theta\right)=2 for  0≤θ≤360°0\le\theta\le360\degree^{ } . Give your answer(s) to 1 decimal place.  
Note: Use the fact that  cos⁡(2θ)=1−2sin⁡2(θ)\cos\left(2\theta\right)=1-2\sin^2\left(\theta\right)  

a)

 θ=153.4∘\theta=153.4^{\circ}  

b)

 θ=26.6∘\theta=26.6^{\circ}  

c)

 θ=26.6∘,153.4∘\theta=26.6^{\circ},153.4^{\circ}  

d)

 θ=26.6∘,153.4∘,206.6∘,333.4∘\theta=26.6^{\circ},153.4^{\circ},206.6^{\circ},333.4^{\circ}  

8.

A right-angled triangle XYZ has an angle, \theta , where  sin⁡(θ)=55\sin\left(\theta\right)=\frac{\sqrt{5}}{5} . Without evaluating θ\theta , calculate the exact value(in surd form if applicable) of cos⁡(θ)\cos\left(\theta\right) .    

a)

 cos⁡(θ)=25\cos\left(\theta\right)=2\sqrt{5}  

b)

 cos⁡(θ)=25\cos\left(\theta\right)=\frac{2}{5}  

c)

 cos⁡(θ)=55\cos\left(\theta\right)=\frac{\sqrt{5}}{5}  

d)

 cos⁡(θ)=255\cos\left(\theta\right)=\frac{2\sqrt{5}}{5}  

9.

A right-angled triangle XYZ has an angle, \theta , where  sin⁡(θ)=55\sin\left(\theta\right)=\frac{\sqrt{5}}{5} . Without evaluating θ\theta , calculate the exact value(in surd form if applicable) of sin⁡(2θ)\sin\left(2\theta\right) .    
Note: Use the fact that  sin⁡(2θ)=2sin⁡(θ)cos⁡(θ)\sin\left(2\theta\right)=2\sin\left(\theta\right)\cos\left(\theta\right) . 

a)

 sin⁡(2θ)=45\sin\left(2\theta\right)=\frac{4}{5}  

b)

 sin⁡(2θ)=15\sin\left(2\theta\right)=\frac{1}{5}  

c)

 sin⁡(2θ)=255\sin\left(2\theta\right)=\frac{2\sqrt{5}}{5}  

d)

 sin⁡(2θ)=105\sin\left(2\theta\right)=\frac{\sqrt{10}}{5}  

10.

A wire in the form of a circle with radius 4 cm is reshaped into the form of a sector of a circle with radius 10 cm. Determine, in radians, the angle of the sector, giving your answer in terms of π\pi . 

a)

 θ=4π5−1\theta=\frac{4\pi}{5}-1  

b)

 θ=2(2π−5)5\theta=\frac{2\left(2\pi-5\right)}{5}  

c)

 θ=4π5\theta=\frac{4\pi}{5}  

d)

 θ=4(2π−5)\theta=4\left(2\pi-5\right)