WorksheetsFourier series Basics
Total questions: 10
Worksheet time: 7mins
The value of sin nπ is
1
0
-1
n
The value of cos nπ= ------ and Cos 0=-------
0 and 0
(−1)n and 0
(−1)n and 1
1 and 1
The value of cos 2π and cos π
0 and 0
1 and 1
1 and -1
-1 and -1
The value of ∫cos5x dx =
5 sin5x
-5sin5x
5sin5x
−5sin5x
The value of ∫0π sin3x dx
32
−32
0
31
dxd(x2) =
x
2
2x
0
dxd(k)= -------where k is constant
1
k
0
x
∫02π x sinx dx =
∣x(−cosx)−(−sinx)∣
∣x(cosx)−(sinx)∣
∣x(−cosx)−(−sinx)∣02π = 0
∣x(−cosx)−(−sinx)∣02π = −2π
∫02π x cosnx dx =
∣x(sinx)(−cosx)∣
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣02π =0
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣02π =2
∫02π x cos(lnπ )x dx =
∣∣∣x(sin(lnπ )x)(−cos(lnπ )x)∣∣∣
∣∣∣∣∣x((lnπ )sin(lnπ )x)−(−(lnπ )2cos(lnπ )x)∣∣∣∣∣
∣∣∣∣∣x((lnπ )sin(lnπ )x)−(−(lnπ )2cos(lnπ )x)∣∣∣∣∣02π
= 0
∣∣∣∣x(nsinnx)−(−n2cosnx)∣∣∣∣02π
=2
