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Fourier series Basics

Total questions: 10

Worksheet time: 7mins

Name
Class
Date
1.

The value of sin nπn\pi  is

a)

1

b)

0

c)

-1

d)

n

2.

The value of cos nπ=n\pi=  ------ and  Cos 0=-------

a)

0 and 0

b)

 (−1)n\left(-1\right)^n   and 0

c)

 (−1)n\left(-1\right)^n  and 1

d)

1 and 1

3.

The value of cos 2π2\pi  and cos π\pi  

a)

0 and 0

b)

1 and 1

c)

1 and -1

d)

-1 and -1

4.

The value of  ∫cos⁡5x dx\int_{ }^{ }\cos5x\ dx  =

a)

5 sin5x

b)

-5sin5x

c)

 sin⁡5x5\frac{\sin5x}{5}  

d)

 −sin⁡5x5-\frac{\sin5x}{5}  

5.

The value of ∫0π sin⁡3x dx\int_0^{\pi}\ \sin3x\ dx  

a)

 23\frac{2}{3}  

b)

 −23-\frac{2}{3}  

c)

0

d)

 13\frac{1}{3}  

6.

 ddx(x2) =\frac{\text{d}}{\text{d}x}\left(x^2\right)\ =  

a)

x

b)

2

c)

2x

d)

0

7.

 ddx(k)=\frac{\text{d}}{\text{d}x}\left(k\right)=  -------where k is constant

a)

1

b)

k

c)

0

d)

x

8.

 ∫02π  x sin⁡x dx\int_0^{2\pi}\ \ x\ \sin x\ dx  =

a)

 ∣x(−cos⁡x)−(−sin⁡x)∣\left|x\left(-\cos x\right)-\left(-\sin x\right)\right|  

b)

 ∣x(cos⁡x)−(sin⁡x)∣\left|x\left(\cos x\right)-\left(\sin x\right)\right|  

c)

 ∣x(−cos⁡x)−(−sin⁡x)∣02π = 0\left|x\left(-\cos x\right)-\left(-\sin x\right)\right|_0^{2\pi}\ =\ 0  

d)

 ∣x(−cos⁡x)−(−sin⁡x)∣02π = −2π\left|x\left(-\cos x\right)-\left(-\sin x\right)\right|_0^{2\pi}\ =\ -2\pi  

9.

 ∫02π x cos⁡nx dx =\int_0^{2\pi}\ x\ \cos nx\ dx\ =  

a)

 ∣x(sin⁡x)(−cos⁡x)∣\left|x\left(\sin x\right)\left(-\cos x\right)\right|  

b)

 ∣x(sin⁡nxn)−(−cos⁡nxn2)∣\left|x\left(\frac{\sin nx}{n}\right)-\left(-\frac{\cos nx}{n^2}\right)\right|  

c)

 ∣x(sin⁡nxn)−(−cos⁡nxn2)∣02π  =0\left|x\left(\frac{\sin nx}{n}\right)-\left(-\frac{\cos nx}{n^2}\right)\right|_0^{2\pi}\ \ =0  

d)

 ∣x(sin⁡nxn)−(−cos⁡nxn2)∣02π =2\left|x\left(\frac{\sin nx}{n}\right)-\left(-\frac{\cos nx}{n^2}\right)\right|_0^{2\pi}\ =2  

10.

 ∫02π x cos⁡(nπl )x dx =\int_0^{2\pi}\ x\ \cos\left(\frac{n\pi}{l}\ \right)x\ dx\ =  

a)

 ∣x(sin⁡(nπl )x)(−cos⁡(nπl )x)∣\left|x\left(\sin\left(\frac{n\pi}{l}\ \right)x\right)\left(-\cos\left(\frac{n\pi}{l}\ \right)x\right)\right|  

b)

 ∣x(sin⁡(nπl )x(nπl ))−(−cos⁡(nπl )x(nπl )2)∣\left|x\left(\frac{\sin\left(\frac{n\pi}{l}\ \right)x}{\left(\frac{n\pi}{l}\ \right)}\right)-\left(-\frac{\cos\left(\frac{n\pi}{l}\ \right)x}{\left(\frac{n\pi}{l}\ \right)^2}\right)\right|  

c)

 ∣x(sin⁡(nπl )x(nπl ))−(−cos⁡(nπl )x(nπl )2)∣02π  \left|x\left(\frac{\sin\left(\frac{n\pi}{l}\ \right)x}{\left(\frac{n\pi}{l}\ \right)}\right)-\left(-\frac{\cos\left(\frac{n\pi}{l}\ \right)x}{\left(\frac{n\pi}{l}\ \right)^2}\right)\right|_0^{2\pi}\ \                            

    = 0

d)

 ∣x(sin⁡nxn)−(−cos⁡nxn2)∣02π \left|x\left(\frac{\sin nx}{n}\right)-\left(-\frac{\cos nx}{n^2}\right)\right|_0^{2\pi}\   
 =2