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12 B : STRAIGHT LINES : 09 JAN

Total questions: 10

Worksheet time: 5mins

Name
Class
Date
1.

Distance - of  ,(α, β, γ),\left(\alpha,\ \beta,\ \gamma\right)  
from
y - axis - is

a)

 β\beta  

b)

 β\left|\beta\right|  

c)

 α+β\left|\alpha\right|+\left|\beta\right|  

d)

 α2+γ2\sqrt{\alpha^2+\gamma^2}  

2.

Distance - of - plane
 r .(27i+37i67k)= 1\overrightarrow{r\ }.\left(\frac{2}{7}i+\frac{3}{7}i-\frac{6}{7}k\right)=\ 1  
from - origin - is

a)

1

b)

7

c)

 17\frac{1}{7}  

d)

5

3.

 Direction  ratio  ofDirection\ -\ ratio\ -\ of  
 line , 4x2= y6= 1z3line\ ,\ \frac{4-x}{2}=\ \frac{y}{6}=\ \frac{1-z}{3}  
is

a)

- 2, 6 , - 3

b)

2 , 6 , 3

c)

- 2, 6 , 3

d)

2, 6 , -3

4.

Line - parallel - to

 2i + j + 3k2i\ +\ j\ +\ 3k  
is

a)

 x52= y3 1= z3\frac{x-5}{2}=\ \frac{y-3}{-\ 1}=\ \frac{z}{3}  

b)

 x5 2= y31= z3\frac{x-5}{-\ 2}=\ \frac{y-3}{1}=\ \frac{z}{3}  

c)

 x52= y31= z 3\frac{x-5}{2}=\ \frac{y-3}{1}=\ \frac{z}{-\ 3}  

d)

 x52= y31= z3\frac{x-5}{2}=\ \frac{y-3}{1}=\ \frac{z}{3}  

5.

 Lines , x12= y43p=z34 Lines\ ,\ \frac{x-1}{-2}=\ \frac{y-4}{3p}=\frac{z-3}{4}\   

and
 x24p= y52=z17\frac{x-2}{4p}=\ \frac{y-5}{2}=\frac{z-1}{-7}  
are - perpendicular
then, p =

a)

10

b)

- 10

c)

14 

d)

- 14

6.

Line, through

 (α, β, γ)\left(\alpha,\ \beta,\ \gamma\right)  
and - parallel - to
z - axis, is

a)

 x α0= y β0= z  γ1\frac{x-\ \alpha}{0}=\ \frac{y-\ \beta}{0}=\ \frac{z\ -\ \gamma}{1}  

b)

 x α0= y β1= z  γ0\frac{x-\ \alpha}{0}=\ \frac{y-\ \beta}{1}=\ \frac{z\ -\ \gamma}{0}  

c)

 x α1= y β0= z  γ0\frac{x-\ \alpha}{1}=\ \frac{y-\ \beta}{0}=\ \frac{z\ -\ \gamma}{0}  

d)

 x α1= y β1= z  γ1\frac{x-\ \alpha}{1}=\ \frac{y-\ \beta}{1}=\ \frac{z\ -\ \gamma}{1}  

7.

Foot - of - perpendicular

 drawn  from (2, 4,  1)drawn\ -\ from\ \left(2,\ 4,\ -\ 1\right)  
to - the - line
 x+51= y+34= z69\frac{x+5}{1}=\ \frac{y+3}{4}=\ \frac{z-6}{-9}  
is

a)

( 4, 1, 3)

b)

( 4, -1 , 3)

c)

( - 4 , 1, - 3)

d)

( - 4, - 1, -3 )

8.

line - through

( 0, - 1, - 1 ) &

( 4, 5, 1 )

is

a)

x4 = y+ 16 = z+ 12\frac{x}{4}\ =\ \frac{y+\ 1}{6}\ =\ \frac{z+\ 1}{2}

b)

x4 = y 16 = z+ 12\frac{x}{4}\ =\ \frac{y-\ 1}{6}\ =\ \frac{z+\ 1}{2}

c)

x4 = y+ 16 = z 12\frac{x}{4}\ =\ \frac{y+\ 1}{6}\ =\ \frac{z-\ 1}{2}

d)

x4 = y+ 1 6 = z+ 12\frac{x}{4}\ =\ \frac{y+\ 1}{-\ 6}\ =\ \frac{z+\ 1}{2}

9.

Direction - ratio - of - line

5x - 3 = 15y + 7 = 3 - 10 z

is

a)

6 , 2 , 3

b)

6 , 2, -3

c)

6, - 2 , 3

d)

6 , - 2 , -3

10.

 line, r   a  = λ. b line,\ \overrightarrow{r\ }\ -\ \overrightarrow{a\ }\ =\ \lambda.\ \overrightarrow{b\ }  
is - parallel - to

a)

  a \ \overrightarrow{a\ }  

b)

  b \ \overrightarrow{b\ }  

c)

 λ\lambda  

d)

None of all