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WorksheetsAP Electrochemistry Review
Total questions: 107
Worksheet time: 1hrs 13mins
Which species is oxidized in the following reaction?
2 Ag+(aq) + Cu(s) ⟶ 2 Ag(s) + Cu2+(aq)
Ag
Ag+
Cu
Cu2+
The diagram shows the electrolysis of lead(II) bromide using inert electrodes. Why does the lead(II) bromide need to be melted in order for this reaction to occur?
Bromine atoms in lead(II) bromide are converted to ions when it is melted
Electrons flow through the lead(II) bromide when it is melted
The ions in lead(II) bromide are mobile in the molten state.
There are no ions in solid lead(II) bromide
Reactions in electrolytic cells are
What is an anode?
It is the electrode where oxidation takes place.
It is the electrode where reduction takes place.
It is an aqueous solution containing an electrode.
It is the salt bridge that connects half-cells.
What is a cathode?
It is the electrode where oxidation takes place.
It is the electrode where reduction takes place.
It is an aqueous solution containing an electrode.
It is the salt bridge that connects half-cells.
Which half-reaction correctly represents oxidation?
(Select all that apply)
Ag ⟶ Ag+ + e-
F2 ⟶ 2 F- + 2e-
Au3+ + 3e- ⟶ Au
Fe2+ + e- ⟶ Fe3+
Au ⟶ Au3+ + 3e-
The overall reaction in an electrochemical cell is
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)
As the reaction in this cell takes place, the
mass of the Zn(s) electrode decreases
Zn2+(aq) concentration remains the same
mass of the Cu(s) electrode decreases
Cu2+(aq) concentration remains the same
Which species is oxidized in the following reaction?
2 Ag+(aq) + Cu(s) ⟶ 2 Ag(s) + Cu2+(aq)
Ag
Ag+
Cu
Cu2+
The overall reaction in a galvanic cell is
2 Ag+(aq) + Cu(s) ⟶ 2 Ag(s) + Cu2+(aq)
Which of the following statements are correct as the cell operates?
The mass of the silver electrode increases.
The mass of the copper electrod increases.
The concentration of the silver ions increases.
The concentration of the copper ions increases.
Copper is the anode.
What is the role of the salt bridge in a voltaic cell? (Check all that apply)
To allow the movement of water molecules between the two half cells
To allow the movement of electrons between the half cells
To allow the movement of ions to maintain charge neutrality
What happens to the cell voltage when the salt bridge is removed?
The cell voltage drops to zero.
The cell voltage increases.
The cell voltage becomes negative.
The cell voltage is unchanged.
Reduction happens at the ____.
anode
cathode
salt bridge
voltmeter
Oxidation happens at the ____.
anode
cathode
salt bridge
voltmeter
This electrode in a voltaic cell becomes more massive as the cell operates.
anode
cathode
This electrode becomes less massive as a voltaic cell operates.
anode
cathode
Which of the following statements correctly describes the movement of electrons in a voltaic cell?
Electrons flow through the salt bridge from the cathode to the anode
Electrons flow from left to right as the cell operates.
Electrons flow through the external wire from the anode to cathode
Electrons flow from right to left as the cell operates.
In a voltaic cell, anions flow from the salt bridge into the _____ compartment.
cathode
anode
In a voltaic cell, cations flow from the salt bridge into the ____ compartment.
cathode
anode
Consider the diagram of a voltaic cell represented here. What reaction occurs at the anode?
Ag+ + e- →Ag
Ag → Ag+ + e-
Ni2+ + 2e- → Ni
Ni → Ni2+ + 2e-
A voltaic cell is established based on the redox reaction below.
Mg(s) + Fe2+(aq) → Mg2+(aq) + Fe(s)
Which statements are correct as the cell runs? (Select all that apply)
Magnesium atoms lose electrons.
The mass of the iron electrode decreases.
Electrons flow from the iron electrode to the magnesium electrode.
Anions flow into the iron half-cell.
Anions flow into the magnesium half-cell.
Calculate the Ecell for the following galvanic cell.
using a zinc half cell with 1.0 M Zn(NO3)2 and a silver half cell with 0.1M AgNO3
EAg+ | Ag = +1.08V and EZn2+ | Zn = -0.76V
0.32 V
0.33 V
1.84 V
1.85 V
Calculate the cell potential, Ecell of the electrochemical cell in which reaction
Pb2+ (aq) + Cd (s) → Pb (s) + Cd2+ (aq)
Given that Eocell = +0.277 V,
[Cd2+] = 0.02M, and [Pb2+] = 0.2M.
0.207 V
0.255 V
0.307 V
0.355 V
A voltaic cell was set up using a zinc electrode immersed in a zinc nitrate solution and a nickel electrode immersed in a nickel(II) nitrate solution.
Ni2+ + Zn ⟶ Ni + Zn2+
Which of the following would give a cell voltage that is greater than the standard cell potential?
Increase temperature
Decrease the concentration of Ni2+
Increase the concentration of Ni2+
Increase the concentration of Zn2+
The standard electrode potential of Pb2+/ Pb and Cu2+/ Cu is -0.13V and +0.34 V respectively. Identify the anode and the cathode for the galvanic cell.
Anode: Pb2+, Cathode: Cu
Anode: Pb, Cathode: Cu
Anode: Pb, Cathode: Cu2+
Anode: Pb, Cathode: Cu2+
What is the Nernt Equation for the following reaction?
2Al (s) + 6H+ (aq) → 2Al3+ (aq) + 3H2 (g)
Ecell = E0cell - nFRT ln [H+]6[Al3+]2
Ecell = E0cell - nFRT ln [Al3+]2[H+]6
Ecell = E0cell - nFRT ln [Al3+]2 (PH2)3[H+]6
Ecell = E0cell - nFRT ln [H+]6[Al3+]2 (PH2)3
Given the half-cell equation:
Cu2+ (aq) +2e → Cu (s)
Determine the coulombs required to produced 0.10 mol of Cu
19300 C
4825 C
482500 C
193000 C
What is an anode?
It is the electrode where oxidation takes place.
It is the electrode where reduction takes place.
It is an aqueous solution containing an electrode.
It is the salt bridge that connects half-cells.
What is a cathode?
It is the electrode where oxidation takes place.
It is the electrode where reduction takes place.
It is an aqueous solution containing an electrode.
It is the salt bridge that connects half-cells.
Electrons always flow from
cathode to anode
anode to cathode
Oxidation occurs at the
anode
cathode
Electrons are gained at the
anode
cathode
Given their standard reduction potentials, which of the species is going to be oxidized?
Cu2+/Cu = 0.34V
Zn2+/Zn = -0.76V
Cu
Zn
CuSO4
ZnSO4
What reaction occurs at the anode?
Ag+/Ag = 0.80V
Ni2+/Ni = -0.25V
Ag+ + e- →Ag
Ag → Ag+ + e-
Ni2+ + 2e- → Ni
Ni → Ni2+ + 2e-
A current of 5.0 A flows for 4 hours through 5.0L of a 2.0M aqueous solution of copper (II) sulfate. Calculate the mass of copper deposited at the cathode.
21.69 g
22.69 g
23.69 g
When a certain amount of electric charge flows through an aqueous solution of silver nitrate, 3.24 g of silver is deposited on the cathode.
Calculate the mass of aluminium, Al that will be deposited by the same quantity of charge.
0.27 g
0.29 g
0.40 g
Calculate the time taken to produce 18.0 g of silver from silver nitrate by a current of 0.900 A.
1.58 X 104 s
1.68 X 104 s
1.78 X 104 s
Cell potentials should be (a) for the reaction to be spontaneous.
ΔG should be (a) , for the reaction to be spontaneous.
In a copper plating experiment in which copper metal is deposited from copper (II) ion solution, the system is run for 2.600 hours at a current of 12.00 A. What mass of copper is deposited?
---
NOTE: Use Faraday Constant Value 96, 485 C
(Report your answer with 4 sig figs)
(a)
If a current of 15.0 A is run through electrolysis cell for 2.00 hours, how many moles of electrons have moved? (Answer with "moles of e" as a UNIT, 3 sig figs)
(a)
Consider the reaction
Pb(s) + 2Ag+(aq) ⟶ Pb2+(aq)+ 2Ag(s)
If Eocell = 0.93 V
Calculate ΔG° at 298.15 K for this reaction.
---
Ag+(aq) + e- ⟶ Ag(s) [ E° =0.80 V]
Pb2+(aq) + 2e ⟶ Pb(s) [E° = - 0.13 V]
(Report your answer in kJ with 2 sig figs))
(a)
A voltaic cell is made by connecting a Mn/Mn2+ half cell with a Pb/Pb2+ half-cell. Which statement is correct?
Mn2+ + 2 e- ⟶ Mn Eo = -1.19V
Pb2+ + 2 e- ⟶ Pb Eo = -0.13 V
As an element is oxidized, its oxidation number
decreases as electrons are lost
increases as electrons are lost
decreases as electrons are gained
increases as electrons are gained
A salt bridge is required to measure the cell potential of an electrochemical cell. The function of the salt bridge is to ____.
to provide large surface area for reactions to occur
to allow electrons to flow through from one cell to another cell
to allow ions to pass through and to maintain the ionic balance
to increase the voltage of the electrochemical cell
Consider the cell reaction 2Al(s) + 3Mn2+(aq) → 2Al3+(aq) + 3Mn(s)
Predict whether Ecell is larger or smaller than E°cell
if [Al3+ ] = 2.0 M, [Mn2+ ] = 1.0 M
Ecell is smaller than E°cell
Ecell is larger than E°cell
Ecell is the same as E°cell
Consider the cell reaction Pb(s) + Mn2+(aq) → Pb2+(aq) + Mn(s)
Predict whether Ecell is larger or smaller than E°cell
if [Pb2+] = 0.50 M, and [Mn2+] = 0.50 M
Ecell is smaller than E°cell
Ecell is larger than E°cell
Ecell is the same as E°cell
Given the standard reduction potentials at 25℃ , calculate the standard cell potential, Ecell.
Mg(aq)2++2e−→Mg(s) E°= -2.37V
Al(aq)3++3e−→Al(s) E°= -1.66V
- 0.71V
- 4.03V
+0.71V
+4.03V
Which of the following statements accurately describes the Nernst equation shown below?
At equilibrium, Ecell calculates to a value of 0 and the battery is considered dead because Q becomes Keq and Keq has a value of 0.
Increasing the concentration of the reactants will increase the value of Ecell.
This equation is used to figure out the standard cell potential at any concentration, partial pressure or temperature.
At standard conditions, Ecell = E°cell because all the concentrations are 1 M at an ambient temperature of 273 K.
What is the value of the equilibrium constant, K, if E°cell=+0.71V at 298 K.
Overall eq: 3Mg(s)+2Al(aq)3+→3Mg(aq)2++2Al(s) (F = 96485 C/ mol e ; R= 8.31 J/(mol.K))
1.212×1072
−1.212×1072
1.101×1036
−1.101×1036
An AP chemistry student sets up a galvanic cell using two standard half-cells with half reactions.
Half-cell 1: Cr3+(aq)+e-→Cr2+(aq)
Half-cell 2: Cr(s)→Cr2+(aq)+2e-
Suitable materials for the electrodes of the two half-cells are
Half-cell 1: Platinum; Half-cell 2: Platinum
Half-cell 1: Platinum; Half-cell 2: Chromium
Half-cell 1: Chromium; Half-cell 2: Chromium
Half-cell 1: Chromium; Half-cell 2: Platinum
Calculate the standard cell potential for a voltaic cell using a zinc half-cell and a cadmium half-cell.
Zn2+(aq) + 2e → Zn(s) Eº = – 0.76 V
Cd2+(aq) + 2e → Cd(s) Eº = – 0.40 V
Eocell = -0.36 V
Eocell = -1.16 V
Eocell = +1.16 V
Eocell = +0.36 V
Which of the pairs give the highest value for the standard cell voltage?
Al3+(aq) + 3e → Al(s) Eocell = - 1.66 V
Cu2+(aq) + 2e → Cu(s) Eocell = + 0.34 V
Ni2+(aq) + 2e → Ni(s) Eocell = – 0.25 V
Br2(l) + 2e → 2Br-(aq) Eocell = + 1.07 V
Al and Ni
Cu and Br2
Al and Br2
Cu and Ni
Calculate Ecell for the following reaction and predict whether the following reaction is thermodynamically favorable.
2Ag(s) + Br2(g) ⟶ 2Ag+(aq) + 2Br-(aq)
EºAg+/Ag = + 0.80 V Eº Br2/Br-= + 1.07 V
Eº cell= + 0.27 V (not thermodynamically favorable)
Eº cell= + 0.27 V (thermodynamically favorable)
Eº cell= - 0.37 V (not thermodynamically favorable)
Eº cell= - 0.37 V (thermodynamically favorable)
Consider the cell reaction
2Al(s) + 3Mn2+(aq) → 2Al3+(aq) + 3Mn(s) at non-standard conditions. Calculate the value of Ecell if the initial solutions concentrations were:
[Al3+ ] = 2.0 M [Mn2+ ] = 1.5 M
Al3+/Al E0= -1.66V
Mn2+/Mn E0= -1.19 V
0.699 V
0.50 V
0.469 V
0.741 V
The electrolysis of molten NaCl with carbon electrodes was run for 30. minutes with current of 5.0 A . Find the mass of sodium deposited on the cathode.
2.14 gram
5.25 gram
3.95 gram
4.52 gram
Calculate the mass of copper deposited at cathode during electrolysis using CuSO4 for 20. minutes with a current of 3.0A.
1.79 g
0.79 g
1.18 g
9.71 g
Two copper electrodes were immersed in a copper (II) sulfate solution. If 0.39 g of copper was deposited on the cathode after the cell was operated for 1.5 hours, calculate the average current used (in amperes) for this electrolysis process.
0.22 A
2.0 A
0.15 A
0.3 A
Chromium (III) chloride solution was electrolysed using a current of 10. A for 50. minutes. Calculate the theoretical mass of chromium metal that will deposit on the cathode.
16.2 g
8.08 g
4.38 g
0.0898 g
5.38 g
Will this reaction be thermodynamically favorable?
Fe2+(aq) + Co(s) ⟶ Fe(s) + Co2+ (aq)
GIVEN:
Co2+(aq) / Co(s) Eo = -0.28 V
Fe2+(aq) / Fe(s) Eo= -0.44 V
The reaction is thermodynamically favorable because the value of Eocell is +0.16
The reaction is thermodynamically favorable because the value of Eocell is +0.72
The reaction is not thermodynamically favorable because the value of Eocell is -0.72
The reaction is not thermodynamically favorable because the value of Eocell is -0.16
An aqueous solution of CuSO4 is electrolysed
using a current of 0.150 A for 5 hours. Calculate the mass of copper deposited at cathode.
(Molar mass of Cu = 63.6 g/mol)
0.0140 g
0.8897 g
0.4449 g
1.7794 g
A voltaic cell is constructed using a silver electrode immersed in a 0.10 M solution of silver nitrate and a copper strip immersed in a solution of 1.0M copper(II) nitrate. The mass of the silver electrode is observed to increase.
Which of the following correctly identifies the anode and the cathode in this cell?
Ag is the anode and Cu is the cathode
Cu is the anode and Ag is the cathode
Ag is the anode and Cu2+ is the cathode
Cu is the anode and Ag+ is the cathode
What would be the theoretical cell potential of a galvanic cell constructed with a silver electrode immersed in 1M silver nitrate solution and a nickel electrode immersed in a 1.0M nickel(II) nitrate solution?
Ag+/Ag Eo = 0.80V
Ni2+/Ni Eo = -0.25V
1.05V
-1.05V
0.55V
-0.55V
A galvanic cell was constructed with a zinc half cell with 1.0 M Zn(NO3)2 and a silver half cell with 0.1M AgNO3
EAg+ | Ag = +1.08V and EZn2+ | Zn = -0.76V
Which of the following correctly compares the cell voltage to the standard cell potential and provides a correct explanation?
Ecell < Eocell, because Q > 1
Ecell < Eocell, because Q < 1
Ecell < Eocell, because Q < 1
Ecell > Eocell, because Q < 1
Consider the following reaction in a galvanic cell:
Zn+ Cu+2 →Zn2+ + Cu E∘ =1.10V
What is the Gibb's free energy for the reaction under standard conditions?
106.15kJ/mol
212.3kJ/mol
−212.3kJ/mol
−106.15kJ/mol
Suppose that a reaction with an equilibrium constant equal to 4.5∗106 occurs while at standard state conditions.
Which of the following is true regarding this reaction?
The Gibbs free energy change for this reaction is negative and the reaction is spontaneous
The Gibbs free energy change for this reaction is positive and the reaction is nonspontaneous
The Gibbs free energy change for this reaction is negative and the reaction is nonspontaneous
The Gibbs free energy change for this reaction is positive and the reaction is spontaneous
Given the electrochemical reaction shown, what is the standard free energy change ΔG° if
E˚ = +1.61 V?
Mg / Mg 2+(aq) // Zn2+(aq) / Zn
E˚ = +1.61 V
-311 kJ/mol
+311 kJ/mol
-155 kJ/mol
+155 kJ/mol
none of the above
What is ΔG° for the following balanced reaction, if
E˚ = +2.431 V?
Al(s) + Fe3+(aq) → Al3+(aq) + Fe(s) E˚ = +2.431 V
-704 kJ/mol
+704 kJ/mol
-235 kJ/mol
-469 kJ/mol
none of the above
When a voltaic cell reaches equilibrium, __________
E= 0
E= K
Ecell = 0
Ecell = Q
Ecell = K
ΔG should be (a) for the reaction to be spontaneous.
e
Calculate for the Gibbs free energy, answer in kJ.
(a)
In a copper plating experiment in which copper metal is deposited from copper (II) ion solution, the system is run for 2.600 hours at a current of 12.00 A. What mass of copper is deposited?
---
NOTE: Use Farad Constant Value 96, 485 C
(Answer with "g Cu" as a UNIT, 4 sig figs)
(a)
If a current of 15.0 A is run through electrolysis cell for 2.00 hours, how many moles of electrons have moved? (Answer with "moles of e" as a UNIT, 3 sig figs)
(a)
The diagram shows the electrolysis of molten lead(II) bromide. What process occurs at the cathode in this cell?
2 Br- ⟶ Br2 + 2e-
Br2 + 2 e- ⟶ 2Br-
Pb2+ + 2 e- ⟶ Pb
Pb ⟶ Pb2+ + 2 e-
Consider a voltaic cell, represented by the following net ionic equation
Pb2+ (aq) + Cd (s) → Pb (s) + Cd2+ (aq)
Given that Eocell = +0.277 V,
if the initial [Cd2+] is 0.02M and the initial [Pb2+] = 0.2M, which of the following correctly compares the cell voltage to the standard cell potential and provides a correct explanation?
Ecell< Eocell because Q < 1
Ecell < Eocell because Q < 1
Ecell > Eocell because Q < 1
Ecell < Eocell because Q < 1
Ecell = Eocell because Q = 1
Consider the following reaction in a galvanic cell:
Zn+ Cu+2 →Zn2+ + Cu E∘ =1.10V
Which of the following correctly describes ΔG and K for this reaction?
ΔG > 0 and K > 1
ΔG < 0 and K < 1
ΔG < 0 and K > 1
ΔG > 0 and K < 1
The diagram shows the electrolysis of molten lead(II) bromide.
Which of the following correctly describes ΔG and K for this reaction?
ΔG > 0 and K > 1
ΔG < 0 and K < 1
ΔG < 0 and K > 1
ΔG > 0 and K < 1
Consider a voltaic cell, represented by the following net ionic equation
Pb2+ (aq) + Cd (s) → Pb (s) + Cd2+ (aq)
What happens to the concentration of the ions in each half cell?
(Select all that apply)
[Pb2+] increases in the cathode compartment
[Pb2+] decreases in the cathode compartment
[Cd2+] increases in the anode compartment
[Cd2+] decreases in the anode compartment
[Pb2+] decreases in the anode compartment
Consider a galvanic cell with the following reaction.
Al(s) + Fe3+(aq) → Al3+(aq) + Fe(s)
As the cell operates, the mass of the aluminum electrode decreases. Which of the following correctly explains this observation?
aluminum ions go into solution in the anode compartment
aluminum atoms deposit on the anode
aluminum ions travel through the wire to the cathode
iron(II) ions travel through the wire to the cathode
iron atoms deposit on the cathode
A voltaic cell was set up using a zinc electrode immersed in a zinc nitrate solution and a nickel electrode immersed in a nickel(II) nitrate solution.
Ni2+ + Zn ⟶ Ni + Zn2+
Which of the following would give a cell voltage that is less than the standard cell potential?
Decrease temperature
Decrease the concentration of Ni2+
Increase the concentration of Ni2+
Increase the concentration of Zn2+
What is the standard cell potential of Cell C?
1.05V
2.03V
0.93V
4.45V
In galvanic cells A and B, which of the following takes place in half-cell 3?
Oxidation occurs in both cell A and cell B.
Reduction occurs in both cell A and cell B.
Oxidation occurs in cell A, and reduction occurs in cell B.
Reduction occurs in cell A, and oxidation occurs in cell B.
In galvanic cells B and C, which of the following takes place in half-cell 1?
Oxidation occurs in both cell B and cell C.
Reduction occurs in both cell B and cell C.
Oxidation occurs in cell B and reduction occurs in cell C.
Reduction occurs in cell B and oxidation occurs in cell C.
If the half-cell containing 1.00M Cr(NO3)3 in galvanic cells A and B is replaced with a half-cell containing 0.100M Cr(NO3)3, what will be the effect on the cell voltage of the two galvanic cells?
The voltage will increase in both cells.
The voltage will decrease in both cells.
The voltage will increase in cell A and decrease in cell B.
The voltage will decrease in cell A and increase in cell B.
If the half-cell containing 1.00 M Ni(NO3)2 in galvanic cells 2 and 3 is replaced with a half-cell containing 0.100M Ni(NO3)2, what will be the effect on the cell voltage of the two galvanic cells?
The voltage will increase in both cells.
The voltage will decrease in both cells.
The voltage will decrease in cell B and increase in cell C.
The voltage will increase in cell B and decrease in cell C.
A galvanic cell based on the reaction represented above was constructed from zinc and copper half–cells. The observed voltage was found to be 1.00 volt instead of the standard cell potential, Eo, of 1.10 volts. Which of the following could correctly account for this observation?
Zn(s) + Cu2+(aq) ⟶ Zn2+(aq) + Cu(s)
The copper electrode was more massive than the zinc electrode
The Zn2+ solution was more concentrated than the Cu2+ solution.
The solutions in the half–cells had different volumes.
The salt bridge was not in contact with the solutions in the half-cells
The Zn2+ solution was less concentrated than the Cu2+ solution.
Cu(s) + 2 Ag+ (aq)⟶ Cu2+(aq) + 2 Ag(s)
If the equilibrium constant for the reaction above is 3.7x1015, which of the following correctly describes the standard voltage, Eo, and the standard free energy change, ΔGo, for this reaction?
Eo is positive and ΔGo is negative.
Eo and ΔGo are both negative.
Eo is negative and ΔGo is positive.
Eo and ΔGo are both zero
Eo and ΔGo are both positive
Cu2+(aq) + 2 Ag(s) ⟶ Cu(s) + 2 Ag+ (aq)
If the equilibrium constant for the reaction above is 2.7x10-16, which of the following correctly describes the standard voltage, Eo, and the standard free energy change, ΔGo, for this reaction?
Eo is positive and ΔGo is negative.
Eo and ΔGo are both negative.
Eo is negative and ΔGo is positive.
Eo and ΔGo are both zero
Eo and ΔGo are both positive
Which of the following correctly describes the values of ΔG and Keq as the electrolysis reaction proceeds?
ΔG is positive and Keq is less than 1.
ΔG is positive and Keq is greater than 1.
ΔG is negative and Keq is less than 1.
ΔG is negative and Keq is greater than 1.
Which of the following correctly represents the balanced net ionic equation for the electrolysis reaction?
2 H2O + 2 Cu2+ ⟶ 4 H+ + 2 Cu + O2
4 H+ + 2 Cu + O2(g) ⟶ 2 H2O + 2 Cu2+
2 H2O + Cu2+ ⟶
4 H+ + Cu + O2
2H+ + 2 Cu + O2 ⟶ H2O + 2 Cu2+
Which of the following correctly describes the electrochemical cell?
Copper ions are reduced at the cathode, and oxygen gas is generated at the anode.
Copper metal is reduced at the anode, and oxygen gas is generated at the cathode.
Copper ions are oxidized at the cathode, and water is oxidized at the anode.
Copper metal is oxidized at the anode, and water is reduced at the cathode.
Which of the following changes will result in an increase in the cell voltage?
Adding 50.0 mL of 5.0M Cu(NO3)2 to the right beaker
Adding 50.0 mL of 5.0M Pb(NO3)2 to the left beaker
Increasing the mass of the copper strip
Decreasing the mass of the lead strip
What will be the effect on the cell voltage if a 50.0 mL sample of 5M Pb(NO3)2 is added to the left beaker?
Ecell will increase.
Ecell will decrease but remain above zero.
Ecell will decrease to zero and remain at zero.
No change to Ecell will occur.
What will be the effect on the cell voltage if a 5.0 mL sample of 5M KI is added to the left beaker?
Ecell will increase.
Ecell will decrease but remain above zero.
Ecell will decrease to zero and remain at zero.
No change to Ecell will occur.
What will be the effect on the cell voltage if the solutions in each cell are replaced with 0.50 M solutions?
Ecell will increase.
Ecell will decrease but remain above zero.
Ecell will decrease to zero and remain at zero.
No change to Ecell will occur.
What will be the effect on the cell voltage if the salt bridge is removed?
Ecell will increase.
Ecell will decrease but remain above zero.
Ecell will decrease to zero and remain at zero.
No change to Ecell will occur.
What will be the effect on the cell voltage if the salt bridge is removed?
Ecell will increase.
Ecell will decrease but remain above zero.
Ecell will decrease to zero and remain at zero.
No change to Ecell will occur.
Draw an arrow to show how the K+ ions will move through the salt bridge when the cell is operating.
Which of the following correct describes the movement of ions in the salt bridge?
(Select all that apply)
K+ ions will enter the copper compartment.
K+ ions will enter the lead compartment.
NO3- ions will enter the lead compartment.
NO3- ions will enter the copper compartment.
Sort the options to show how Q affects Ecell
Ecell < Eocell
Ecell > Eocell
Ecell = Eocell
Label the parts of the galvanic cell shown here
movement of electrons
reduction
anode
cathode
salt bridge
oxidation
When Ecell is positive, ΔG is (a) and Keq is (b) . When Ecell is negative, ΔG is (c) and Keq is (d) .
