WorksheetsModule 9 quiz review
Total questions: 14
Worksheet time: 42mins
The variables x and y vary inversely. Use the given values x= -4 and y= 18 to calculate the constant of variation and write the equation. Then find the value of y when x=6
y=x−4.2
y= -.7
y=−72x
y=-432
y=x−72
y=-12
y=−4.2x
y= -25.2
State if the tables show direct variation, inverse variation or neither. State the constant if there is one.
I. Direct, k=1.5
II. Inverse, k= 7.5
III. neither
IV. Inverse, k=3
I. Direct, k=1.5
II. Inverse, k= 7.5
III. Inverse, k=100
IV. Direct, k=3
I. Inverse, k=1.5
II. Direct, k=7.5
III. neither
IV. Inverse, k=3
I. Inverse, k=1.5
II. Direct, k=7.5
III. Inverse, k=100
IV. Inverse, k=3
The maximum load L of a horizontal beam varies inversely as the distance d between its supports. A beam with 16 feet between its supports has a maximum load of 350 pounds. What is the maximum load of the beam if it has 20 feet between its supports?
Find k. Write the equation. Solve.
k=21.875
y=21.875x
y=437.5 pounds
k=21.875
y=x21.875
y=1.36 pounds
k=5600
y=5600x
y=112000 pounds
k=5600
y=x5600
y=280 pounds
Given the reciprocal function: f(x)=x4 , write an equation with asymptotes of x= -5 and y= -3.
f(x)=x−54−3
f(x)=x+54−3
f(x)=x+34−5
f(x)=x−34−5
The graph of g(x)=x+14+2 , is transformed from the function f(x)=x4 Describe the transformations.
Left 1, up 2.
Right 1, up 2
Left 1, down 2
Right 1, down 2
The graph of g(x)=x+14+2 , is transformed from the function f(x)=x4 State domain.
(−∞,∞)
(−∞, −1)U(−1, ∞)
(−∞, −1)U (−1, 2)U (2, ∞)
(−∞,2)U(2, ∞)
The graph of g(x)=x+14+2 , is transformed from the function f(x)=x4
State VA and HA.
State x and y intercepts.
x=-1
y=2
(-3, 0)
(0,6)
x=2
y=-1
(0, -3)
(6,0)
x=4
y=-1
(0, -3)
(0,6)
x=-1
y=2
(0, -3)
(6,0)
Given the rational function below, state the requested information.
y=x2+7x+124x+12
Domain
(−∞,∞)
(−∞, −3)U(−3,∞)
(−∞, −4)U(−4,∞)
(−∞, −4)U (−4, −3)U (−3,∞)
Given the rational function below, state the requested information.
y=x2+7x+124x+12
Hole, VA and HA
Hole: x= -4
VA: x= -3
HA y=o
Hole: x= -3
VA: x= -4
HA none
Hole: x= -3
VA: x= -4
HA y=o
Hole: x= -4
VA: x= -3
HA none
The graph of the rational function f(x)=x+5x3+5x2+x+5 is a parabola with a hole in it. (Hint: Factor first)
What is the equation of the parabola? (Hint: It is quadratic.)
y=x2−5
y=x2+1
y=(x2+1)(x+5)
y=(x+1)(x−1)
The graph of the rational function f(x)=x+5x3+5x2+x+5 is a parabola with a hole in it. (Hint: Factor first)
Where is the location of the hole?
(Hint: Find the x value of the hole. Then plug that x value in to the simplified equation to find the y value of the hole)
(-5, 26)
(-5, -24)
(5, 26)
(5, -24)
Find the vertical and horizontal asymptotes of the function: f(x)=x+23x+8 . State the domain.
Domain: (−∞,−2)U(−2,∞)
VA: x= -2
HA: none
Domain: (−∞,−2)U(−2,∞)
VA: x= 2
HA: y=3
Domain: (−∞,∞)
VA: x=2
HA: y=3
Domain: (−∞,−2)U(−2,∞)
VA: x= -2
HA: y=3
Write the equation of the reciprocal function graphed below. The parent function is f(x)=x2
f(x)=x+22+3
f(x)=x−22−3
f(x)=x+22−3
f(x)=x−22+3
Find the vertical asymptote(s) and/or hole(s) for the graph of f(x)=x2−2x−8x2+7x+10 . Then state the domain.
Domain: (−∞,−2)U(−2,4)U(4,∞) Hole: x=-2
VA: x=4
Domain: (−∞,4)U(4,∞)
Hole: x=4
VA: none
Domain: (−∞,−2)U(−2,∞) Hole: none
VA: x=-2
Domain: (−∞,∞)
Hole: none
VA: none
