Point to remember about coefficient and subscripts while balancing a chemical equation.

Point to remember about coefficient and subscripts while balancing a chemical equation.

When you see a formula like 2Ca(OH)_{2, which of the statements are true}

AgNO3​(aq)+NaCl(aq)→AgCl(s)+NaNO3​(aq) What will you balance first in the equation?

AgNO3​(aq)+NaCl(aq)→AgCl(s)+NaNO3​(aq) Name the metals in the chemical equation?

AgNO3​(aq)+NaCl(aq)→AgCl(s)+NaNO3​(aq) Name the non-metals in the chemical equation?

AgNO3​(aq)+NaCl(aq)→AgCl(s)+NaNO3​(aq) In this equation:

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Name the metals in the chemical equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Number of sodium atoms on the reactant side, in the given equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Number of sodium atoms on the product side, in the given equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. therefore to balance the Sodium we will multiply the sodium on the reactant side with

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Name the non-metals in the chemical equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Number of sulphur atoms on the reactant side, in the given equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Number of sulphur atoms on the product side, in the given equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Is sulphur balanced on both sides of the equation?

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Is sulphur balanced on both sides of the equation?

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Number of oxygen atoms on the reactant side, in the given equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. Number of oxygen atoms on the product side, in the given equation.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. : Wait to balance oxygen last; since placing a coefficient (2) in front of Water (H2O) will not change any other elements.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. : Six oxygens are required to balance the reaction, so this dictates that we use a coefficient in front of oxygen on the product side.

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. : A chemical equation is balanced when the number of atoms of each type on each side of the equation is the same. Which means if you have 4 hydrogens on the left hand side of the equation, you must have ____ hydrogens on the right hand side

NaOH+H2​SO4​→Na2​SO4​+H2​O. Balance the given chemical equation. : There are 4 hydrogens on the left but ____ on the right.

Fe + H₂O → Fe₃O₄ + H_{2, Name the metals in the equation}

Fe + H₂O → Fe₃O₄ + H_{2, What will we start balancing the equation with?}

Fe + H₂O → Fe₃O₄ + H_{2, What is the number of Fe atoms in the reactant side?}

Fe + H₂O → Fe₃O₄ + H_{2, What is the number of Fe atoms in the product side?}

Fe + H₂O → Fe₃O₄ + H_{2, By what coefficient will we multiply Fe on the reactant side}

Fe + H₂O → Fe₃O₄ + H_{2, What is the number of Oxygen atoms in the reactant side?}

Fe + H₂O → Fe₃O₄ + H_{2, What is the number of Oxygen atoms in the product side?}

Fe + H₂O → Fe₃O₄ + H_{2, Since Oxygen is not balanced;} Put ___ as the coefficient of H2O

Fe + H₂O → Fe₃O₄ + H_2, When oxygen is balanced, the atoms of hydrogen on the LHS (reactant) side increase to ____

Fe + H₂O → Fe₃O₄ + H_2, So, balance hydrogen on RHS by adding 4 as coefficient to hydrogen so that there are eight atoms on both the side and hydrogen is balanced.

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. Identify the metals in the above equation.

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. Identify the non-metals in the above equation.

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. How many calcium atoms are on the reactant side (LHS) of the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. How many calcium atoms are on the product side (RHS) of the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. How many sulphur (S) atoms are on the reactant side (LHS) of the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. How many sulphur (S) atoms are on the product side (RHS) of the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. How many Chlorine (Cl) atoms are on the reactant side (LHS) of the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. How many Chlorine (Cl)

atoms are on the product side (RHS) of the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. How many Chlorine (Cl)

atoms are on the product side (RHS) of the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. Is Chlorine balanced in the equation

CaCl₂ (aq) + H₂SO₄ (aq) → CaSO₄ (s) +  HCl (aq)

Calcium Chloride + Sulfuric Acid = Anhydrite + Hydrogen Chloride. What should be done to balance Chlorine (Cl)

H₂O + H₂S₂O₇ →  H₂SO_{4. Balance the equation. Identify the metals in the equation}

H₂O + H₂S₂O₇ →  H₂SO_{4. Balance the equation. Identify the non-metals in the equation}

H₂O + H₂S₂O₇ →  H₂SO_{4. How many sulphur atoms are there on the reactant side (LHS) of the equation}

Balance the following equation.

H2​S2​O7​(I)+H2​O(I)→__ H2​SO4​(I)

Balance equation:

SO₂(g) + H₂S(aq) ===> S(s) + H₂O (l)

Identify the metals in the euqation

Balance equation:

SO₂(g) + H₂S(aq) ===> S(s) + H₂O (l)

Identify the non-metals in the euqation

Balance equation:

SO₂(g) + H₂S(aq) ===> S(s) + H₂O (l)

Step 2: Compare the number of atoms of reactants with the number of atoms of products.

Sulphur atoms on the LHS (Reactant Side)

Balance equation:

SO₂(g) + H₂S(aq) ===> S(s) + H₂O (l)

Step 2: Compare the number of atoms of reactants with the number of atoms of products.

Sulphur atoms on the RHS (Product Side)

Balance equation:

SO₂(g) + H₂S(aq) ===> S(s) + H₂O (l)

Step 3: We find that the equation is not balanced yet. As the number of sulphur atoms is unequal on the two sides.

Now, let us consider sulphur atom. If we multiply ____ in the product (S), we will get the equal number of atoms as in reactants (SO₂ and H₂S)

Balance equation:

SO₂(g) + H₂S(aq) ===> S(s) + H₂O (l)

Step 4: Now, let us consider oxygen atom. If we multiply ____ in the product (in H₂O), we will get the equal number of atoms as in reactants (SO₂)

Balance equation:

SO₂(g) + H₂S(aq) ===> S(s) + H₂O (l)

Step 5: Now, let us consider hydrogen atom. If we multiply ____ in the reactant (in H₂S), we will get the equal number of atoms as in product (H₂O)

Write the balanced equation for

Ag + HCl ==> AgCl + H₂

_{Step 1: Identify the metals in the equation}

Write the balanced equation for

Ag + HCl ==> AgCl + H₂

_{Step 1: Identify the metals in the equation}

Write the balanced equation for

Ag + HCl ==> AgCl + H₂

Step 2: Compare the number of atoms of reactants with the number of atoms of products. Number of Silver (Ag) atoms on the LHS (reactant side)

Write the balanced equation for

Ag + HCl ==> AgCl + H₂

Step 3: Intially, the number of Silver (Ag) atoms on the RHS (product side)

Write the balanced equation for

Ag + HCl ==> AgCl + H₂

Step 4: Since metals are balanced in the equation, we shall consider non-metal Chlorine. If we multiply ____ in the product (in AgCl), we will get the equal number of atoms as in reactant (in HCl)

Write the balanced equation for

Ag + HCl ==> AgCl + H₂

Step 4: Since metals are balanced in the equation, we shall consider non-metal Chlorine. If we multiply ____ in the product (in AgCl), we will get the equal number of atoms as in reactant (in HCl)

Write the balanced equation for

Ag + HCl ==> AgCl + H₂

Step 5: Sinc there are no oxygen atoms; now, we consider hydrogen atom. If we multiply ____ in the reactant (in HCl), we will get the equal number of atoms as in product (H₂)

Write the balanced equation for

Ag + 2 HCl ==> AgCl + H₂

Step 6: Now check whether the equation is balanced or not by comparing the atoms. We find that the equation is not balanced yet. As the number of

chlorine atom is ______ on the two sides.

Write the balanced equation for

Ag + 2HCl ==> ___AgCl + H₂

Step 7: Now, let us consider chlorine atom. If we multiply ______ in the product (in AgCl), we will get the equal number of atoms as in reactant (in HCl)

Step 8: Write the resulting equation:

Ag + 2HCl ==> 2AgCl + H₂

_{Now, the Chlorine on boh reactant side and product side are ____}

Step 9: Write the resulting equation:

Ag + 2HCl ==> 2AgCl + H₂

We find that the equation is not balanced yet. As the number of _____ atom is unequal on the two sides.

Step 10: Write the resulting equation:

Ag + 2HCl ==> 2AgCl + H₂

Now, let us consider silver atom. If we multiply ____ in the reactant (Ag), we will get the equal number of atoms as in product (AgCl)

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 1: Identify the metals in the equation

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 2: How many Calcium atoms are there on the reactant side?

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 3: How many Calcium atoms are there on the product side?

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 4: Is calcium balanced on both sides?

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 4: Is calcium balanced on both sides?

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 5: Identify the non-metals in the equation

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 6: Is Nitrogen balanced on both sides?

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 7: The number of Nitrogen atoms on the reactant side (LHS)

Balance the following chemical equations.

HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 8: The number of Nitrogen atoms on the product side (RHS)

Balance the following chemical equations.

2HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 9: If we multiply Nitrogen atoms in HNO₃ on the reactant side (LHS) by _____ the total number of Nitrogen atoms on both the sides become equal.

Is the following chemical equations.

2HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 10: balanced or unbalanced?

Is the following chemical equations.

2HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 11: We can see that Ca(NO₃)₂ on the product side; it has ___ oxygen atoms, which is the highest number of atoms.

Is the following chemical equations.

2HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 12: We can see that Ca(NO₃)₂ on the product side; it has 6 oxygen atoms, and it also receives 1 more Oxygen atom from H₂O. therefore, the total number of oxygen atoms is ___

Is the following chemical equations.

2HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + H₂O

Step 13: In atoms of Oxygen (O)

Initially: In Reactant 3+2

In Product 6+1 =7

Is the following chemical equations.

2HNO₃ + Ca (OH)₂ → Ca (NO₃)₂ + 2H₂O

Step 14: In atoms of Oxygen (O)

after balancing : In Reactant 2 x 3 + 2 = 8

In Product 6 + 2 x 1 =8