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Punnett Square Quiz

Total questions: 26

Worksheet time: 44mins

Name
Class
Date
1.

Who was the Austrian monk that experimented on pea plants and is called the "father of genetics"? (a)  

Choose from the below words
Gregor Mendel
Charles Darwin
Francis Crick
James Watson
2.

The physical appearance of a trait is known as the-

a)

genotype

b)

phenotype

c)

Homozygous

d)

intelligence

3.
Aa, DD, bB, yy are all examples of
a)
genotypes
b)
phenotypes
4.

Which of the following is/are an example(s) of a phenotype? Select all that apply.

a)

tall

b)

purple

c)

AA

d)

wrinkled

e)

bb

5.

Different versions of a trait (tall or short, white or purple) are called

a)

alleles

b)

traits

c)

versions

d)

genes

6.

If something is heterozygous, it is also _____

a)

purebred

b)

hybrid

c)

dominant

d)

recessive

7.
Which of the following is homozygous recessive?
a)
rr
b)
AA
c)
TT
d)
Ff
8.
G = green, g = yellow
The genotype for a yellow plant is...
a)
GG
b)
Gg
c)
gg
d)
all of the choices result in yellow
9.

If A = red fur and a = white fur, what color fur would Aa be?

a)

red

b)

white

c)

purple

d)

blue

10.
Question Image

Match the following vocabulary words with their definitions

a)

Genetics

1.

The Scientific study of heredity

b)

Heredity

2.

The process in which characteristics are passed down from parents to offspring.

c)

Trait

3.

An organism's characteristics.

d)

Genotype

4.

The specific genetic make up or "code" for an individual.

e)

Phenotype

5.

The total physical appearance for an individual.

11.

Which of the following genotypes is homozygous dominant?

a)

A

b)

Aa

c)

AA

d)

aa

12.

A green pea plant (Gg) is crossed with a yellow pea plant (gg). Describe the genotype of the offspring.

a)

50% heterozygous and 25% homozygous recessive

b)

50% heterozygous and 50% homozygous recessive

c)

100% homozygous recessive

d)

25% heterozygous and 50% homozygous

13.

What are the possible genotypes for this cross?

a)

TT = 25% Tt= 50% tt=25%

b)

all tall

c)

TT= 75% tt = 25%

d)

Tt = 100%

14.

If brown eyes are dominant over blue eyes, what would be the parent genotypes if two heterozygous brown eyed persons were crossed?

a)

BB and bb

b)

BB and Bb

c)

Bb and Bb

d)

bb and Bb

15.

In plants, tall (T) is dominant to short (t). Draw a punnett square and perform the following cross: Tt x Tt

What is the probability of producing a short plant?

a)

0%

b)

25%

c)

50%

d)

75%

16.

What genotype would go in box 2? And is it Homozygous or Heterozygous?

a)

BB Heterozygous

b)

Bb Heterozygous

c)

bb Homozygous

d)

Bb Homozygous

17.
Question Image

Having a Widow's Peak is dominant (W) over not having one (w). If parent A (WW) and parent B (ww) have a child, what is the likelihood that--

a)

The child will have a widow's peak

1.

100%

b)

The child will not have a widow's peak

2.

0%

c)

The genotype of these children

3.

Ww

18.

Which of the following must be the father's genotype?

a)

RR

b)

Rr

c)

rr

19.

How chance the offspring born from this cross will have a homozygous dominant genotype?

a)

25%

b)

50%

c)

75%

d)

100%

20.

What is the mother's genotype?

a)

DD

b)

Dd

c)

dd

21.
If you have a parent who has GgBb as their genotype, what are the possible alleles they could donate to their gametes?
a)
GB, Gb, gB, gb
b)
GB, GB, gb, gb
c)
Gb, Gb, Gb, GB
d)
GG, BB, gg, bb
22.
T4 - What genotype is missing from this Punnett Square?
a)
RrYy
b)
RRYY
c)
rryy
d)
RrYY
23.
Assume dad's gametes are on top, what is his genotype?
a)
AAPP
b)
AaPp
c)
aaPP
d)
Aapp
24.
Using the dihybrid cross and key provided, what is the probability of the offspring being tall and white?
a)
9
b)
2
c)
3
d)
6
25.

Based off this punnett square, what fraction of the offspring will have wrinkled, yellow seeds?

a)

9/16

b)

3/16

c)

1/16

d)

16/16

26.

A white mouse with red eyes is crossed with a black mouse with brown eyes. The white mouse is recessive for both of its traits. The black mouse is dominant for both of its traits.

This cross would be

a)

BBEE x bbee

b)

BBEe x BbEe

c)

BbEE x BbEe

d)

BBee x BBEE