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KINEMATICS

Total questions: 116

Worksheet time: 4hrs 40mins

Name
Class
Date
1.

Slope of position v/s time graph

a)

speed

b)

velocity

c)

acceleration

d)

distance

e)

displacement

2.

Slope of velocity v/s time graph

a)

speed

b)

velocity

c)

acceleration

d)

distance

e)

displacement

3.

Area under velocity v/s time graph

a)

speed

b)

velocity

c)

acceleration

d)

distance

e)

displacement

4.

Select all the correct options

a)

ddt(constant)=0\frac{\text{d}}{\text{d}t}\left(cons\tan t\right)=0

b)

ddt(tn)=n tn1\frac{\text{d}}{\text{d}t}\left(t^n\right)=n\ t^{n-1}

c)

ddt(tn)=tn+1n+1\frac{\text{d}}{\text{d}t}\left(t^n\right)=\frac{t^{n+1}}{n+1}

d)

ddt(a±b)=ddt(a)±ddt(b)\frac{\text{d}}{\text{dt}}\left(a\pm b\right)=\frac{d}{dt}\left(a\right)\pm\frac{d}{dt}\left(b\right)

5.

Velocity=

a)

rate of change of position

b)

rate of change of acceleration

c)

v =dxdtv\ =\frac{\text{d}x}{\text{d}t}

d)

rate of change of momentum

6.

Which of the following graphs cannot possibly represent one dimensional motion of a particle?

a)

a. two positions not possible at the same time

b)

b. two velocities at same time not possible

c)

c. speed can never be negative

d)

d. path length cannot decrease with time for an object in motion

7.

Study the velocity-time graph and calculate the displacement between t =0 to t = 6 sec

a)

8.33 m

b)

150 m

c)

zero

d)

75 m

8.

Study the velocity-time graph and calculate the acceleration between 4 to 5 sec

a)

a = - 8.33 m/s2

b)

a = 8.33 m/s2

c)

a =10nm/s 2

d)

a = zero

9.

Study the velocity-time graph and calculate acceleration between t = 1s to 2s

a)

a = 8.33 m/s

b)

a = 6.67 m/s2

c)

a =10nm/s2

d)

0

10.

Study the velocity-time graph and calculate displacement between t = 1s to 5s

a)

65 m

b)

66.67 m

c)

70 m

d)

56.67 m

11.

An object moves along the grid through points A, B, C, D, E, and F as shown below. The side of each square tiles measures 1 km. Calculate the distance & magnitude of the displacement of the object

a)

distance = 13km & displacement = 5km

b)

distance = 5km & displacement = 13km

c)

distance = 13km & displacement = 6.4km

d)

distance = 14km & displacement = 5km

e)

distance = 6.5km & displacement = 2.5km

12.

Manu travels 250 m towards North but then returns 105 m south to pick his friend. What is the total distance & displacement?

a)

distance = 355m & displacement = 145m South

b)

distance = 355m & displacement = 145m North

c)

distance = 145m & displacement = 355m South

d)

distance = 145m & displacement = 355m North

13.

An object can be taken as a point object

a)

only if it is a point sized object

b)

distance covered by the object is very large compared to size of the object

c)

distance covered by the object is very small compared to size of the object

d)

Any object under any condition can be taken as a point object

14.

Distance is

a)

actual length of the path covered by the object

b)

shortest distance from the initial position to the final position.

c)

a scalar quantity

d)

a vector quantity

e)

for an object in motion distance always increases

15.

Distance is

a)

for an object in motion distance is always positive

b)

for an object in motion distance can be positive, negative or zero

c)

distance can be greater or equal to displacement

d)

distance is always greater than displacement

e)

for an object in motion distance can increase or decrease with time

16.

Displacement is

a)

actual length of the path covered by the object

b)

shortest distance from the initial position to the final position.

c)

a scalar quantity

d)

a vector quantity

e)

for an object in motion displacement always increases

17.

Displacement

a)

is always positive for an object in motion

b)

can be positive, negative or zero for an object in motion

c)

can be less or equal to distance

d)

is always less than distance

e)

can increase or decrease for an object in motion

18.

A man jogging around a circular track of radius 100m completes one - quarter of the track. What are the approximate distance and magnitude of displacement at this point.

a)

distance = 157m & displacement = 141 m

b)

distance = 141m & displacement = 157 m

c)

distance = 200m & displacement = 157 m

d)

distance = 200m & displacement = 200 m

19.

A body covers a semicircular path of 11 meters. What is the displacement of the object?

a)

22 m

b)

11 m

c)

28 m

d)

7 m

20.

An object covers 3m north, 4m east and then 12m vertically up from that point. What is the total displacement of the final position with respect to the starting point.

a)

17m

b)

5m

c)

19m

d)

13m

e)

7 m

21.

Assertion (A) : Distance is always greater than or equal to the displacement. Reason (R) : Displacement is the shortest distance from initial position to final position.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

22.

Assertion (A) : Distance can increase or decrease with time for a moving object. Reason (R) : As the object moves away from the initial position, distance increases and when it returns to the initial position distance decreases.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

23.

Assertion (A) : Displacement can increase or decrease with time for a moving object. Reason (R) : As the object moves away from the initial position, displacement increases and when it returns towards the initial position displacement decreases.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

24.

Assertion (A) : Considering the left to right direction as positive direction, for an object moving from left to right the displacement can be +ve or -ve . Reason (R) : As the object moves left to right on the left side of the origin the displacement is -ve and on the right side of the origin the displacement is +ve.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

25.

Assertion (A) : For any object in motion displacement can be zero , +ve or -ve . Reason (R) : if the final position is same as the initial position displacement is zero, if the final position > initial position displacement is +ve and if the final position < initial position displacement is negative.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

26.

Assertion (A) : For any object in motion displacement is always > distance. Reason (R) : Distance is the actual length of the path between the initial and final position while displacement is the shortest distance from initial position to final position.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

27.

The graph represent

a)

distance covered by an object going away from the starting point and coming back to the same point

b)

distance covered by an object thrown vertically upwards and coming back to the starting point

c)

Graph is not possible as path length can never decrease with time

d)

distance covered by a stone in to air and falling back to ground

28.

Analyse the graphs and identify the correct statements for an object moving along a straight line

a)

(a) is not possible as an object cannot have two positions at the same time.

b)

(b) is not possible as an object cannot have two velocities at the same time.

c)

(c) is not possible as speed can never be negative.

d)

(d) is correct as it indicate an object moving away and comes back and again going away from the starting point.

29.

An object travel along the circumference AB =314m of a semicircular path and stops at the center C of the circular path. (i) distance and (ii) displacement of the journey approximately is ........

a)

distance = 414 m

displacement = 100m

b)

distance = 214 m

displacement = 100m

c)

distance = 414 m

displacement = 100m

d)

distance = 471 m

displacement = 157m

30.

A body covers a semicircular path of 11 meters. What is the displacement of the object?

a)

22 m

b)

11 m

c)

28 m

d)

7 m

31.

An object covers 3m north, 4m east and then 12m vertically up from that point. What is the total displacement of the final position with respect to the starting point.

a)

17m

b)

5m

c)

19m

d)

13m

e)

7 m

32.

Assertion (A) : Distance is always greater than or equal to the displacement. Reason (R) : Displacement is the shortest distance from initial position to final position.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

33.

Assertion (A) : Distance can increase or decrease with time for a moving object. Reason (R) : As the object moves away from the initial position, distance increases and when it returns to the initial position distance decreases.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

34.

Assertion (A) : Displacement can increase or decrease with time for a moving object. Reason (R) : As the object moves away from the initial position, displacement increases and when it returns towards the initial position displacement decreases.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

35.

Assertion (A) : Considering the left to right direction as positive direction, for an object moving from left to right the displacement can be +ve or -ve . Reason (R) : As the object moves left to right on the left side of the origin the displacement is -ve and on the right side of the origin the displacement is +ve.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

36.

Assertion (A) : For any object in motion displacement can be zero , +ve or -ve . Reason (R) : if the final position is same as the initial position displacement is zero, if the final position > initial position displacement is +ve and if the final position < initial position displacement is negative.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

37.

Assertion (A) : For any object in motion displacement is always > distance. Reason (R) : Distance is the actual length of the path between the initial and final position while displacement is the shortest distance from initial position to final position.

a)

Both A & R are true and R is the correct explanation for A

b)

Both A & R are true but R is not the correct explanation for A

c)

A is true but R is false

d)

A is false but R is true

e)

Both A & R are false

38.

The graph represent

a)

distance covered by an object going away from the starting point and coming back to the same point

b)

distance covered by an object thrown vertically upwards and coming back to the starting point

c)

Graph is not possible as path length can never decrease with time

d)

distance covered by a stone in to air and falling back to ground

39.

An object travel along the circumference AB =314m of a semicircular path and stops at the center C of the circular path. (i) distance and (ii) displacement of the journey approximately is ........

a)

distance = 414 m

displacement = 100m

b)

distance = 214 m

displacement = 100m

c)

distance = 414 m

displacement = 100m

d)

distance = 471 m

displacement = 157m

40.

A train travelling with constant velocity, crosses a bridge of 90m long in 30 seconds and after that passes a man in 15 seconds. What is the speed of the train?

a)

6 km/h

b)

21.6 km/h

c)

1.67 km/h

d)

21.6 m/s

e)

3m/s

41.

A 100m long train is moving with a speed of 60 km/h. Calculate the time taken by the train to cross a bridge of 1 km long.

a)

6.6 sec

b)

1.67 sec

c)

16.67 sec

d)

66 sec

42.

A body travels half of the distance at 12 km/h and the rest at 18km/h. calculate the average speed of the body for the entire motion.

a)

15 km/h

b)

12 km/h

c)

18 km/h

d)

14.4 km/h

43.

A vehicle travels half the distance L with speed u and the other half with speed V then its average speed is

a)

(u+v)2\frac{\left(u+v\right)}{2}

b)

2 u vu+v\frac{2\ u\ v}{u+v}

c)

(2u + v )u +v\frac{\left(2u\ +\ v\ \right)}{u\ +v}

d)

L(u+v)u v\frac{L\left(u+v\right)}{u\ v}

44.

At a metro station, a girl walks up a stationary escalator in time a. If she remains stationary on the escalator, then the escalator take her up in time b. The time taken by her to walk up on the moving escalator will be

a)

(a+b)2\frac{\left(a+b\right)}{2}

b)

b - a

c)

a - b

d)

a ba  b\frac{a\ b}{a\ -\ b}

e)

a ba+b \frac{a\ b}{a+b}\

45.

average speed is always 

a)

= total distancetotal time =\ \frac{total\ dis\tan ce}{total\ time}\  

b)

=total displacementtotal time=\frac{total\ displacement}{total\ time}  

c)

= average of the speeds

d)

(u +v )2\frac{\left(u\ +v\ \right)}{2}  

e)

scalar quantity 

46.

average velocity is always 

a)

= total distancetotal time =\ \frac{total\ dis\tan ce}{total\ time}\  

b)

=total displacementtotal time=\frac{total\ displacement}{total\ time}  

c)

= average of the velocities

d)

(u +v )2\frac{\left(u\ +v\ \right)}{2}  

47.

Average speed

a)

is always positive for an object in motion

b)

can be positive, negative or zero for an object in motion

c)

is always greater than magnitude of average velocity.

d)

is greater than or equal to magnitude of average velocity

e)

always increases with time

48.

Average velocity

a)

is always positive for an object in motion

b)

can be positive, negative or zero for an object in motion

c)

is always greater than magnitude of average speed

d)

is less than or equal to speed

e)

always increases with time

49.

Find the (a) distance & (b)displacement of the object from the velocity (Y axis) v/s time ( X axis) graph.

a)

(a) 20 m & (b) zero

b)

(a) zero2 & (b) 0 m

c)

(a) 50 m & (b) zero

d)

(a) 40 m & (b) zero

e)

(a) 20 m & (b) 20 m

50.

Analyse the graphs and select the correct statements based on the graphs

a)

speed of object in figure 1 > speed of the object in figure 2

b)

figure 1 represent motion uniform velocity & figure 2 represent accelerated motion

c)

both the figures represent motion with uniform velocity

d)

both the figures represent motion with acceleration

e)

displacement of the object in figure 1 > displacement of the object in figure 2

51.

Velocity – time graph of a body is given here. Find the displacement in time 2s to 7s

a)

12 m

b)

42 m

c)

45 m

d)

30 m

e)

zero

52.

The graph given here represent ( assume the motion of the car to be along straight line path only)

a)

A car starting from rest, accelerates, then moves with a constant speed and then decelerates & comes to rest

b)

A car starting a velocity of 5m/s, accelerates, then moves with a constant speed and then decelerates & comes to rest

c)

A car moving forward and then coming backward with uniform speed

d)

A car going towards right of the starting point, then turns left and after some time again turns right

53.

Ravi goes to the football ground to play football on his high speed bicycle. The distance- time graph of his journey from his home to the ground is given here. What is speed between 8 to 12 sec

a)

5.75 m/s

b)

15.5 m/s

c)

20 m/s

d)

10.25 m/s

e)

18.75 m/s

54.

Figure ahead represents the displacement-time sketch of motion of two cars A and B. Find the velocity of (a) car A and (b) car B.

a)

(a) 40 km/h & (b) 20 km/h

b)

(a) 20 km/h & (b) 40 km/h

c)

(a) 20 km/h & (b) 10 km/h

d)

(a) 10 km/h & (b) 20 km/h

e)

(a) 20 km/h & (b) 20 km/h

55.

If position of particle changes with time as x =t33t22+t +5x\ =\frac{t^3}{3}-\frac{t^2}{2}+t\ +5 . Select the correct options

a)

v = t2 - t + 1

b)

v = t2 - t

c)

a = 2t

d)

a = 2t - 1

e)

a = 2

56.

If position of particle changes with time as x =t33t22+t +5x\ =\frac{t^3}{3}-\frac{t^2}{2}+t\ +5 . Acceleration is zero at t =....

a)

t = 4 sec

b)

t = 1 sec

c)

t = 0 sec

d)

t = 0.5 sec

e)

t = 2 sec

57.

If position of particle changes with time as x =t33t22+t +5x\ =\frac{t^3}{3}-\frac{t^2}{2}+t\ +5 . Acceleration at t = 4 sec is

a)

a = 5 m/s2

b)

a = 4 m/s2

c)

a = 8 m/s2

d)

a =7 m/s2

e)

a = 2 m/s2

58.

If position of particle changes with time as x =t33t22+t +5x\ =\frac{t^3}{3}-\frac{t^2}{2}+t\ +5 . Find the velocity at t = 2 sec

a)

v =3 m/s

b)

v = 2 m/s

c)

v = 1 m/s

d)

v =4 m/s

59.

A particle starts from the origin at t = 0 and moves with velocity v = 2t - 1, then find position at t = 3 sec

a)

x = 6 m

b)

x = 3 m

c)

x = 4m

d)

x = 5 m

60.

A particle starts from rest at t = 0 and moves with an acceleration a = 2t + 1, then find velocity at t = 3 sec

a)

v = 12 m/s

b)

v = 3 m/s

c)

v = 6m/s

d)

xv= 9 m/s

61.

An engine of the train moving with uniform acceleration passes an electric pole with velocity u and the last compartment with velocity v. Find the velocity of middle point of the train passing the same pole.

a)

(v +u)2\frac{\left(v\ +u\right)}{2}

b)

(v+u)2\sqrt[]{\frac{\left(v+u\right)}{2}}

c)

(v2+u2)2\sqrt[]{\frac{\left(v^2+u^2\right)}{2}}

d)

(v2u2)2\sqrt[]{\frac{\left(v^2-u^2\right)}{2}}

62.

A stone is released from the top of a tower of height 19.6 m. Calculate magnitude of its final velocity just before touching the ground.

a)

4.42 m/s

b)

zero

c)

19.6 m/s

d)

9.8 m/s

63.

A stone is thrown vertically upwards from the top A of a tower. It reaches the ground in t1 seconds. If it is thrown vertically downwards from A with same speed it reaches the ground in t2 seconds. If it is allowed to fall freely from A, then find the time it takes to reach the ground

a)

t = t1 + t2

b)

t =(t1+t2)2t\ =\frac{\left(t_1+t_2\right)}{2}

c)

t = (t12+t22)2t\ =\ \sqrt[]{\frac{\left(t_1^2+t_2^2\right)}{2}}

d)

t =t1 ×t2t\ =\sqrt[]{t_1\ \times t_2}

64.

A ball rolls off the top of a staircase with a horizontal velocity u m/s. If the steps are h meter high and b meter wide, the ball will hit the edge of the nth step, if

a)

n =2hu2gb2n\ =\frac{2hu^2}{gb^2}

b)

n =2hugb2n\ =\frac{2hu}{gb^2}

c)

n =hu2gb2n\ =\frac{hu^2}{gb^2}

d)

n=2hu2gbn=\frac{2hu^2}{gb}

65.

The range R of a projectile is same when its maximum heights are H1 and H2. What is the relation between R and H1 and H2 ?

a)

R =H1H2R\ =\sqrt[]{H_1H_2}

b)

R =4H1H2R\ =\sqrt[]{4H_1H_2}

c)

R =16H1H2R\ =\sqrt[]{16H_1H_2}

d)

R =25H1H2R\ =\sqrt[]{25H_1H_2}

66.

A projectile can have the same range R for two angles of projection. If T1 and T2 be the time of flight in the two cases then

a)

T1T2=2RgT_1T_2=\frac{2R}{g}

b)

T1T2=2Rg\sqrt[]{T_1T_2}=\frac{2R}{g}

c)

T1T2=2RgT_1T_2=\sqrt[]{\frac{2R}{g}}

d)

T1+T2=2RgT_1+T_2=\frac{2R}{g}

67.

If 4 seconds be the time in which a projectile reaches a point P on its trajectory and 5 seconds the time from P to till it reaches the horizontal plane through its point of projection, Find height of P above the horizontal plane. (g =9.8 m/s2 )

a)

9.8 m

b)

98 m

c)

4.9 m

d)

49 m

68.

If A = 5 N and B = 5 N, for what angle, vector sum of A and B to be 5 N

a)

zero

b)

90

c)

120

d)

180

e)

60

69.

What is the net force of three equal vectors 10 N each, acting at a point at the same time equally inclined to each other in the same plane?

a)

0 N

b)

30 N

c)

20 N

d)

10 N

e)

15 N

70.

Analyse the diagram and answer the question

a)

A

b)

B

c)

C

d)

D

e)

NO ANSWER IS CORRECT

71.

If A = B = 10 N , the resultant force is..........

a)

10 N

b)

17.3 N

c)

1.73 N

d)

14.14 N

e)

1.414 N

72.

Analyse the diagram and answer the question

a)

A

b)

B

c)

C

d)

D

e)

ALL OPTIONS ARE CORRECT

73.

A vector E makes an angle θ\theta   with the X axis then

a)

Ex=ECosθE_x=ECos\theta  

b)

Ex=E SinθE_x=E\ Sin\theta  

c)

Ey=E CosθE_y=E\ Cos\theta  

d)

Ey=E SinθE_y=E\ Sin\theta  

74.

If an object is projected vertically upwards

a)

the vertical component of the initial velocity = 0

b)

the horizontal component of the initial velocity = 0

c)

the vertical component of the initial velocity = velocity of projection

d)

the horizontal component of the initial velocity = velocity of projection

e)

Both vertical and horizontal components are nonzero

75.

If an object is projected horizontally

a)

the vertical component of the initial velocity = 0

b)

the horizontal component of the initial velocity = 0

c)

the vertical component of the initial velocity = velocity of projection

d)

the horizontal component of the initial velocity = velocity of projection

e)

Both vertical and horizontal components are nonzero

76.

If an object is projected at an angle to the horizontal

a)

the vertical component of the initial velocity = 0

b)

the horizontal component of the initial velocity = 0

c)

the vertical component of the initial velocity = velocity of projection

d)

the horizontal component of the initial velocity = velocity of projection

e)

Both vertical and horizontal components are nonzero

77.

If an object is projected with an initial velocity u at an angle  θ\theta  to the vertical, then

a)

ux=ucosθu_x=u\cos\theta  

b)

ux=u sinθu_x=u\ \sin\theta  

c)

uy=u sinθu_y=u\ \sin\theta  

d)

uy=u cosθu_y=u\ \cos\theta  

78.

If an object is projected with an initial velocity u at an angle  θ\theta  to the horizontal, then

a)

ux=ucosθu_x=u\cos\theta  

b)

ux=u sinθu_x=u\ \sin\theta  

c)

uy=u sinθu_y=u\ \sin\theta  

d)

uy=u cosθu_y=u\ \cos\theta  

79.

For motion under gravity

a)

vertical component of acceleration = 0

b)

vertical component of acceleration = - g

c)

horizontal component of acceleration = 0

d)

horizontal component of acceleration = - g

e)

horizontal component of velocity = 0

80.

For motion in 2D

a)

The horizontal component of velocity is independent of force and acceleration in vertical direction.

b)

The vertical component of velocity is independent of force and acceleration in horizontal direction.

c)

The horizontal component of velocity is depends of force and acceleration in vertical direction.

d)

The vertical component of velocity is depends of force and acceleration in horizontal direction.

81.

Two small coins (A & B) are released from the same height above the ground level at the same time. A is dropped and B is projected horizontally with an initial velocity, then neglecting the effect of air resistance,

a)

A will reach ground first

b)

B will reach ground first

c)

Both A & B reach ground at the same instant

d)

it depend on the weight of the coin

82.

A man is trying to cross a river by swimming with a constant velocity normal to the river current.

a)

The time taken to cross the river is independent of the speed of the river current

b)

The time taken to cross the river is more if the speed of the river current is more

c)

The distance by which he is washed away depends on the speed of the river current

d)

The distance by which he is washed away is independent of the speed of the river current

83.

ASSERTION(A): For an object projected with an initial velocity and is moving only under the effect of gravity horizontal component of velocity of the object is uniform.

REASON (R): The acceleration in the horizontal direction is zero for an object moving only under the effect of gravity.

a)

A and R are true and R is the correct explanation for A

b)

A and R are true but R is not the correct explanation for A

c)

Both A & R are false

d)

A is true but R is false

e)

A is false but R is true

84.

ASSERTION(A): For an object projected with an initial velocity at an angle to the horizontal, the X component of velocity is always cosine component and the Y component of velocity is always sine component .

REASON (R): The component adjacent to the angle is always the cos component and the opposite component to the angle is always the sine component.

a)

A and R are true and R is the correct explanation for A

b)

A and R are true but R is not the correct explanation for A

c)

Both A & R are false

d)

A is true but R is false

e)

A is false but R is true

85.

If F = 10N, analyse the given diagram and select the correct statement(s)

a)

Fx=5 NF_x=5\ N

b)

Fy=5NF_y=5N

c)

Fx=53NF_x=5\sqrt{3}N

d)

Fy=53NF_y=5\sqrt{3}N

e)

Fx=Fy=10NF_x=F_y=10N

86.

Rain is falling vertically with a speed of 10m/s. If wind blows with a speed of  10310\sqrt{3}  m/s from north to south direction, in what direction a boy standing at the bus stop has to keep the umbrella to protect himself from the rain?

a)

30 degrees from the vertical towards north 

b)

30 degrees from the vertical towards south 

c)

60 degrees from the vertical towards north 

d)

60 degrees from the vertical towards south 

87.

Two tall buildings face each other and are at a distance of 180 m from each other. With what velocity must a ball be thrown horizontally from a window 55 m above the ground in one building, so that it enters a window 10.9 m above the ground in second building?

a)

40 m/s

b)

30 m/s

c)

60 m/s

d)

120 m/s

88.

A man can swim at a speed of 4 km/h in still water. (a) How long does he take to cross a river 2 km wide? If the river flows at a steady rate of 2 km/h and the man makes his strokes normal to the river current. (b) How far down the river he goes when he reach the other bank?

a)

(a) t = 0.5 hr

(b) d = 1.0 m

b)

(a) t = 0.5 hr

(b) d = 1.0 km

c)

(a) t = 0.5 min

(b) d = 1000 m

d)

(a) t = 2 hr

(b) d = 1.0 km

89.

At what angle the forces P + Q and P – Q act such that the resultant is (a) 3P2+Q2\sqrt[]{3P^2+Q^2} (b) 2(P2+Q2)\sqrt[]{2\left(P^2+Q^2\right)}

a)

(a) 600

(b) 900

b)

(a) 900

(b) 600

c)

(a) 600

(b) 300

d)

(a) 1200

(b) 300

90.

A particle is moving towards east with a velocity of 525\sqrt[]{2} m/s. In 10 seconds the velocity changes to 525\sqrt[]{2} m/s towards north. What is the average acceleration in this time?

a)

zero

b)

52ms25\sqrt[]{2}ms^{-2}

c)

5 ms-2

d)

2ms2\sqrt[]{2}ms^{-2}

91.

A stone is thrown horizontally with a speed of √(2𝑔ℎ) from the top of a tower of height h. If it strikes the level ground at a distance ‘a’ from the foot of the tower, find correct relation between a & h

a)

a = h/2

b)

a = h

c)

a=2ha=\sqrt[]{2h}

d)

a = 2 h

92.

A particle is thrown with a velocity of u m/s. It passes A and B as shown in figure at time t1 = 1 s and t2= 3 s. The value of u is (g = 10 m/s^2)

a)

10 m/s

b)

20 m/s

c)

30 m/s

d)

40 m/s

93.

Two paper screens A and B are separated by distance 100 m. A bullet penetrates A and B, at points P and Q respectively, where Q is 10 cm below P. If bullet is travelling horizontally at the time of hitting A, find the velocity of bullet at A.( g = 9.8 SI unit)

a)

500 m/s

b)

700 m/s

c)

1700 ms\frac{1}{700}\ \frac{m}{s}

d)

1500 ms\frac{1}{500}\ \frac{m}{s}

94.

A car is moving at a speed of 40 m/s on a circular track of radius 400 m. This speed is increasing at the rate of 3 m/s2. Find the  magnitude of total acceleration of car.

a)

a = 3 m/s2

b)

a = 4 m/s2

c)

a = 5 m/s2

d)

a = 2 m/s2

95.

From the top of a tower 400 m high a ball is dropped and at the same time another ball is thrown vertically up from the ground at a speed of 100 m/s. Assuming both balls move along same line find (a) when and (b) where the balls meet?

a)

(a) t = 4 sec

(b) h = 320 m from ground

b)

(a) t = 4 sec

(b) h = 80 m from ground

c)

(a) t = 2 sec

(b) h = 320 m from ground

d)

(a) t = 2 sec

(b) h = 80 m from ground

96.

A person is running at his maximum speed of 4m/s to catch a train. When he is at 6m from the door of the train it starts moving with a constant acceleration of 1m/s2. Find the minimum time he takes to catch the train?

a)

6 sec

b)

2 sec

c)

4 sec

d)

3 sec

97.

A body covers 200 m in first 2 seconds and 220 m in the next 4 seconds. What is the velocity of the body at the end of seventh seconds?

a)

v =10 m/s

b)

v =5 m/s

c)

v =15 m/s

d)

v =20 m/s

98.

A particle, starting with an initial speed of u m/s, covers 15 m in the 3rd second and 23 m in the 7th second of its motion. How much distance would it cover in the 11th second of its motion assuming the acceleration to be uniform?

a)

s = 31 m

b)

s = 62 m

c)

s = 16 m

d)

s = 40 m

99.

A ball is thrown vertically up from the ground with a speed of 24.5 m/s. After what time it will be at a height of 29.4 m from the ground.

a)

t = 2 sec only

b)

t = 3 sec only

c)

t = 2 and t = 3 sec

d)

t = 2 sec or t= 3 sec

100.

A body traveling along a straight line traversed one third of the total distance with a velocity of 4m/s. the remaining distance was covered with a velocity of 2 m/s for half the time and with a velocity of 6m/s for the other half time. What is the mean velocity averaged over the whole time of the motion?

a)

2 m/s

b)

3 m/s

c)

4 m/s

d)

5 m/s

101.

Points P, Q and R are in the same vertical line such that PQ = QR. A ball is dropped from P. If t1 and t2 are the time taken by the stone to cover PQ and QR respectively, find the ratio of t1/t2.

a)

1 : 1

b)

121\frac{1}{\sqrt[]{2}-1}

c)

12+1\frac{1}{\sqrt[]{2}+1}

d)

12\frac{1}{\sqrt[]{2}}

102.

From the top of a tower, a stone is projected vertically upwards. When the stone reaches a distance ‘h’ below the tower, its velocity is double of what was at a height ‘h’ above the tower. Find the maximum height attained by the stone from the top of the tower

a)
4h/3
b)
2h
c)
h/2
d)
5h/3
103.

A car starting from rest accelerates at a constant rate ‘a’ for some time and then retards uniformly at the rate of ‘b’ before coming to rest. If the total time taken is t seconds, calculate the (i) maximum velocity (v) and (ii) total distance covered (s)?

a)

v = ab ta+b\frac{ab\ t}{a+b}

b)

s = ab t22(a+b)\frac{ab\ t^2}{2\left(a+b\right)}

c)

v = (a+b )tab\frac{\left(a+b\ \right)t}{ab}

d)

s = (a+b) t22(ab)\frac{\left(a+b\right)\ t^2}{2\left(ab\right)}

104.

Draw the speed (v) – time graph of an object thrown upwards till it reaches the ground

a)

b)

c)

d)

105.

Draw the velocity (v) – time graph of an object thrown upwards till it reaches the ground

a)

b)

c)

d)

106.

Draw the velocity (v) – time graph of an object dropped from height,hit the ground & returns back to the same height

a)

b)

c)

d)

107.

Draw the speed (v) – time graph of an object dropped from height,hit the ground & returns back to the same height

a)

b)

c)

d)

108.

Draw the velocity (v) – time graph of an object dropped from height,hit the ground & returns back to the same height

a)

b)

c)

d)

109.

Displacement of an object at the nth second of its motion is given by

a)

Snth=u+ a2 (2n 1)S_{n^{th}}=u+\ \frac{a}{2\ }\left(2n\ -1\right)

b)

Snth=u+ a2 (2n +1)S_{n^{th}}=u+\ \frac{a}{2\ }\left(2n\ +1\right)

c)

Snth=u a2 (2n 1)S_{n^{th}}=u-\ \frac{a}{2\ }\left(2n\ -1\right)

d)

Snth=ut + 12at2S_{n^{th}}=ut\ +\ \frac{1}{2}at^2

110.

Kinematic equations for motion with uniform acceleration are

a)

v = u + at

b)

s =ut +12at2s\ =ut\ +\frac{1}{2}at^2

c)

v2=u2+2asv^2=u^2+2as

d)

u = v + at

111.

For a projectile

a)

Path is parabola

b)

ax=0a_x=0

c)

ay=ga_y=-g

d)

ax=ga_x=-g

e)

ay=0a_y=0

112.

If an object is projected with an initial velocity u, at an angle θ\theta with the horizontal, range of the projectile is

a)

= (usinθ)22g=\ \frac{\left(u\sin\theta\right)^2}{2g}

b)

=2usinθg=\frac{2u\sin\theta}{g}

c)

=u2sin2θg=\frac{u^2\sin2\theta}{g}

d)

= (usinθ)2g=\ \frac{\left(u\sin\theta\right)^2}{g}

113.

If an object is projected with an initial velocity u, at an angle θ\theta with the horizontal, maximum height of the projectile for this angle is

a)

= (usinθ)22g=\ \frac{\left(u\sin\theta\right)^2}{2g}

b)

=2usinθg=\frac{2u\sin\theta}{g}

c)

=u2sin2θg=\frac{u^2\sin2\theta}{g}

d)

= (usinθ)2g=\ \frac{\left(u\sin\theta\right)^2}{g}

114.

If an object is projected with an initial velocity u, at an angle θ\theta with the horizontal, time of flight of the projectile for this angle is

a)

= (usinθ)22g=\ \frac{\left(u\sin\theta\right)^2}{2g}

b)

=2usinθg=\frac{2u\sin\theta}{g}

c)

=u2sin2θg=\frac{u^2\sin2\theta}{g}

d)

= (usinθ)2g=\ \frac{\left(u\sin\theta\right)^2}{g}

115.

An object is projected with an initial velocity u, at an angle θ\theta with the horizontal, if R,T and H represent the range, time of flight and maximum height for this angle then

a)

4H = R tanθ4H\ =\ R\ \tan\theta

b)

4R = H tanθ4R\ =\ H\ \tan\theta

c)

H=T2g8H=\frac{T^2g}{8}

d)

T =H2g8T\ =\frac{H^2g}{8}

116.

For what angle of projection range of the projectile is equal to the maximum height ?

a)

θ=tan1(4)\theta=\tan^{-1}\left(4\right)

b)

θ=tan1(14)\theta=\tan^{-1}\left(\frac{1}{4}\right)

c)

450

d)

900