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Chemistry 1.25: Unit 6 Wrap-Up

Chemistry 1.25: Unit 6 Wrap-Up

Assessment

Presentation

Science

9th - 12th Grade

Hard

NGSS
HS-PS1-5, MS-PS1-4, HS-PS1-3

+2

Standards-aligned

Created by

Amie Ojerio

Used 1+ times

FREE Resource

10 Slides • 16 Questions

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Multiple Choice

Kinetic Theory states that atoms and molecules are constantly in:

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motion

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phases

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reaction

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trouble

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state

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Multiple Choice

Question image

What phase will CO2CO_2  be in at 15 atm and 40°C-40\degree C  

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Solid

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Liquid

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Gas

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Multiple Choice

The presence of which type of intermolecular forces in a liquid will lead to the highest boiling point?

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Van der Waals

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Dipole-dipole forces

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Hydrogen bonding

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Multiple Choice

Which type of solid has the weakest forces holding it together?

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Molecular

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Metallic

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Network

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Ionic

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Multiple Choice

When a solute such as salt is added to a solvent such as water, the temperature at which the solution freezes becomes:

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Lower

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Higher

3

There is no change

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Multiple Choice

Which of these compares moles of solute to the mass of a solvent?

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Molality

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Molarity

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Multiple Choice

Salt (NaCl) is added to water. What is the freezing point of the solution if the molality is 2.25 mol/kg?

Kf = 1.86

i = 2

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16.74°C-16.74\degree C  

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8.37°C-8.37\degree C  

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0°C0\degree C  

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8.37°C8.37\degree C  

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Multiple Choice

Which is the correct KeqK_{eq}  for this reaction:

2NO(g) + 2H2(g)  N2(g) + 2H2O(g)2NO\left(g\right)\ +\ 2H_2\left(g\right)\ \leftrightarrow\ N_2\left(g\right)\ +\ 2H_2O\left(g\right)  

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Keq = [N2][H2O][NO]2[H2]K_{eq}\ =\ \frac{\left[N_2\right]\left[H_2O\right]}{\left[NO\right]^2\left[H_2\right]}  

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Keq = [N2][H2O]2[NO]2[H2]2K_{eq}\ =\ \frac{\left[N_2\right]\left[H_2O\right]^2}{\left[NO\right]^2\left[H_2\right]^2}  

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Keq = [NO]2[H2][N2]2[H2O]K_{eq}\ =\ \frac{\left[NO\right]^2\left[H_2\right]}{\left[N_2\right]^2\left[H_2O\right]}  

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Multiple Choice

Use the equation and the concentrations given to calculate KeqK_{eq}  :

Keq = [N2][H2O]2[NO]2[H2]2K_{eq}\ =\ \frac{\left[N_2\right]\left[H_2O\right]^2}{\left[NO\right]^2\left[H_2\right]^2}  

[NO] = 2 M\left[NO\right]\ =\ 2\ M  

[H2] = 2 M\left[H_2\right]\ =\ 2\ M  

[N2] = 1.5 M\left[N_2\right]\ =\ 1.5\ M  

[H2O] = 3 M\left[H_2O\right]\ =\ 3\ M  

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0.40

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0.84

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1.12

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1.18

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Multiple Choice

If Keq = 0.84K_{eq}\ =\ 0.84  are there more products or reactants present at equilibrium?

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Products

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Reactants

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Multiple Choice

H2(g) + I2(g)  2HI(g)H_2\left(g\right)\ +\ I_2\left(g\right)\ \leftrightarrow\ 2HI\left(g\right)  

This system is at dynamic equilibrium. What happens if you increase the concentration of HI(g)?

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The equilibrium position will shift to the reactant side.

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The equilibrium position will shift to the product side.

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There will be no change.

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Multiple Choice

CaCO3(s)  CaO(s) + CO2(g)CaCO_3\left(s\right)\ \leftrightarrow\ CaO\left(s\right)\ +\ CO_2\left(g\right)  

This system is at dynamic equilibrium. What happens when you remove some of the CaO from the reaction chamber?

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The equilibrium position will shift to the reactant side.

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The equilibrium position will shift to the product side.

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There will be no change.

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Multiple Choice

What is meant by the rate of reaction?

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How far to completion the reaction goes

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How much energy the reaction requires

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How concentrated the final products are

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How slow or fast a reaction progresses

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Multiple Choice

What does the "hill" represent in an energy diagram?

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The energy of the reactants

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The energy of the products

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The activation energy

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Total energy of the system

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Multiple Choice

What would decrease the rate of the formation of ammonia (NH3)\left(NH_3\right)  ?

N2(g) + 3H2(g)  2NH3 (g) + heatN_2\left(g\right)\ +\ 3H_2\left(g\right)\ \leftrightarrow\ 2NH_3\ \left(g\right)\ +\ heat  

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Increasing the temperature

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Increasing the pressure

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Increasing the concentration of reactants

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Decreasing the temperature

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Multiple Choice

What effect would a catalyst have on the reaction?

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It shifts equilibrium to the left.

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It decreases the activation energy.

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It decreases the reaction rate.

4

It increases the concentration of the reactants.

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