Тригонометриялық теңдеулерді шешу

Тригонометриялық теңдеулерді шешу

10th - 11th Grade

6 Qs

quiz-placeholder

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Тригонометриялық теңдеулерді шешу

Тригонометриялық теңдеулерді шешу

Assessment

Quiz

Mathematics

10th - 11th Grade

Hard

Created by

Saule Alibek

Used 11+ times

FREE Resource

6 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt


2sinx=32\sin x=\sqrt{3}

x=(1)nπ6+πn, nϵZx=\left(-1\right)^n\frac{\pi}{\text{6}}+\pi n,\ n\epsilon Z

x=±π3+2πn, nϵZx=\pm\frac{\pi}{\text{3}}+2\pi n,\ n\epsilon Z

x=π3+πn, nϵZx=\frac{\pi}{\text{3}}+\pi n,\ n\epsilon Z

x=(1)nπ3+πn, nϵZx=\left(-1\right)^n\frac{\pi}{\text{3}}+\pi n,\ n\epsilon Z

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 2sin2x+5sinx+2=02\sin^2x+5\sin x+2=0  

 x=(1)n+1π6+πn, nϵZx=\left(-1\right)^{n+1}\frac{\pi}{6}+\pi n,\ n\epsilon Z  

 x=(1)nπ6+2πn, nϵZx=\left(-1\right)^n\frac{\pi}{6}+2\pi n,\ n\epsilon Z  

 x=(1)n+1π2+πn, nϵZx=\left(-1\right)^{n+1}\frac{\pi}{2}+\pi n,\ n\epsilon Z  

 x=(1)nπ3+πn, nϵZx=\left(-1\right)^n\frac{\pi}{3}+\pi n,\ n\epsilon Z  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 2cosx=12\cos x=-1  

 x=±2π3+2πn, nϵZx=\pm\frac{2\pi}{3}+2\pi n,\ n\epsilon Z  

 x=2π3+2πn, nϵZx=\frac{2\pi}{3}+2\pi n,\ n\epsilon Z  

 x=π3+2πn, nϵZx=\frac{\pi}{3}+2\pi n,\ n\epsilon Z  

 x=±π3+2πn, nϵZx=\pm\frac{\pi}{3}+2\pi n,\ n\epsilon Z  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 sin2x=32sinx\sin2x=\frac{3}{2}\sin x  

 πn, nϵZ;  ±arccos34+πk, kϵZ\pi n,\ n\epsilon Z;\ \ \pm\arccos\frac{3}{4}+\pi k,\ k\epsilon Z  

 2πn, nϵZ;  ±arcsin34+2πk, kϵZ2\pi n,\ n\epsilon Z;\ \ \pm\arcsin\frac{3}{4}+2\pi k,\ k\epsilon Z  

 πn, nϵZ;  ±arccos34+2πk, kϵZ\pi n,\ n\epsilon Z;\ \ \pm\arccos\frac{3}{4}+2\pi k,\ k\epsilon Z  

 πn, nϵZ\pi n,\ n\epsilon Z  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 2+cos2x=2sinx2+\cos^2x=2\sin x  

  x=π2+2πk, kϵZ\ x=\frac{\pi}{2}+2\pi k,\ k\epsilon Z  

  x=π4+2πk, kϵZ\ x=\frac{\pi}{4}+2\pi k,\ k\epsilon Z  

  x=π2+2πk, kϵZ\ x=-\frac{\pi}{2}+2\pi k,\ k\epsilon Z  

  x=2π3+2πk, kϵZ\ x=\frac{2\pi}{3}+2\pi k,\ k\epsilon Z  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 tg(π+x3)1=0tg\left(\pi+\frac{x}{3}\right)-1=0  

 x=π4+πn, nϵZx=\frac{\pi}{4}+\pi n,\ n\epsilon Z  

 x=3π4+3πn, nϵZx=\frac{3\pi}{4}+3\pi n,\ n\epsilon Z  

 x=3π4+πn, nϵZx=\frac{3\pi}{4}+\pi n,\ n\epsilon Z  

 x=π4+πn, nϵZx=-\frac{\pi}{4}+\pi n,\ n\epsilon Z