Big G, Little g, Cavendish

What was Henry Cavendish the most afraid of?

• Other people, especially women

• Failure

• Animals, especially dogs

• Asparagus because of the bitter taste

What did Cavendish's experiment with lead balls measure?

• Universal Gravitational Constant, G, and therefore the mass of earth

• Density of lead

• Gravitational force at the surface of earth

• Radius of earth

Tags

NGSS.HS-PS2-4

How close was Cavendish's measurement of G to accepted values today?

• 1%

• 2%

• 5%

• 10%

Tags

NGSS.HS-PS2-4

What two pieces of information are required to calculate the acceleration at a planet's surface, g?

• Planet mass & radius

• Planet density & diameter

• Planet location relative to sun & mass of sun

• G, universal gravitational constant & mass of person on planet surface

Tags

NGSS.HS-PS2-4

Two spherical objects have masses of 8000 kg and 1500 kg. Their centers are separated by a distance of 1.5 m. Find the gravitational attraction between them

• 5.4 X 10^-4 N

• 1.2 X 10⁷ N

• 3.6 X 10^-4 N

• 5.33 N

Tags

NGSS.HS-PS2-4

A 500 kg asteroid is located 3.4 x10⁷m from the center of Earth. The mass of Earth is 6.0x10²⁴ kg. What is the gravitational force between the asteroid and Earth?

F = GMm/r²

G= 6.67 x 10^-11

• 1.73 x 10² N

• 4.63 x 10⁵ N

• 2.94 x 10³ N

• 6.42 x 10⁴ N

Tags

NGSS.HS-PS2-4

NGSS.HS-ESS1-4

The number 6.67 x 10 ^-11 N* m² / kg² is called the

• Universal speed constant

• centripetal force

• Universal Gravitational constant

• Earth's Gravitational constant

Tags

NGSS.HS-PS2-4

Two masses m1 and m2 are separated by a distance R and gravitaional force between them is F. If the distance R is doubled the force will now be _

• 4F

• 2F

• F/2

• 8F

• F/4

Tags

NGSS.HS-PS2-4

Given the equation, g = GM/R², what is the acceleration due to gravity on Jupiter, radius = 6.98 x 10⁷ m, mass = 1.901 x 10²⁷ kg

• 26.0 m/s²

• 9.81 m/s²

• 1.62 m/s²

• 13 m/s²

Tags

NGSS.HS-PS2-4

Two masses m₁ and m₂ are separated by a distance R and gravitaional force between them is F. If the distance R is reduced to R/2 the force will now be

• 8F

• 2F

• F/4

• F/2

• 4F

Tags

NGSS.HS-PS2-4