Quiz 4. Implicit Differentiation + Slope of the Tangent Line

Quiz 4. Implicit Differentiation + Slope of the Tangent Line

10th Grade - University

13 Qs

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Quiz 4. Implicit Differentiation + Slope of the Tangent Line

Quiz 4. Implicit Differentiation + Slope of the Tangent Line

Assessment

Quiz

Mathematics

10th Grade - University

Easy

Created by

Adeyemi Aderinto

Used 11+ times

FREE Resource

13 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx  if     12x + 4y = 10


 dydx=13\frac{dy}{dx}=-\frac{1}{3}  

 dydx=1x3y\frac{dy}{dx}=-\frac{1x}{3y}  

 dydx=3\frac{dy}{dx}=-3  

 dydx=13\frac{dy}{dx}=\frac{1}{3}  

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if      3x26y3=133x^2-6y^3=13  

 dydx=x3y2\frac{dy}{dx}=\frac{x}{3y^2}  

 dydx=x3y2\frac{dy}{dx}=-\frac{x}{3y^2}  

 dydx=18x6y2\frac{dy}{dx}=\frac{18x}{6y^2}  

 dydx=3xy2\frac{dy}{dx}=-\frac{3x}{y^2}  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Differentiate w.r.t x,

 4x2+12x+6y210y=5-4x^2+12x+6y^2-10y=5  

 dydx=2(2x3)6y5\frac{dy}{dx}=\frac{2\left(2x-3\right)}{6y-5}  

 dydx=2(2x3)6y5\frac{dy}{dx}=\frac{-2\left(2x-3\right)}{6y-5}  

 dydx=(2x3)6y5\frac{dy}{dx}=\frac{\left(2x-3\right)}{6y-5}  

 dydx=8x+1212y10\frac{dy}{dx}=\frac{-8x+12}{12y-10}  

 dydx=8x+126y5\frac{dy}{dx}=\frac{-8x+12}{6y-5}  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if        3x2+6y2+10=5x+7y+1003x^2+6y^2+10=5x+7y+100  

 dydx=6x+512y7\frac{dy}{dx}=\frac{-6x+5}{12y-7}  

 dydx=6x+512y+7\frac{dy}{dx}=\frac{-6x+5}{-12y+7}  

 dydx=6x512y7\frac{dy}{dx}=\frac{6x-5}{12y-7}  

 dydx=3x+56y7\frac{dy}{dx}=\frac{-3x+5}{6y-7}  

 dydx=3x56y7\frac{dy}{dx}=\frac{3x-5}{6y-7}  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

What is dy/dx if

 2x7y4=102x^7y^4=10  

 dydx=7y4x\frac{dy}{dx}=-\frac{7y}{4x}  

 dydx=7x4y\frac{dy}{dx}=-\frac{7x}{4y}  

 dydx=4x7y\frac{dy}{dx}=-\frac{4x}{7y}  

 dydx=14y4x\frac{dy}{dx}=-\frac{14y}{4x}  

 dydx=7y4x\frac{dy}{dx}=\frac{7y}{4x}  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if

 5x3+2x4y2=105x^3+2x^4y^2=10  

 dydx=8x3y215x24x4y\frac{dy}{dx}=\frac{-8x^3y^2-15x^2}{4x^4y}  

 dydx=8x3y2+15x24x4y\frac{dy}{dx}=\frac{8x^3y^2+15x^2}{4x^4y}  

 dydx=16x3y215x24x4y\frac{dy}{dx}=\frac{16x^3y^2-15x^2}{4x^4y}  

 dydx=4x2y8xy2+15\frac{dy}{dx}=-\frac{4x^2y}{8xy^2+15}  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find dy/dx if 8xy = 12

dydx=yx\frac{dy}{dx}=-\frac{y}{x}

dydx=yx\frac{dy}{dx}=\frac{y}{x}

dydx=xy\frac{dy}{dx}=-\frac{x}{y}

dydx=xy\frac{dy}{dx}=\frac{x}{y}

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