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PH 1 Turunan Fungsi Trigonometri 2021-2022

Authored by Eviana Budiarti

Mathematics

12th Grade

Used 10+ times

PH 1 Turunan Fungsi Trigonometri 2021-2022
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10 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Turunan pertama dari y = cos (2x3 - x4) adalah ...

y' = sin(2x3 - x4)

y' = -sin(2x3 - x4)

y' = (6x2 - 4x3) cos(2x3 - x4)

y' = (6x2 - 4x3) sin(2x3 - x4)

y' = -(6x2 - 4x3) sin(2x3 - x4)

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Turunan pertama dari (sin x + cos x)2 adalah ...

-2 sin 2x

2 sin 2x

-2 cos 2x

2 cos 2x

4 cos 2x

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika f(x) = sin2\sin^2 (2x + \frac{\pi}{6} ), nilai dari f'(0) adalah ...

 2\sqrt{2}  

 3\sqrt{3}  

2

2 3\sqrt{3}  

12 3\sqrt{3}  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fungsi f dinyatakan oleh f(x) = sec 4x. Nilai f"( π4\frac{\pi}{4} ) adalah ...

-16

-8

-4

 4

16

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fungsi f dinyatakan oleh f(x) = sin2\sin^2 4x. Hasil f"(x) adalah ...

32 cos 8x

16 cos 8x

8 cos 8x

4 cos 8x

2 cos 8x

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui h(x) =  x2 cot xx^2\ \cot\ x . Nilai dari h'( π4\frac{\pi}{4} ) = ...

 π8(4+π)\frac{\pi}{8}\left(4+\pi\right)  

 π8(4π)\frac{\pi}{8}\left(4-\pi\right)  

 π8(π4)\frac{\pi}{8}\left(\pi-4\right)  

 π4(8π)\frac{\pi}{4}\left(8-\pi\right)  

 π4(8+π)\frac{\pi}{4}\left(8+\pi\right)  

7.

MULTIPLE SELECT QUESTION

3 mins • 1 pt

BENAR atau SALAH penyataan berikut!

Jika f(x) = sinxcosxsinx\frac{\sin x-\cos x}{\sin x} maka nilai f'( 13π\frac{1}{3}\pi ) adalah  13\frac{1}{3} 

BENAR

SALAH

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