Lesson 13 Charles Law

What is the formula Charles' Law?

• V = T
• VT = VT
• T₁ / V_{1 =} T₂ / V₂
• V₁ / T₁ = V₂ / T₂

What is 50 C in Kelvin?

• 223
• 323
• 100
• 50

There are 40 liters of helium in a balloon at a temperature of 100 K. If the temperature of the balloon is increased to 200 K, what will be the new volume of the balloon?

• 80 L

• 45 L

• 54 L

• 45.33 L

If a beach ball has a volume of 261 L at a temperature of 502 K, what will be the new temperature of the balloon if the volume decreases to 176 L?

• 744 K

• 0.0030 K

• 339 K

• 512 K

The pressure remains constant over a sample of neon gas occupying a volume of 255 mL . The volume is now 323mL because the temperature has increased to 369 K. What is the original temperature of the gas?

• 291 K

• 223 K

• 467 K

• 76 K

A sample of argon gas is at a temperature of 20 °C. The temperature is increased to 30°C so that the volume is now 373 mL. What was the original volume?

• 338 mL

• 411 mL

• 254 mL

• 249 mL

The pressure remains constant over a sample of helium gas occupying a volume of 638 mL. The temperature is increased to 471 K and the volume is now 953 mL. What was the original temperature?

• 315 K

• 1291 K

• 704 K

• 133 K

When the temperature of a gas decreases (with pressure and amount held constant), does the volume increase or decrease?

• Unaltered

• Remains constant

• Increase

• Decrease

Tags

NGSS.MS-PS1-4

Charles' Law deals with what quantities?

• pressure/temperature

• pressure/volume

• volume/temperature

• volume/temperature/pressure

If the Kelvin temperature of a gas is doubled, the volume of the gas will increase by ____.

• A factor of 2

• A factor of 1

• A factor of 3

• A factor of 0.5