SAT DIGITAL PRACTICE #28

These questions come from The Princeton Review DIGITAL SAT Premium Prep Book 2024.

The questions all come from the practice test of the 2nd math test (easier version). Remember that after taking test 1, you are directed to either the easier version or the harder version based on how you did on part 1

• I understand

• Don't click here

Answer explanation

This is Algebra

If we solve the 2nd equation we know that y = 15. Plug that in to find 4(15) - 16 So the correct value should be _____

Tags

CCSS.6.EE.A.2C

• 4

• 5

• 7

• 8

Answer explanation

This is an Algebra question. Remember about 35% of the test will be algebra type questions

This is just asking you to put (3) in for x so it is 3^2 - 1

Tags

CCSS.HSF.IF.A.2

• $1,850

• $2,300

• $3,850

• $4,150

Answer explanation

Since x represents how many units are produced, we should replace x with 2,000 in the equation

So 2(2000) + 150

Tags

CCSS.HSF.LE.B.5

• 2

• 4

• 6

• 9

Answer explanation

This is asking us to plug 6 in for x so

(2/3)(6) = 12/3 or 4

Tags

CCSS.HSF.IF.A.2

In the figure above, what is the value of d if line a is parallel to line b?

Answer explanation

This is Geometry. About 15% or 3-4 questions will be geometry questions

These are a linear pair of angles so they should add to equal 180. Therefore d = 180 - 62.

Notice that the fact that the lines are parallel is not needed to solve this problem.

Tags

CCSS.8.G.A.5

Answer explanation

First I need to find C and D.

Putting 0 in for y makes C = 17/3.

Putting 0 in for x makes D = -17/4

So c/d = (17/3) / (-17/4).

This becomes

(17/3)(-4/17) = -4/3

A postal machine precesses mail at a constant rate of 21 pieces of mail per minute. At this rate, how many pieces of mail would the machine process in 7 minutes?

• 3

• 14

• 28

• 147

Answer explanation

1 minute = 21 pieces

2 minutes = 2(21) = 42 pieces

3 minutes = 3(21) = 63 pieces

.

.

.

7 minutes = 7(21) = 147 pieces

Tags

CCSS.3.OA.A.3

Stella had 211 invitations to send for an event. She has already sent 43 invitations and will send them all if she send 24 each day for the next d days. Which of the following equations represents this situation?

Answer explanation

This is an algebra equation

since I've already sent out 43 I can say

(number left to send)+ 43 = 211

That narrows choices to B.

Tags

CCSS.HSA.CED.A.3

Answer explanation

Plug in the values from the table into the equations. Which equation will work all 4 times?

Tags

CCSS.8.F.B.4

CCSS.HSF.LE.A.2