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  5. Jan 14 15 Solving Square Root Equations Hwk

Jan 14-15 Solving Square Root Equations HWK

Authored by Myrtle Dillon Rogers

Mathematics

9th - 12th Grade

CCSS covered

Used 1+ times

Jan 14-15 Solving Square Root Equations HWK
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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Ava solves the equation x−2x=3x - 2\sqrt{x} = 3 and reports two solutions: x=1x = 1 and x=9x = 9 .

Which statement correctly classifies Ava’s solutions?

Only x=9x = 9 is valid; x=1x = 1 is extraneous

Only x=1x = 1 is valid; x=9x = 9 is extraneous

Both x=1x = 1 and x=9x = 9 are valid

Neither x=1x = 1 nor x=9x = 9 is valid

Tags

CCSS.HSA.REI.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Chelsey models the speed yy (mph) of a tsunami and the ocean depth xx (feet) with y=3x−4y = 3\sqrt{x} - 4 . If satellites recorded a speed of 200200 miles per hour, how deep was the ocean?

x=4,624x = 4{,}624 feet

x=2,304x = 2{,}304 feet

x=400x = 400 feet

x=68x = 68 feet

Tags

CCSS.HSA.REI.A.2

3.

MATH RESPONSE QUESTION

2 mins • 1 pt

Solve and check each equation. Find xx if 2x+2−3=2\sqrt{2x+2}-3=2 .

x = ____

11.511.5

Mathematical Equivalence

ON

Tags

CCSS.HSA.REI.A.2

4.

MATH RESPONSE QUESTION

2 mins • 1 pt

Solve and check each equation. Find jj if 15−5j=015 - 5\sqrt{j} = 0 .

j = ____

99

Mathematical Equivalence

ON

Tags

CCSS.HSA.REI.A.2

5.

MULTIPLE SELECT QUESTION

30 sec • 1 pt

Solve and check each equation. Determine all solutions for 23c+1=4c+1\dfrac{2}{3}c + 1 = \sqrt{4c + 1} .

c=0c = 0

c=6c = 6

c=−6c = -6

no solution

Tags

CCSS.HSA.REI.A.2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve the equation below and identify any extraneous solutions. What is the solution set to 12(x+17)=4−5x\dfrac{1}{2}(x + 17) = 4 - 5\sqrt{x} ?

no solution

extraneous solutions,

x = {1, 81}

Solution: x=1x = 1

extraneous solution

x = {81}

Solution: x = 9

extraneous solution

x = {1}

Solution: x=81x=81

extraneous solution

x = {9}

Tags

CCSS.HSA.REI.A.2

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

While solving the 2x+7=x−4\sqrt[]{2x+7}=x-4 , Marlon writes the associated quadratic equation 2x+7=(x−4)22x+7=\left(x-4\right)^2 . He solves this quadratic equation and obtains x = 1, x = 9. Which of Marlon's solutions is an extraneous solution of the original square root equation ?

x = 1 is extraneous

x = 9 is extraneous

x = 1 and x= 9 are extraneous

Tags

CCSS.HSA.REI.A.2

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