Charles's Law and Temperature Conversions

Charles's Law and Temperature Conversions

Assessment

Interactive Video

Physics

9th - 10th Grade

Hard

Created by

Patricia Brown

FREE Resource

The video tutorial explains Charles's Law, which describes the relationship between the volume and temperature of a gas at constant pressure. It provides a step-by-step guide to solving a problem involving a gas sample with known volume changes and unknown initial temperature. The tutorial covers converting temperatures from Celsius to Kelvin, rearranging the Charles's Law formula to solve for the unknown, and calculating the initial temperature in both Kelvin and Celsius.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does Charles's Law describe?

The relationship between pressure and temperature

The relationship between pressure and volume

The relationship between mass and volume

The relationship between volume and temperature

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the sample problem, what is the initial volume of the gas?

3.00 liters

2.00 liters

2.80 liters

2.57 liters

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final temperature of the gas in the sample problem?

0 degrees Celsius

25 degrees Celsius

100 degrees Celsius

273 Kelvin

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you convert a temperature from Celsius to Kelvin?

Divide by 273

Multiply by 273

Add 273

Subtract 273

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for Charles's Law?

V1/P1 = V2/P2

V1/T1 = V2/T2

P1*V1 = P2*V2

P1/T1 = P2/T2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in isolating the unknown temperature in the Charles's Law equation?

Multiply both sides by V2

Divide both sides by T1

Multiply both sides by T1

Add T2 to both sides

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the volume of a gas when the temperature decreases, according to Charles's Law?

The volume doubles

The volume remains constant

The volume decreases

The volume increases

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