Free Printable Reciprocal Trig Functions and Applying Trig Functions

1.

Write all six trig ratios.

a)

$\sin\theta=\frac{24}{25}\ \cos\theta=\frac{7}{25}\ \tan\theta=\frac{24}{7}\$ $\csc\theta=\frac{25}{24}\ \sec\theta=\frac{25}{7}\ \cot\theta=\frac{7}{24}$

b)

$\sin\theta=\frac{7}{25}\ \cos\theta=\frac{24}{25}\ \tan\theta=\frac{7}{24}$ $\csc\theta=\frac{25}{7}\ \sec\theta=\frac{25}{24}\ \cot\theta=\frac{24}{7}$

2.

Find the remaining trig ratios if $\sin\theta=\frac{2}{3}$

a)

$\cos\theta=\frac{5}{7}\ \tan\theta=\frac{2}{5}$ $\csc\theta=\frac{3}{2}\ \sec\theta=\frac{7}{5}\ \cot\theta=\frac{5}{2}$

b)

$\cos\theta=\frac{2\sqrt{5}}{5}\ \tan\theta=\frac{2}{3}$ $\csc\theta=\frac{3}{2}\ \sec\theta=\frac{\sqrt{5}}{2}\ \cot\theta=\frac{3}{2}$

c)

$\cos\theta=\frac{\sqrt{5}}{2}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{2\sqrt{5}}{5}\cot\theta=\frac{5\sqrt{5}}{2}$

d)

$\cos\theta=\frac{\sqrt{5}}{3}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{3\sqrt{5}}{5}\cot\theta=\frac{\sqrt{5}}{2}$

3.

Find the missing side. Round answers to the nearest tenth.

a)

39.4

b)

12.2

c)

4

d)

29.1

4.

Find the missing side. Round answers to the nearest tenth.

a)

2.6

b)

6.7

c)

13.7

d)

5.4

5.

Find the missing angle. Round answers to the nearest whole degree.

a)

$50\degree$

b)

$40\degree$

c)

$1\degree$

d)

$33\degree$

6.

Find the missing angle. Round answers to the nearest whole degree.

a)

$64\degree$

b)

$35\degree$

c)

$51\degree$

d)

$63\degree$

7.

What is the reciprocal function to sin?

a)

sec

b)

cos

c)

csc

d)

cot

8.

What is the reciprocal function of sec?

a)

csc

b)

cos

c)

sin

d)

tan

9.

What is the reciprocal function of tan?

a)

csc

b)

cos

c)

sec

d)

cot

10.

If $\sec\theta=\frac{29}{20}$ , then what is the hypotenuse?

a)

24

b)

21

c)

20

d)

29

Reciprocal Trig Functions and Applying Trig Functions

Total questions: 10

Worksheet time: 37mins

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