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Review Before Predicting Products

Review Before Predicting Products

Assessment

Presentation

Science

10th Grade

Practice Problem

Easy

NGSS
MS-PS1-5, MS-PS1-1

Standards-aligned

Created by

Kate Dunkelgod

Used 3+ times

FREE Resource

8 Slides • 9 Questions

1

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Review Before

Predicting Products

2

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Reviewing Metals and Nonmetals (Unit 1-2)

Check your periodic table. Do you
have the metals and nonmetals
labelled?

3

Categorize

Options (15)

calcium

Mg

Cl

Fluorine

O

C

sulfur

N

Ar

He

Fe
Cu
Zn

silver

Au

Sort the elements into metals and nonmetals

Metal
Nonmetal

4

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Reviewing Ionic vs Covalent (Unit 3)

When a metal bonds with a nonmetal, it’s ionic

A compound that only contains nonmetals is covalent

5

Categorize

Options (14)

NaCl

MgBr2

calcium sulfide

carbon monoxide

CO2

sulfur hexafluoride

CCl4

KOH

LiF

BaCl2

Na2SO4

KF

H2O

NH3

Categorize the compounds as ionic or covalent

Ionic
Covalent

6

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Reviewing Ionic Bonding (Unit 3)

To write the ionic compound’s formula, we have to look up the charges of
the two ions, and then do the “swap and drop” (or your other preferred
method) to figure out the subscripts.

Example:

magnesium chloride

Mg is +2, Cl is -1

Mg+2 Cl-1

swap and drop the 2 and the 1

Mg1Cl2 but we don’t usually write “1,” so it becomes: MgCl2

7

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Reviewing Ionic Bonding (Unit 3)

To write the ionic compound’s formula, we have to look up the charges of
the two ions, and then do the “swap and drop” (or your other preferred
method) to figure out the subscripts.

Example:

calcium oxide

Ca is +2, O is -2

Ca+2 O-2

swap and drop the 2s

Ca2O2 but reduce to lowest whole number = CaO

8

Drag and Drop

Aluminum (Al) and iodine (I) bond ionically because aluminum is a metal that loses electrons to form a ​
charge (Al+3), while iodine is a nonmetal that gains electrons to form a ​
charge (I⁻1). Using the swap and drop method, the charge of aluminum (3) becomes the ​
for iodine, and the charge of iodine (1) becomes the subscript for aluminum, resulting in the formula ​
. This ensures the compound is neutral, with three negatively charged iodide ions balancing the one positively charged aluminum ion.
Drag these tiles and drop them in the correct blank above
+3
-1
subscript
AlI₃
+1
-3
Al3I

9

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Reviewing Diatomics (Unit 3)

There are 7 elements that are naturally diatomics

When these elements are not bonded to another element (by itself in the
equation), they get a subscript of 2.

They are:

H2, N2, O2, F2, Cl2, Br2, I2

The subscript of 2 is only for when they are by themselves, not when they
bond to a different element. If they bond to a different element, you can do
the swap and drop to figure out the correct subscripts (see previous slide)

10

Drag and Drop

The seven diatomic elements—hydrogen (H₂), nitrogen (N₂), ​
(O₂), fluorine (F₂), chlorine (Cl₂), bromine (​
), and iodine (I₂)—exist naturally as molecules made of ​
atoms because they are more stable this way. These elements are all ​
, and they form ​ covalent bonds to share electrons and achieve a full outer energy level. A common way to remember them is the acronym ​
or by noting that they form a "7" shape on the periodic table, plus hydrogen.

Drag these tiles and drop them in the correct blank above
oxygen
Br₂
two
nonmetals
metals
ionic
"BrINClHOF"

11

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Reviewing Types of Reactions (Unit 4)

Synthesis A+B AB (one product)

Decomposition AB A + B (one reactant)

Combustion Hydrocarbon + O2 CO2 + H2O

Single Replacement A + BC AC + B (single element on both sides)

Double Replacement AB + CD AD + CB (all compounds, cations swap)

Our next topic/unit is about predicting the products of these 5 types of
reactions, if given the reactants. We will still be classifying and balancing too!

12

Match

Match the following reactions to the correct type of reaction. Remember, "replacement" and "displacement" can be used interchangeably, so "single displacement" means "single replacement."

Synthesis

Decomposition

Single Displacement

Double Displacement

Combustion

2Na + Cl₂ → 2NaCl

CaCO₃ → CaO + CO₂

Zn + 2HCl → ZnCl₂ + H₂

HCl + NaOH → NaCl + H₂O

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

13

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Reviewing Conservation of Mass/Matter (Unit 4)

Balancing chemical reactions ensures that the number of atoms of each
element is the same on both sides of the equation, following the Law of
Conservation of Mass.

This is done by adding coefficients (numbers in front of compounds)
without changing the chemical formulas (subscripts).

14

Multiple Choice

What is the correct coefficient for O₂ when balancing the following equation?

__ C + O₂ → CO₂

1

1

2

2

3

3

4

4

15

Multiple Choice

What is the missing coefficient for Al in the balanced equation below?

__ Al + 3CuCl₂ → 2AlCl₃ + 3Cu

1

1

2

2

3

3

4

4

16

Multiple Choice

What coefficient should be placed in front of O₂ to balance this combustion reaction?

C₃H₈ + __ O₂ → 3CO₂ + 4H₂O

1

3

2

4

3

5

4

6

17

Multiple Choice

What are the correct coefficients to balance the following equation?

Na₃PO₄ + CaCl₂ → NaCl + Ca₃(PO₄)₂

1

1, 1, 3, 2

2

2, 3, 6, 1

3

3, 2, 6, 1

4

1, 2, 3, 2

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Review Before

Predicting Products

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