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p block

Total questions: 60

Worksheet time: 58mins

Name
Class
Date
1.

Acidity of diprotic acid in aqueous solution increases in the order.

a)

H2Se < H2Te < H2S

b)

H2S < H2Se < H2Te

c)

) H2Te < H2S < H2Se

d)

H2Se < H2S < H2Te

2.

Chlorine reacts with excess of NH3 to form

a)

N2 + NH4C

b)

NCl3 + HCl

c)

NH4Cl

d)

N2 + Hcl

3.

Which of the following reactions is an example of redox reaction?

a)

(a) XeF4 + O2F2 → XeF6 + O2

b)

XeF2 + PF5 → [XeF]+ [PF6]–

c)

XeF6 + H2O → XeOF4 + 2HF

d)

XeF6 + 2H2O → Xeo2F2 + 2HF

4.

Which of the following pairs of ions are isoelectronic and isostructural?

a)

a

b)

b

c)

c

d)

d

5.

Affinity for hydrogen decreases in the group from fluorine to iodine. Which of the halogen acids should have highest bond dissociation enthalpy?

a)

HI

b)

HCL

c)

HBR

d)

HF

6.

H2S is more acidic than H2O because

a)

oxygen is more electronegative than sulphur.

b)

atomic number of sulphur is higher than oxygen.

c)

H — O bond dissociation energy is less also compared to H — S bond.

d)

H — S bond dissociation energy is less as compared to H — O bond.

7.

When chlorine reacts with cold and dilute solution of sodium hydroxide, it forms

a)

Cl– and ClO2–

b)

Cl– and ClO–

c)

Cl– and ClO3–

d)

Cl– and ClO4–

8.

Match the items of Columns I and II and mark the correct option

a)

A (2) B (1) C (3) D (4)

b)

A (4) B (1) C (2) D (3)

c)

A (4) B (3) C (1) D (2)

d)

A (3) B (4) C (1) D (2)

9.

Sulphur trioxide can be obtained by which of the following

a)

a

b)

c

c)

d

d)

b

10.

7. The correct order of acid strength is

a)

HClO4 < HClO3 < HClO2 < HClO

b)

HCIO < HClO2 < HClO3 < HClO4

c)

HClO4 < HClO < HClO2 < HClO3

d)

(d) HClO2 < HClO3 < HClO4 < HClO

11.

Which is the correct order of decreasing bond dissociation enthalpy?

a)

F2 > Cl2 > Br2 > I2

b)

I2 > Br2 > Cl2 > F2

c)

Cl2 > Br2 > F2 > I2

d)

Br2 > I2 > F2 > Cl2

12.

9. Which of the statement is incorrect for XeO4

a)

four p𝜋-d𝜋 bonds are present

b)

four sp3 – p 𝜎 bonds are present

c)

it has a pair of lone pair

d)

It has a square planar shape

13.

What is the basicity of H3P04?

a)

1

b)

2

c)

3

d)

4

14.

complete the following series of reactions

XeF4 + O2F2 --------> ________ + O2

a)

XeF2

b)

XeF4

c)

XeF6

d)

Xe

15.

Br2 + F2 (excess) ------------->

a)

BrF

b)

BrF5

c)

BrF3

d)

Br2F2

16.

Cl2 +H2O -------->

a)

Hcl

b)

Hclo

c)

Hclo + Hcl

d)

Hclo3

17.

Mno2 + Hcl ------------->

a)

Mncl

b)

Mncl2

c)

cl2

d)

H20

18.

PbS + O2 -------->

a)

so3

b)

so2

c)

Pbso4

d)

o2

19.

SO2 + MnO4- + H2O -----> (a)   + SO42- + H+

20.

F2 + H2O --------->

a)

HF2 + o2

b)

2HF + o2

c)

4HF + O2

d)

HF + H2O

21.

NaOH + cl2 ------> NaCl + __________ + H2O

hot and conc

a)

NaOCl

b)

NaClo3

c)

NaoCl2

d)

Naclo4

22.

What is the shape of IF3

a)

square planar

b)

pyramidal

c)

Bent T shape

d)

Trigonal Bipyramidal

23.

What is the shape of ClF3

a)

Trigonal Planar

b)

Square Pyramidal

c)

Tetrahedral

d)

Pentagonal Bipyramidal

24.

What is the shape of XeF6

a)

Linear

b)

Square planar

c)

Distorted octahedral

d)

Pyramidal

25.

When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

a)

Zero to – 1 and zero to +3

b)

Zero to + 1 and zero to –3

c)

Zero to + 1 and zero to –5

d)

Zero to – 1 and zero to +5

26.

Which of the following statements regarding ozone is not correct?

a)

The oxygen-oxygen bond length in ozone is identical with that of molecular oxygen

b)

The ozone is resonance hybrid of two structures

c)

The ozone molecule is angular in shape

d)

Ozone is used as a germicide and disinfectant for the purification of air.

27.

Which of the following reactions of xenon compounds is not feasible

a)

XeO3 + 6HF ® XeF6 + 3H2O

b)

3XeF4 + 6H2O ® 2Xe + XeO3 + 12HF + 1.5O2

c)

2XeF2 + 2H2O ® 2Xe + 4HF + O2

d)

XeF6 + RbF ® Rb [XeF7]

28.

The brown ring test for nitrates depends on

a)

reduction of ferrous sulphate to iron

b)

oxidation of nitric oxide to nitrogen dioxide

c)

the reduction of nitrate to nitric oxide

d)

oxidising action of sulphuric acid

29.

One mole of magnesium nitride on the reaction with an excess of water gives:

a)

one mole of ammonia

b)

one mole of nitric acid

c)

two moles of ammonia

d)

two moles of nitric acid

30.

which one is having peroxo bond?

a)

H2SO3

b)

H2SO4

c)

H2S2O8

d)

H2S2o7

31.

Nitrogen is chemically inert. Why?

a)

Due to presence of double bond require more energy to break

b)

Due to presence of triple bond require more energy to break

c)

Triple bond requires less energy to break

d)

None of the above

32.

Nitrogen cannot exhibit co valancy more than four due to

a)

Presence of vacant d orbitals

b)

Due to large size

c)

Due to absence of vacant d orbitals

d)

Due to inert nature

33.

5.The shape of I F 7

a)

T shape

b)

trigonal bipyramidal

c)

linear

d)

pentagonal bipyramidal

34.

Which of the following is known as "inorganic benzene"?

a)

Phosphazine

b)

Piperazine

c)

Borazine

d)

Pyridine

35.

Bond dissociation enthalpy of E—H (E = element) bonds is given below. Which of the compounds will act as strongest reducing agent?

Compound NH3 PH3 AsH3 SbH3

Δdiss (E—H)/kJ mol–1 389 322 297 255

a)

NH3

b)

PH3

c)

AsH3

d)

SbH3

36.

Strong reducing behaviour of H3PO2 is due to

a)

Low oxidation state of phosphorus

b)

Presence of two –OH groups and one P–H bond

c)

Presence of one –OH group and two P–H bonds

d)

High electron gain enthalpy of phosphorus

37.

Which of the following statements are correct?

a)

S–S bond is present in H2S2O6.

b)

In peroxosulphuric acid (H2SO5) sulphur is in +8 oxidation state.

c)

Sulphur exist in S2 in nature like O2

d)

Change in enthalpy is positive for the preparation of SO3 by catalytic oxidation of SO2.

38.

PH3 exist but PH5 does not exist?

a)

becouse phosphorous have large size

b)

becouse hydrogen have small size and less electronegativity hence can't promote electron 3p to 3d orbital

c)

both are correct

d)

none of these

39.

Match the following

(A) H2SO4 (1) Highest electron gain enthalpy

(B) CCl3NO2 (2) Chalcogen

(C) Cl2 (3) Tear gas

(D) Sulphur (4) Storage batteries

a)

A (4) B (3) C (1) D (2)

b)

A (3) B (4) C (1) D (2)

c)

A (4) B (1) C (2) D (3)

d)

A (2) B (1) C (3) D (4)

40.

Assertion : Both rhombic and monoclinic sulphur exist as S8 but oxygen exists as O2.

Reason : Oxygen forms pπ – pπ multiple bond due to small size and small bond length but pπ – pπ bonding is not possible in sulphur

a)

Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.

b)

Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.

c)

Assertion is correct, but reason is wrong statement.

d)

Assertion is wrong but reason is correct statement.

e)

Both assertion and reason are wrong statement

41.

A brown ring is formed in the ring test for NO3ion. It is due to the formation of

a)

[Fe(H2O)5 (NO)]2+

b)

FeSO4.NO2

c)

[Fe(H2O)4(NO)2]2+

d)

FeSO4.HNO3

42.

Assertion : N2 is less reactive than P4.

Reason : Nitrogen has more electron gain enthalpy than phosphorus

a)

Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.

b)

Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.

c)

Assertion is correct, but reason is wrong statement.

d)

Assertion is wrong but reason is correct statement.

e)

Both assertion and reason are wrong statement

43.

Which of the following options are not in accordance with the property

mentioned against them?

a)

(i) F2 > Cl2 > Br2 > I2 Oxidising power.

b)

(ii) MI < MBr < MCl < MF Ionic character of metal halide.

c)

(iii) F2 > Cl2 > Br2 > I2 Bond dissociation enthalpy.

d)

(iv) HI < HBr < HCl < HF Bond dissociation enthalpy.

44.
What was the chemical that was used by the Germans that made Chlorine more lethal?
a)
Hydrobromic Acid
b)
Hydrochloric Acid 
c)
Diphosphate
d)
Phosgene COCl2
45.
What did Haber synthesize for Nobel Peace Prize?
a)
Chlorine gas
b)
Mustard gas
c)
Synthesizing Ammonia
d)
Dynamite
46.
The bleaching action of SO2 is
a)
pertmanent
b)
temprory
c)
can not say
47.

LiAlH4 + SiCl4

a)

SiH2 +AlCl3 + LiCl

b)

SiH4 +AlCl3 + LiCl

c)

SiH4 +AlCl3 + 2LiCl

d)

SiH2 +AlCl3 + 2LiCl

48.

K2Cr2O7 + H2SO4 + 3H2SO3

a)

K2SO4 + 3CrSO4 + 4H2O

b)

K2SO4 + 2Cr2(SO4)3 + 4H2O

c)

K2SO4 + 2CrSO4 + 4H2O

d)

K2SO4 + Cr2(SO4)3 + 4H2O

49.

Which of the following Halogen Acids is strongest one?

a)

HF

b)

HCl

c)

HBr

d)

HI

50.

The shape of XeF4 is

a)

Tetrahedral

b)

Triangular pyramidal

c)

Square planer

d)

None of these

51.

The molecular shape of SF4 is

a)

square planar

b)

see-saw

c)

tetrahedral

d)

bent 'T' shape

52.

Which compound was the first compound of noble gas?

a)

XePtF6

b)

ArPtF6

c)

NePtF6

d)

none

53.

In OF2 the oxidation state of oxygen is

a)

+2

b)

-2

c)

-1

d)

0

54.

H2S is less acidic than H2Te because

a)

H-Te bond dissociation enthalpy is less than that of H-S

b)

H2S undergoes hydrogen bonding

c)

H2Te undergoes hydrogen bonding

d)

H-Te bond dissociation enthalpy is greater than that of H-S

55.

O3 acts as a powerful oxidising agent because

a)

ozone is thermodynamically unstable

b)

its decomposition into oxygen results in the liberation of heat

c)

it liberates atoms of nascent oxygen

(O3 → O2 + O)

d)

ozone has a characteristic smell

56.

Which of the following statements is NOT true ?

a)

Rhombic sulphur (α-sulphur) is yellow in colour

b)

α-sulphur ransforms into β-sulphur above 369 K

c)

Both rhombic and monoclinic sulphur have S8 molecules.

d)

At 1000 K S2 is the dominant species and is diamagnetic.

57.

SO2 + MnO4- + H2O → ?

a)

SO42- + Mn2+ + H+

b)

SO42- + MnO2 + H+

c)

SO32- + Mn2+ + H+

d)

SO3 + Mn2+ + H+

58.

S-O-O-S bond is present in

a)

H2S2O7

b)

H2S2O8

c)

H2S2O3

d)

H2SO4

59.

Which of the following statements are correct?

a)

All the three N—O bond lengths in HNO3 are equal.

b)

All P—Cl bond lengths in PCl5 molecule in gaseous state are equal.

c)

P4 molecule in white phohsphorus have angular strain therefore white phosphorus is very reactive.

d)

In case of PCl5 two P—Cl bond shorter then three P—Cl bond

60.

Chlorine reacts with excess of ammonia to give

a)

NH4Cl

b)

N2 + HCl

c)

N2+NH4Cl

d)

N2+NCl3