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Worksheets3RD SEM - STRENGTH OF MATERIALS - FINAL 1
Total questions: 110
Worksheet time: 37mins
Name
Class
Date
1.
The capacity of a material to resist penetration, absorbs or a cut is know as
a)
Toughness
b)
Hardnesss
c)
Plasticity
d)
Elasticity
2.
is the property of a material to<br />recover its original shape and size when the applied force deforming
a)
Plasticity
b)
Elasticity
c)
Brittle
d)
Ductile
3.
The unit of load
a)
N
b)
N mm
c)
N/mm
d)
N/mm²
4.
Load / Area
a)
Elongation
b)
Strain
c)
Stress
d)
Torque
5.
Load = 10KN, Area = 100mm², Stress =?
a)
1 N/mm²
b)
1000 N/m²
c)
100 N/mm²
d)
10 N/m²
6.
Stress = 120 N/mm² , Area =12 mm² Find<br />Load
a)
100N
b)
0.1 N
c)
10N
d)
1440 N
7.
Load = 1 KN, Area = 100 mm², Find<br />stress
a)
0.1 N/mm²
b)
100 N/mm²
c)
10 N/mm²
d)
1000 N/mm²
8.
Load = 100 MN, Area = 1 m² . Find stress
a)
1000 N/mm²
b)
100 N/mm²
c)
10 N/mm²
d)
1000 N/mm²
9.
1 x 10³ N =
a)
1 MN
b)
1 KN
c)
1 GN
d)
None of these
10.
When the body is subjected to two equal<br />and opposite pushing force, Then the type of load is
a)
Tensile load
b)
Compressive load
c)
Maximum load
d)
No load
11.
When a body is subjected to two equal and opposite pulls, then the load is
a)
Tensile load
b)
Compressive load
c)
Maximum load
d)
No load
12.
The property of a material to recover its original position on removal of external<br />load is
a)
Plasticity
b)
Malleability
c)
Elasticity
d)
Toughness
13.
Load p = .
a)
IAE/L
b)
PI/AE
c)
AE
d)
PE/AL
14.
The capacity of a material to resist penetration is
a)
Toughness
b)
Hardnesss
c)
Plasticity
d)
Elasticity
15.
Strain =
a)
Load/Area X E
b)
Load xE/Area
c)
Area/Load X E
d)
None of these
16.
Load =
a)
Area/Load
b)
Area/Stress
c)
Stress X Area
d)
Stress/perimetr
17.
when a body is subjected to two equal and opposite pulls, then the type of stress is
a)
Yield stress
b)
copressive stress
c)
Tensile stress
d)
Ultimate stress
18.
Stress =
a)
Area/Load
b)
Load X Area
c)
Load/Area
d)
Area x Load
19.
Original length of a rod is 250 mm, change in<br />length is 0.02 mm then starin=
a)
0.8
b)
0.008
c)
8.0E-4
d)
8.0E-5
20.
Unit of Stress is
a)
N/mm
b)
N mm
c)
N/mm²
d)
N² /mm
21.
Unit of Strain is
a)
mm
b)
No unit
c)
mm²
d)
mm³
22.
Change in length / original length =
a)
Stress
b)
Volimetric Strain
c)
Elastic modulus
d)
strain
23.
Young's Modulus E =
a)
load/Area X Strain
b)
Load x Strain/Area
c)
Area/load x Strain
d)
Strain/Area x<br />Strain
24.
1 GPa =
a)
1 X 10² N/m²
b)
1 X 10² N/m²
c)
1 X 10 N/m²
d)
1 X 10³ N/m²
25.
1 pa =
a)
1 N/mm²
b)
1 N/m²
c)
1000 N/mm²
d)
10 N/m²
26.
1 N / mm²
a)
10 Mpa
b)
10³ Mpa
c)
1 Mpa
d)
100 Mpa
27.
1 MPa is
a)
1 N/m²
b)
1 N/mm²
c)
1 X 105 N/m²
d)
1 X 103 N/m²
28.
Modulus of elasticity of steel is
a)
5 x 10⁵ N/mm²
b)
20 x 10⁵ N/mm²
c)
2 x 10⁵ N/mm²
d)
10 x 10⁵ N/mm²
29.
The modulus of Elasticity is
a)
N/mm²
b)
N/m³
c)
N/mm
d)
Nm²
30.
Young's Modulus is also called as
a)
Bulk Modulus
b)
Modulus of<br />Elasticity
c)
Modulus of<br />Rigidity
d)
None of these
31.
within limit Stress is directly<br />proportional to strain
a)
no limit
b)
plastic
c)
elastic
d)
none of these
32.
Area of base of a square bar is 36 mm² load<br />acting on it is 360 N. stress?
a)
10 N/mm²
b)
1N/m²
c)
1000N/mm²
d)
100N/m²
33.
Elongation =
a)
PA/LE
b)
PL/AE
c)
PE/AL
d)
AE/PL
34.
Elongation of a wire due to self weight is
a)
2 AE/WL2
b)
WL/2AE
c)
WL2/2AE
d)
2AE/WL
35.
Possion's ratio is
a)
lateral strain/longitudina<br />l sttrain
b)
shear stress/shear strain
c)
lateral stress/longitudinal<br />strain
d)
volumetric stress/volumetric<br />strain
36.
The notation for possion's ratio is
a)
b)
c)
d)
none of these
37.
The modulus of elasticity of copper is
a)
20x105 N/mm²
b)
2x105 N/mm²
c)
10x105 N/mm²
d)
1x105N/mm²
38.
The modulus of elasticity is
a)
Nmm²
b)
N/mm²
c)
N/mm
d)
Nmm
39.
Ultimate strength =
a)
minimum load/orignal area of cross<br />section
b)
maximumload/orig nal areaof cross section
c)
minimum load/orignal surfaceof cross<br />section
d)
maximum load/orignal surface of cross<br />section
40.
Microscopic cracks are present In all -------
a)
aluminium
b)
metal
c)
bronze
d)
gold
41.
Shear Stress =
a)
Shear load /<br />Area
b)
Ultimate load /<br />Area
c)
Area / Shear load
d)
Area / Shear load
42.
The unit of shear strain is
a)
N
b)
N/mm2
c)
Radian
d)
None of the<br />above
43.
E = 9 KG / (3K+G) in this equation G is
a)
Young's<br />modulus
b)
Bulk modulus
c)
Modulus of rigidity
d)
Modulus of<br />elasticity
44.
E = 9 KG / (3K+G) in this equation E is
a)
Bulk modulus
b)
Modulus of rigidity
c)
Modulus of<br />elasticity
d)
None of the<br />above
45.
Shear Strain =
a)
Shear<br />Stress/Young's modulus
b)
Shear stress/ Rigidity modulus
c)
shear stress/bulk stress
d)
none of the above
46.
Unit of shear strain is
a)
N/mm²
b)
Nm
c)
Radian
d)
N/m
47.
If the shear load is 15 KN and area of cross section is 78.6mm². Find shear stress
a)
191 N/mm²
b)
0.191 N/mm²
c)
1.91 N/mm²
d)
19.1 N/mm²
48.
If the shear load is 15 KN and area of cross section is 78.6mm² and shear stress=191 N/mm² Find the diameter of the rod
a)
100m
b)
96 N
c)
10 mm
d)
None of the above
49.
If the shear load is 15KN and diameter of the<br />rod 1cm. Find the shearstress
a)
191 N/m²
b)
191 N m²
c)
191 Mpa
d)
191 N-mm²
50.
if the shear load is 15 KN and the shear stress<br />is 190.83 N/mm². find the area
a)
2854 mm²
b)
78.56 N/mm²
c)
78.56 mm²
d)
258.4 m²
51.
Tempreature Stran =
a)
1T/2
b)
T/1
c)
1T/1
d)
1t/4
52.
The unit of shear stress is
a)
N/m
b)
N/m³
c)
N/mm²
d)
None of these
53.
The temperature stress induced due to
a)
Only increase in thr temperature
b)
Only decerature<br />rease in the temperature
c)
Both a & b
d)
Neither a nor b
54.
The change in the length is directly<br />propostional to
a)
Only<br />temperature
b)
Only length
c)
Both a & b
d)
Neither a nor b
55.
The temperature stress is directly propostional<br />to
a)
Only length
b)
Only temperature<br />diffrence
c)
Both a & b
d)
None of the<br />above
56.
The deformation of length due to
a)
Only increase in thr temperature
b)
only decease in temperature
c)
Both a & b
d)
Neither a nor b
57.
Find out the correct formula
a)
l = x t x L
b)
l= x t x G
c)
l= x t x E
d)
l= x t
58.
When the temperature of a body is incresed,<br />the stress induced will be
a)
Tension
b)
Compression
c)
Both a & b
d)
NEither a nor b
59.
The unit of teperature coefficient
a)
Kelvin
b)
No unit
c)
c
d)
/c
60.
Find the change in length, if a = 0.000012/c &<br />L = 500mm
a)
0.006mm
b)
0.06cm
c)
0.00048mm
d)
Data is insufficient
61.
Find the temperature strain if the temperature rise is 70 , = 0.000012 per c
a)
8.4 x 10-³
b)
8.4 x 10- 4
c)
8.4 x 10- 5
d)
8.4 x 10-²
62.
The tempetrature stress if the temperature rise is 90 , = 0.00012 perc and E=1 x 10³ N/mm²
a)
108 N/mm²
b)
10.8 N/mm²
c)
1.08 N/mm²
d)
75 N/mm²
63.
Find the change in length, if the initial<br />temperature is 90 and final temperature is 30<br />, = 0.000012 perc and l =500 mm
a)
0.36 mm
b)
0.006 cm
c)
0.00072 mm
d)
0.036 mm
64.
l = 0.36 mm, a = 0.000012 per °c and L = 500<br />mm Find temperature difference
a)
60 watts
b)
60 volt
c)
60 c
d)
60 joule
65.
Find the correct formula
a)
Temperature stress = x t x L
b)
Temperature stress = x t x G
c)
Temperature stress = x t x E
d)
Temperature stress = x t
66.
Find the temperature stress if t =40 , L =500 mm, = 0.000017 per c and E = 2 x 10³N/mm²
a)
136 N/m²
b)
1.36 Mpa
c)
136 Gpa
d)
136 Mpa
67.
Find the temperature difference if temp. stress<br />= 96 Mpa , L= 500 mm, =0.000012 per c and E = 2 x 10³N/mm²
a)
55c
b)
55 per c
c)
40 c
d)
40 per c
68.
Find the tempetrature diffrence if temo, stress<br />= 107MPa L= 500mm, = 0.000017 per c and E=2 x 10³N/mm²
a)
31.4 c
b)
31.4/ c
c)
31.4 J
d)
31.4 W
69.
Find change in length, if t=40 , = 0.000017/ c ,<br />E =2 x 10³N/mm²
a)
63 N/mm²
b)
136 N/mm²
c)
136 mm
d)
Data is insufficient
70.
is a general term used for a member<br />under copressive load
a)
Post
b)
Strut
c)
Boom
d)
Stanchion
71.
is a member of a truss under<br />compressive load
a)
Stanchion
b)
Boom
c)
Post
d)
Strut
72.
is a principal member subjected to<br />compressive load in a crane
a)
Strut
b)
Post
c)
Stanchion
d)
Boom
73.
is another name for a column
a)
Boom
b)
Strut
c)
Post
d)
Stanchion
74.
The vertical member which is subjected to an<br />axial load is called
a)
Strut
b)
Post
c)
Composite bar
d)
None of these
75.
The load at which the column just buckle is
a)
Ultimate load
b)
Crushing load
c)
Buckling
d)
Yield load
76.
Example for column is
a)
Pendulum
b)
conecting rod
c)
piller
d)
None of these
77.
In End condition of column which of the<br />following is not correct ?
a)
Both the end<br />hinged
b)
One end fixed,<br />other end free
c)
Both the ends<br />fixed
d)
Slides are<br />pressed
78.
The buckling load is 6 KN factor of safety = 4<br />then the safe load is
a)
0.33KN
b)
24KN
c)
1.5KN
d)
0.66KN
79.
The buckling load on both the ends fixed is<br /> times the buckling load on both the ends hinged
a)
2
b)
c)
d)
4
80.
The buckling load for long column is that<br />of short column
a)
Less
b)
more
c)
equal
d)
None of these
81.
The buckling load for long column is that<br />of long column
a)
Less
b)
More
c)
equal
d)
None of these
82.
Factor of safety =
a)
Critical load /<br />safe load
b)
Safe load / Critical<br />load
c)
Critical load x<br />Safe load
d)
None of these
83.
unit of buckling load
a)
Nm
b)
Newton
c)
Watt
d)
mm
84.
The other name of buckling load is
a)
Crushing load
b)
Shear load
c)
Crippling load
d)
Ultimate load
85.
According to Euler's theory of column, which of the following is wrong
a)
The cross- sectional of the column is<br />uniform
b)
The column is perfectly straight
c)
The length of the column is very Small
d)
The column fails only buckling
86.
According to Euler's theory of column, which of the following is wrong
a)
The cross- sectional of the column is not<br />uniform
b)
The column is not straight
c)
The length of the column is very large
d)
The column fails only by buckling
87.
According to Euler's theory of column, which of the following is wrong
a)
The cross- sectional of the column is<br />uniform
b)
The column is not straight
c)
The length of the column is very large
d)
The column fails only by buckling
88.
According to Euler's theory of column , which of the following is correct
a)
The column is initially staright
b)
The material of column is homogeneous and<br />isotropic
c)
Both A & B
d)
None of these
89.
According to Euler's theory of column, which of the following is correct
a)
The self weight of the column is negligible
b)
The cross section is not uniform
c)
The length of the column is small
d)
All the above
90.
According to Euler's theory of column, which of the following is wrong
a)
The cross- sectional of the column is<br />uniform
b)
The column is perfectly straight
c)
The length of the column is very large
d)
The column fails only by crushing
91.
considering the end condition of column when both ends are hinged
a)
Effective length L = l
b)
Effective length L<br />= 2l
c)
Effective length L<br />= /
d)
Effective length L<br />= I / A
92.
Considering the end condition of column when<br />both ends are fixed
a)
Effective length<br />L = l
b)
Effective length L<br />= 2l
c)
Effective length L<br />= 1/2
d)
Effective length L<br />= 1/2
93.
Considering the end condition of column, when one end fixed and end other end hinged
a)
Effective length L = l
b)
Effective length L<br />= 2l
c)
Effective length L<br />= 1/2
d)
Effective length L<br />= 1/2
94.
Example for Strut is
a)
Pendulum
b)
conecting rod
c)
piller
d)
None of these
95.
Slenderness ratio =
a)
Effective length/ least radius of gyration
b)
Poisson's ratio
c)
Modular Ratio
d)
None of these
96.
A strut in which ends are hinged, the length of the strut is 1800mm. Find the effective length
a)
900 mm
b)
1350 mm
c)
675.8 mm
d)
1800 mm
97.
A strut in which both ends are hingrd the length of the strut is 525mm find the effective<br />length
a)
600 mm
b)
900 mm
c)
525 mm
d)
1150 mm
98.
Permissible stress =
a)
Ultimate stress x factor of safety
b)
Ultimate stress / Factor of safety
c)
Factor of safety / ultimate stress
d)
None of these
99.
If k is the radius of gyretion and a is the area<br />moement of inertia is
a)
KL/A
b)
A/K²
c)
AK²
d)
A K
100.
The buckling load P =
a)
² EI/1²
b)
² E/I1²
c)
² I/E1²
d)
² E/1²
101.
least radius of gyration =
a)
Effective length<br />/slenderness ratio
b)
slenderness ratio<br />/effective length
c)
slenderness ratio x effective length
d)
None of these
102.
Efective length =
a)
Least radius of grydation / slenderness<br />ratio
b)
slenderness ratio / Least radius of gyration
c)
slenderness ratio x least radius of gyration
d)
None of these
103.
A strut in which one end is fixed and other end is free the length of two of strut is 1200mm find<br />the effective length
a)
1200mm
b)
2400mm
c)
600mm
d)
1800mm
104.
a strut iin which one end is fixed and other end<br />is hinged the length of the strut is 1200mm find the effective length
a)
2400mm
b)
600mm
c)
968.5mm
d)
848.5mm
105.
A strut in which both ends are hinged effective length of the strut is 848.5 mm Find the length
a)
1200mm
b)
2400mm
c)
600mm
d)
848.5mm
106.
The strut in which one end fixed other end is hinged the effective length is 600mm Find the<br />length
a)
848.5mm
b)
950.8mm
c)
1200mm
d)
600mm
107.
Buckling load P = ² EI /L² whereE young's<br />modulus L is effective length I=?
a)
Section Modulus
b)
centroid
c)
Centre of gravity
d)
Moment of Inertia
108.
P=²EI/L² where E is the youngs modulus, L is<br />the effective length I is the moment of inertia. Then P=?
a)
Crushing load
b)
Shear load
c)
Crippling load
d)
Ultimate load
109.
Buckling load P = ²EI /L² where E young's<br />modulus I is the moment of inertia L=?
a)
Length
b)
Effective length
c)
Total length
d)
None of these
110.
Considering the end condition of column when one end fixed and other end hinged then the<br />buckling force is
a)
²EI/1²
b)
p²EI/41²
c)
p²EI/41²
d)
2p²EI/1²
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