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Intro Chemical Bonding Part 2

Intro Chemical Bonding Part 2

Assessment

Presentation

•

Science

•

12th Grade

•

Hard

•
NGSS
HS-ESS2-4, HS-ESS3-1, HS-PS1-1

+16

Standards-aligned

Created by

Stacy King

Used 4+ times

FREE Resource

13 Slides • 7 Questions

1

Review Questions

2

Multiple Choice

Why do all bonds form?

1

To fill up the outer shell and become more stable.

2

To look cool.

3

To become less stable.

4

So they don't have to be alone.

3

Multiple Choice

If Nitrogen bonded with Oxygen, would it form a covalent bond or an ionic bond?

1

covalent

2

ionic

4

Multiple Choice

When an atom completely gives up its valence electrons to another atom, they form a bond that is considered to be

1

purely ionic.

2

polar-covalent.

3

nonpolar-covalent.

5

Multiple Choice

You can estimate the degree to which a bond between two atoms is

1

distance between the atoms' nuclei.

2

difference in the atoms' electronegativities.

3

atoms' atomic radii.

4

number of atoms in the compound.

6

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7

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3.0 - 3.0 = 0.0
Nonpolar

3.0 - 2.1 = 0.9
Polar

3.0 - 0.9 = 2.1
Ionic

Examples:

• Cl2

• HCl

• NaCl

8

media

Polar Covalent: an uneven sharing of
electron—resulting in an asymmetrical electron
density.

9

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Non-Polar Covalent: an even sharing of
electron—resulting in an symmetrical electron density.

10

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Ionic Bonding: a complete transfer of
electron—resulting in oppositely charged ions.

e-

Cl

11

media

Use electronegativity values to classify
bonding between:

Oxygen (O) and Oxygen (O)
Cesium (Cs) and Fluorine (F)
Chlorine (Cl) and Phosphorus (P)

Practice

12

Multiple Choice

Oxygen and Oxygen

1

Nonpolar Covalent Bond

2

Polar Covalent Bond

3

Ionic

13

Multiple Choice

Cesium and Fluorine

1

Nonpolar Covalent Bond

2

Polar Covalent Bond

3

Ionic

14

Multiple Choice

Chlorine and Phosphate

1

Nonpolar Covalent Bond

2

Polar Covalent Bond

3

Ionic

15

media

Bonding END

Bond type More negative atom

Cs and F

4.0 – 0.8 = 3.2

ionic

fluorine

Cl and P

3.0 – 2.2 = 0.9

polar-covalent

chlorine

O and O

3.5 – 3.5 = 0.0

nonpolar-covalent

NA

Practice Solution

16

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Wrapping it Up!

Nonpolar Covalent Bond

✔ electrons are shared equally

✔ symmetrical electron density

✔ usually identical atoms

17

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Polar Covalent Bond

✔ electrons are shared unequally

✔ asymmetrical electron density

✔ results in partial charges

Wrapping it Up!

18

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Wrapping it Up!

Ionic Bond

✔ electrons are transferred

✔ ions are formed

✔ electrostatic attraction between

cations and anions

Ionic Bond

19

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Ionic Bond

20

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Ionic – transfer of electrons

(Metal + Non-metal)

Did you notice this?

Covalent – sharing of electrons

(Non-metal + Non-metal) (Non-metals + Metalloids

Did you notice this?

Non-polar

Polar

pattern-tertiary
Review Questions

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