Charles' Law

A tank (not rigid) contains 2.4 L of helium gas at 25℃. What will be the volume of the tank after heating it and its content to 41℃ temperature at constant pressure? 

_______________ a. This is an application of

(Boyle’s Law, Charles’ Law).

A tank (not rigid) contains 2.4 L of helium gas at 25℃. What will be the volume of the tank after heating it and its content to 41℃ temperature at constant pressure The unknown quantity in the problem is the

(volume, temperature, pressure) of the gas. 

A tank (not rigid) contains 2.4 L of helium gas at 25℃. What will be the volume of the tank after heating it and its content to 41℃ temperature at constant pressure

The formula needed to solve the problem is

( 𝑃1𝑉1 = 𝑃2𝑉2,

𝑉1T1 = 𝑉2𝑇2 ).

A tank (not rigid) contains 2.4 L of helium gas at 25℃. What will be the volume of the tank after heating it and its content to 41℃ temperature at constant pressure

The temperature of the gas (decreases, increases).

A tank (not rigid) contains 2.4 L of helium gas at 25℃. What will be the volume of the tank after heating it and its content to 41℃ temperature at constant pressure

The volume of the gas (decreases, increases). 

Charles’ Law explains that at constant pressure, volume and temperature 

• A.are inversely proportional from each other

• B.are directly proportional to each other 

• C. have the same value

• d. has no relation at all 

A gas measures 350 mL at a temperature of 30℃. What temperature is needed to make the volume reduced to 150 mL?

• a. 707 K

• b. 13 K

• c. 130 K

• d. 70 K

From the equation = V₁ / T₁ = V₂ / T₂ , which of the following is the formula for final volume? 

• A. 𝑉2 = 𝑉1𝑇2/𝑇1

• B. 𝑉2 = 𝑇1𝑉1/𝑇2

• C. 𝑉2 = 𝑉1𝑇1/𝑇2 

• D. 𝑉2 = 𝑉1𝑇1/𝑇2

 At constant temperature, doubling the volume of a gas makes its pressure...

• A.doubled

• B.halved

•  C.remains the same 

• D. unpredictable

What will happen to the volume of a gas when its temperature decreases?

• A.decreases

• B.increases

• C. remains the same

• D. unpredictable