WorksheetsPRINCIPLES OF INHERITANCE AND VARIATION
Total questions: 100
Worksheet time: 50mins
Among the seven pairs of contrasting traits in pea plant as studied by mendel, the number of traits related to flower, pod and seed respectively were
2,2,2
2,2,1
1,2,2
1,2,2
Some of the dominant traits studied by Mendel were
round seed shape, green seed colour and axial flower position
terminal flower position, green pod colour and inflated pod shape
violet flower colour , green pod colour and round seed shape
wrinkled seed shape, yellow pod colour and axial flower position
Which of the following characters was not chosen by Mendel?
Pod shape
Pod colour
Position of pod
Position of flower
____________ code for a pair of contrasting traits of same gene.
Dominant genes
Alleles
Linked genes
Recessive genes
A recessive allele is expressed in
heterozygous condition only
homozygous condition only
F3 generation
both homozygous and heterozygous conditions.
The characters which appear in the first filial generation are called
recessive characters
dominant characters
holandric characters
lethal characters
In a monohybrid cross between two heterozygous individuals, percentage of pure homozygous individuals obtained in F1 generation will be
25%
50%
75%
100%
On crossing two heterozygous tall plants (Tt), a total of 500 plants were obtained in F1 generation. What will be the respective number of tall and dwarf plants obtained in F1 generation?
375,125
250,250
475, 25
350,150
In mice, black coat colour (allele B) is dominant to brown coat colour (allele b). The offspring of a cross between a black mouse (BB) and a brown mouse (bb) were allowed to interbreed. What percentage of the progeny would have black coats?
25%
50%
75%
100%
In fruit flies, long wing is dominant to vestigial wing. When heterozygous long – winged flies were crossed with vestigial- winged flies, 192 offsprings were produced. If an exact Mendelian ratio had been obtained, then the number of each phenotype would have been
Long –winged 64 Vestigial – winged 128
Long –winged 96 Vestigial – winged 96
Long –winged 128 Vestigial – winged 64
Long –winged 192 Vestigial – winged 0
What is the probability of production of dwarf offsprings in a cross between two heterozygous tall pea plants?
Zero
50%
25%
100%
A tobacco plant heterozygous for a recessive character is self-pollinated and 1200 seeds are subsequently germinated. How many seedlings would have the parental genotype?
120
600
300
750
To determine the genotype of tall plant of F2 generation, Mendel crossed this plant with a dwarf plant. This cross represents a
test cross
monohybrid cross
dihybrid cross
reciprocal cross
Read the given statements and select the correct option.
Statement 1: Test cross is used to determine an unknown genotype within one breeding generation.
Statement 2: Test cross is a cross between F1 hybrid and dominant parent.
Both statements 1 and 2 are correct.
Statement 1 is correct but statement 2 is incorrect.
Statement 1 is incorrect but statement 2 is correct.
Both statements 1 and 2 are incorrect.
Read the given Statements and select the correct option.
Statement 1: The law of segregation is one of the most important contributions to the biology
Statement 2: Law of segregation introduced the concept of heredity factors as discrete physical entities which do not become blended.
Both statements 1 and 2 are correct.
Statement 1 is correct but statement 2 is incorrect.
Statement 1 is incorrect but statement 2 is correct.
Both statements 1 and 2 are incorrect.
The inheritance of flower colour in Antirrhinum (dog flower) is an example of
incomplete dominance
co-dominance
multiple alleles
linkage.
Phenotypic and genotypic ratio is similar in case of
Complete dominance
incomplete dominance
epistasis
Over dominance
In four o’ clock plants, the gene for red flower colour (R) is in incompletely dominant over the gene for white flower colour (r), hence the plants heterozygous for flower colour (Rr) have pink flowers. What will be the ratio of offsprings in a cross between red flowers and pink flowers?
75% red flowers, 25% pink flowers
All red flowers
50% red flowers, 50% pink flowers
Red : pink : white : : 1 : 2 : 1
Andalusian fowls have two pure forms -black and white. If black forms (BB) and white forms (WW) are crossed, F1 individuals appear blue coloured (BW), due to incomplete dominance. Which of the following would be an outcome of a cross between black form and blue form?
1 Black : 2 Blue : 1 White
2 Black : 1 Blue
1 Black : 2 Blue
1 Black : 1 Blue
ABO blood groups in human beings are controlled by the gene |. The gene | has three alleles - |A, |B and i. Since there are three different alleles, six different genotypes are possible.
How many phenotypes can occur?
Six
Two
Three
Four
What can be the blood group of offspring when both parents have AB blood group?
AB only
A, B and AB
A, B, AB and O
A and B only
A cow with red coat is crossed with a bull having white coat. Their offspring produced in F1 generation showed roan coat. This effect is produced due to juxtaposition of small patches of red and white colour. What can be assumed about the gene controlling coat colour in cattle?
The alleles of gene controlling coat colour show a perfect dominant recessive relationship.
The alleles of gene controlling coat colour are incompletely dominant.
The alleles of gene controlling coat colour are co-dominant.
None of these.
ABO blood grouping in human beings cites the example of
Incomplete dominance
Co-dominance
Multiple allelism
Both (b) and (c)
In mice, Y is the dominant allele for yellow fur and y is the recessive allele for grey fur. Since Y is lethal when homozygous, the result of cross Yy x Yy will be
3 Yellow : 1 grey
2 yellow : 1 grey
1 yellow : 1 grey
1 yellow : 2 grey
In mendelian dihybride cross, when heterozygous round yellow are self-crossed, round green offspring are represented by the genotype.
RrYy, RrYY, RRYy
Rryy, RRyy. Rryy
rrYy, rrYY
Rryy, RRyy
Match column I with column II and select the correct option from the given codes.
Column I Column II
A Dihybrid test cross (i) 9:3:3:1
B Law of segregation (ii) Dihybrid cross
C Law of independent (iii) 1:1:1:1
assortment
D ABO blood group (iv) Purity of gametes
in man
(v) Multiple allelism
A-(iii), B-(iv), C-(ii), D-(v)
A-(i), B-(iv), C-(ii), D-(v)
A-(iii), B-(ii), C-(iv), D-(v)
A-(ii), B-(v), C-(iii), D-(i)
When a cross is made between a tall plant with yellow seed (Tt Yy) and a tall plant with green seeds (Tt yy), what is true regarding the proportions of phenotypes of the offsprings in F1 generation?
Proportion of Tall and Green - 3/8
Proportion of Dwarf and Green - 1/8
Proportion of Tall and Green - 2/8
Proportion of Dwarf and Green - 1/8
Proportion of Tall and Green - 1/8
Proportion of Dwarf and Green - 3/8
Proportion of Tall and Green - 2/8
Proportion of Dwarf and Green - 2/8
How many types of gametes can be produced by a diploid organism who is heterozygous for loci?
4
8
16
32
In certain plant, yellow fruit colour (Y) is dominant to green fruit colour (y) and round shape (R) is dominant to oval shape (r). The two genes involved are located on different chromosomes.
Which of the following will result when plant YyRr is self-pollinated?
9:3:3:1 ratio of phenotypes only
9:3:3:1 ratio of genotypes only
1:1:1:1 ratio of phenotypes only
1:1:1:1 ratio of phenotypes and genotypes
In certain plant, yellow fruit colour (Y) is dominant to green fruit colour (y) and round shape (R) is dominant to oval shape (r). The two genes involved are located on different chromosomes.
Which of the following is correct for the condition when plant YyRr is back crossed with the double recessive parent?
9:3:3:1 ratio of phenotypes only
9:3:3:1 ratio of genotypes only
1:1:1:1 ratio of phenotypes only
1:1:1:1 ratio of phenotypes and genotypes
“When two pairs of traits are combined in a hybride, segregation of one pair of characters is independent of the other pair of characters”. The statement explains which of the following laws/principles of mendel?
Principle of paired factors
Principle of dominance
Law of segregation
Law of independent assortment
Law of independent assortment can be explained with the help of
dihybride
test cross
back cross
monohybride cross
Which three scientists independently rediscovered mendel’s work?
Avery, Mcleod, McCarty
Sutton, Morgan and Bridges
Bateson, Punnet and Bridges
de Vries, Correns and Tschermak
Chromosomal theory of inheritance was given by
Morgan et al
Sutton and Boveri
Hugo de Vires
Gregor J. Mendel
Experimental verification of ‘chromosomal theory of inheritance’ was done by
Sutton and Boveri
Morgan et al
Henking
Karl Correns
Match column I with column II and select the correct option from the given codes.
Column I Column II
A. Multiple allelism (i) Tt x tt
B. Back cross (ii) Tt x TT
C. Test cross (iii) Human blood groups
D. Crossing over (iv) Non – parental gene
combination
E. Recombination (v) Non – sister
chromatids
A-(iii), B-(i), C-(ii), D-(v), E-(iv)
A- (iii), B-(ii), C-(i), D-(v), E-(iv)
A-(iii), B-(ii), C-(i), D-(iv), E-(v)
A-(iv), B-(ii), C-(i), D-(v), E-(iii)
Genes located very close to one another on same chromosome tend to be transmitted together and are called
allelomorphs
linked genes
recessive genes
identical genes
Males of silkworm Bombyx mori are known to produce more silk per unit quantity of leaf consumed. Hence, they are preferably bred in sericulture industry. Which of the following genotypes should be crossed in order to get maximum fraction of healthy male insects?
(i) and (iv)
(i) and (iii)
(ii) and (iii)
(ii) and (iv)
The cross over percentage between linked genes J and M is 20%, J and L is 35%, J and N is 70%, L and K is 15%, M and N is 50%, and M and L is 15%. Thus, the sequences of genes on the chromosomes is
J, N, M, L, K
J, M, L, N, K
J, M, L, K, N
M, J, L, K, N
A woman who is a carrier of a certain disease marries a man who is normal for this trait. They have five children (2 daughters and 3 sons). All sons suffer from the given disease but none of the daughters were affected as the disease show diagynic pattern. Which of the following could be this disease?
Autosomal recessive disease
Sex-linked disease
Sex-limited disease
Autosomal dominant disease
Consider the following statements regarding chromosomal aberrations and select the incorrect ones.
I. Chromosomal aberrations refer to changes in number and arrangement of genes in the chromosomes.
II. Aneuploidy refers to the condition where the genome comprises of extra or fewer chromosomes than its normal number in a species.
III. Heteroploidy occurs due to non-disjunction of chromosomes of homologous pair.
IV. Nullisomy is a type of hyperploidy in which one chromosome is devoid of its homologue.
II and III
IV only
II only
I, III and IV
The allele for pea comb (P) in chickens is completely dominant to the allele for single comb (p). The alleles for black feather colour (B), and white feather colour (B’) show incomplete dominance, so that BB’ individuals possess grey feathers. If chickens heterozygous for both pairs of genes are matched, what proportion of offspring are expected to be single combed and grey feathered?
9/16
3/16
1/16
2/16
Study the two cases carefully. What would be the correct interpretation of the two cases?
Case Mother Father Children
Case I With Normal son always with
disease diseases
Case II With Normal Sons and daughters
disease could show disease
Case I : X-linked recessive disease
Case II : Autosomal recessive disease
Case I : Y-linked recessive disease
Case II : X-linked recessive disease
Case I and II : X-linked recessive disease
Case I : X-linked dominant disease
Case II: Autosomal dominant disease
A pedigree is shown below for a disease that is autosomal dominant. What would be the genetic make up of the first generation?
AA, Aa
Aa, aa
Aa, AA
Aa, Aa
In humans, attached earlobes are a dominant feature over free earlobes while hypertrichosis of the ear is a holandric (Y-linked) feature. A man with attached earlobes and extensive hair on pinna married a woman having free earlobes. The couple had one son with attached earlobes and hairy pinna, another son with free earlobes and hairy pinna and two daughters with attached earlobes. One of the daughters married a man with free earlobes and sparse hair on pinna. They had two sons. What would be the characteristics of their pinnae?
Both will have attached earlobes and sparse hair on pinna.
There would be equal chances for both having free or attached earlobes and sparse hair on pinnae.
They would have hairy pinnae and there would be 1 in 8 chance that both will have attached earlobes.
Both will have free earlobes and extensive hair on pinnae.
Mother and father of a person with ‘O’ blood group have ‘A’ and ‘B’ blood group respectively. What would be the genotype of both mother and father?
Mother is homozygous for ‘A’ blood group and father is heterozygous for ‘B’.
Mother is heterozygous for ‘A’ blood group and father is homozygous for ‘B’.
Both mother and father are heterozygous for ‘A’ and ‘B’ blood group, respectively.
Both mother and father are homozygous for ‘A’ and ‘B’ blood group, respectively.
In the F2 generation of a mendelian dihybrid cross the number of phenotypes and genotypes are
phenotypes-4; genotype-16
phenotypes-9; genotypes-4
phenotypes-4; genotypes-8
phenotypes-4; genotypes-8
It is said that Mendel proposed that the factor controlling any character is discrete and independent. His proposition was based on the
Results of F3 generation of a cross
Observations that the offspring of a cross made between the plants having two contrasting characters shows only one character without any blending.
Self-pollination of F1 offsprings
Cross pollination of F1 generation with recessive parent.
The inheritance pattern of a gene over generations among humans is studied by the pedigree analysis. Character studied in the pedigree analysis is equivalent to
Quantitative trait
Mendelian trait
Polygenic trait
Maternal trait
Occasionally, a single gene may express more than one effect. The phenomenon is called
Multiple allelism
Mosaicism
Pleiotropy
Polygeny
In a dihybrid cross, if you get 9:3:3:1 ratio it denotes that
The alleles of two genes are interacting with each other
It is a multigenic inheritance
It is a case of multiple allelism
The alleles of two genes are segregating independently.
ZZ/ZW type of sex determination is seen in
Platypus
snails
cockroach
peacock
Person having genotype /A /B would show the blood group as AB. This is because of
pleiotropy
co – dominance
segregation
incomplete dominance
In sickle cell anaemia glutamic acid is replaced by valine. Which one of the following triplet codes for valine?
G G G
A A G
G A A
G U G
Distance between the genes and percentage of recombination shows
a direct relationship
an inverse relationship
no relationship.
a parallel relationship
Conditions of a karyotype 2n± 1 and 2n ± 2 are called
aneuploidy
polyploidy
allopolyploidy
monosomy
Which of the following trait is controlled by sex linked recessive genes?
Polydactyly
Huntington’s chorea
PTC (Phenylthiocarbamide) tasting
Haemophilia
. In this disease, there occurs a failure of chloride ion transport mechanism in cell surface membrane of epithelial cells; sweat of the patient conditions very high level of Na+ and Cl- ions. This disease is
Thalassemia
Alzheimer’s disease
Gaucher’s disease
Cystic fibrosis
Select the disease which is caused by recessive autosomal genes when present in homozygous condition
Alkaptonuria
Thalassemia
Cystic fibrosis
All of these
. If both parents are carriers for thalassemia, which is an autosomal recessive disorder, what are the chances of pregnancy resulting in an affected child?
25%
100%
No chance
50%
Which of the following is not an example of recessive autosomal disease?
Haemophilia
Cystic fibrosis
Phenlketonuria
Sickle-cell anaemia
An individual affected by phenylketonuria lacks an enzyme that converts the amino acid _________ into __________.
Tyrosine, phenylalanine
Phenylalanine, tyrosine
Homogentistic acid, phenylalanine
Homogentisic acid, tyrosine.
Red green colourblindness is a sex linked trait. Which of the given statements is not correct regarding colourblindness?
It is more common in males than in females.
Homozygous recessive condition is required for the expression of colourblindness in female.
Males can carriers of the trait.
Colourblind women always have colourblind father and always produce colourblind son.
The disease sickle-cell anaemia is caused by the substitution of (i) by (ii) at the (iii) position of (iv) globin chain of haemoglobin molecule.
Which of the following correctly fills the blanks in the above statement?
(i) valine, (ii) glutamic acid, (iii) sixth, (iv) beta
(i) glutamic acid, (ii) valine, (iii) sixth, (iv) beta
(i) glutamic acid, (ii) valine, (iii) fifth, (iv) beta
(i) valine, (ii) glutamic acid, (iii) fifth, (iv) beta
A marriage between a colourblind man and a normal woman produces.
All carrier daughters and normal sons.
50% carrier daughters, 50% normal daughters.
50% colourblind sons, 50% normal sons
All carrier offsprings
A colourblind man (XcY) marries a woman who is carrier for haemophilia (XXh). Which of the following is true for their progenies?
25% female progenies carry the genes for both haemophilia and colourblindness.
25% male progenies carry only the gene for haemophilia.
25% female progenies carry only the gene for colourblindness.
All of these.
If a haemophilic man marries a carrier woman then which of the following holds true for their progenies?
50% daughters are carrier and 50% are haemophilic.
All the daughters are haemophilic.
All sons are haemophilic and all daughters are normal.
All sons normal, all daughters carriers.
____________ is an example of X-linked recessive trait.
Phenylketonuria
Haemophilia
Cystic fibrosis
Sickle-cell anaemia
In heritance of which of the following traits is shown in the given cross?
X-linked dominant trait
X-linked recessive trait
Autosomal recessive trait
Autosomal dominant trait
Refer to the given family tree and answer the question.
What are the chances of this couple’s fifth child being an albino?
1 in 1
1 in 2
1 in 3
1 in 4
Refer to the given family tree and answer the question.
If A=normal allele, a=albino allele, then genotypes of father and mother are respectively.
Aa and Aa
AA and Aa
Aa and AA
Aa and aa
Study the pedigree chart of a family showing the inheritance of myotonic dystrophy.
The trait under study is
Dominant X-linked
Autosomal dominant
Recessive X-linked
Recessive Y-linked
Study the pedigree chart of a family showing the inheritance of sickle-cell anaemia
The traits traced in the above pedigree chart is
Dominant X-linked
Recessive X-linked
Autosomal dominant
Autosomal recessive
Given pedigree chart depicts the inheritance of attached ear lobes, an autosomal recessive trait.
Which of the following conclusions drawn is correct?
Parents are heterozygous.
Parents are homozygous dominant.
Parents are homozygous recessive.
None of these
In humans, polydactyly (i.e, presence of extra fingers and toes is determined by a dominant autosomal allele (P) and the normal condition is determined by a recessive allele (p). Find out the possible genotypes of family members 1, 2 and 3 in the given pedigree.
1. PP 2. Pp 3. pp
1. PP 2. PP 3. pp
1. Pp 2. PP 3.Pp
1. Pp 2. Pp 3. pp
In maize, coloured endosperm (c) is dominant over colourless (c); and full endosperm (R) is dominant over shrunken (r). When a dihybrid of F1 generation was test crossed, it produced four phenotypes in the following percentage:
Coloured full – 48% Coloured shrunken – 5%
Colourless full – 7% Colourless shrunken – 40%
From this data, what will be the distance between two non- allelic genes?
48 units
5 units
7 units
12 units
Refer to the given figure of cross A and cross B and select the correct statement regarding them.
In cross A, the strength of linkage genes y and w is higher than the cross B genes w and m.
In cross A, the strength of linkage between genes y and w is lesser than the cross B genes w and m.
Both cross A genes y and w and cross B genes w and m have the same strength of linkage.
The percentage of recombinants produced in cross A is higher than cross B.
What is true about the crossing over between linked genes?
No crossing over at all
High percentage of crossing over
Hardly and crossing over
None of these
Chromosome maps/genetic maps were first prepared by
Sutton and Boveri (1902)
Bateson and Punnett (1906)
Morgan (1910)
Sturtevant (1911)
Given diagram shows a pair of homologous chromosomes during meiosis.
Maximum crossing over will occur between genes
A and a, D and
C and d, c and D
B and c, b and C
A and d, a and D
Which of the following are reasons for Mendel’s success?
(i) Usage of pure lines or pure breeding varieties
(ii) Consideration of one character at a time
(iii) Maintenance of statistical records of experiments
(iv) Knowledge of linkage and incomplete dominance
(i) and (ii) only
(i), (ii) and (iii)
(i) and (iv) only
(ii), (iii) and (iv)
If linkage was known at the time of mendel then which of the following laws, he would not have been able to explain?
Law of dominance
Law of independent assortment
Law of segregation
Law of purity of gametes
Read the given statement and select the correct option.
(i) Percentage of homozygous dominant individuals obtained by selfing Aa individuals is 25%.
(ii) Types of genetically different gametes produced by genotype AABbcc are 2.
(iii) Phenotypic ratio of monohybrid F2 progency in case of Mirabilis jalapa is 3:1.
All the statements are true.
Statements (i) and (ii) are true, but statement (iii) is false.
Statements (i) and (iii) are true, but statement (ii) is false.
Statements (ii) and (iii) are true, but statement (i) is false.
In polygenic inheritance
Many genes govern a single character
Heterozgous organisms express only one allele itself
Heterozygous organisms express both alleles
A single gene influence many characters.
In a cross between negro and albino skin colour of humans showing polygenic inheritance, the phenotypic ratio in F2 generation will be
9:3:3:1
1:6:15:20:15:6:1
1:4:6:4:1
1:2:2:4:1:2:1:2:1
When a single gene influences more than one trait it is called
Pseudo -dominance
pleiotropy
epistasis
none of these
XO type of sex determination and XY type of sex determination are the examples of
Male heterogamety
Female heterogamety
Male homogamety
Both (b) and (c)
Select the correct statements regarding honeybees.
(i) The queen bee and the worker bees develop from fertilized eggs and are sexually females.
(ii) Males (drones develop parthenogenetically from unfertilized eggs.
(iii) Queen bee feeds upon royal jelly and the worker bees feed upon bee bread.
(i) and (ii) only
(ii) and (iii) only
(i) and (iii) only
(i), (ii) and (iii)
Number of autosomes present in liver cells of a human female is
22 autosomes
22 pairs
23 autosomes
23 pairs
In honeybees, females are (i) having (ii) chromosomes and males are (iii) having (iv) chromosomes.
(i) diploid (ii) 46 (iii) haploid (iv) 23
(i) haploid (ii) 23 (iii) diploid (iv)46
(i) diploid (ii) 32 (iii) haploid (iv) 16
(i) haploid (ii) 16 (iii) diploid (iv) 32
Refer to the given figure.
This type of sex determination is found in
grasshoppers and cockroaches
birds and reptiles
butterflies and moths
honeybees, ants and wasps
Find out the mismatched pair.
Haemophilia – sex linked recessive
Cystic fibrosis – Autosomal recessive
Down’s syndrome – Trisomy 21
Turner’s syndrome – Y-linked
Refer to the given figure representing karyotype of individual who inflicted with this chromosomal disorder.
Select the correct statement regarding it.
This disorder occurs due to failure of segregation of chromatids during cell division cycle results in the gain of chromosome.
This disorder occurs due to failure of cytokinesis after telophase stage of cell division results in an increase in whole set of chromosome.
Individuals inflicted with this disorder are usually sterile.
Both (a) and (c)
Due to nondisjunction of chromosomes during spermatogenesis, some sperms carry both sex chromosomes (22A + XY) and some sperms do not carry any sex chromosome (22A + O). If these sperms fertilise normal eggs (22A + X), what types of genetic disorders appear accordingly among the offsprings?
Klinerfelter’s syndrome and Turner’s syndrome
Turner’s syndrome and Klinefelter’s syndrome
Down’s syndrome and Turner’s syndrome
Down’s syndrome and cri-du-chat syndrome
Rate of mutation is affected by
Temperature
X- rays
Gamma rays
All of these
Insertion or deletion of a single base causes
inversion mutation
transition mutation
frame – shift mutation
transversion mutation
Point mutation may occur due to
Alteration in DNA sequence
Change in a single base pair of DNA
Deletion of a segments of DNA
Gain of a segment in DNA
Select the incorrect statement regarding pedigree analysis.
Solid symbols show unaffected individuals
Proband is the person from which case history starts
It is useful for genetic counsellors
It is an analysis of traits in several generation of a family.
The possibility of a female becoming hameophilic is extremely rare because mother of such a female has to be at least (i) and father should be (ii).
(i) haemophilic, (ii) carrier
(i) carrier, (ii) haemophilic
(i) haemophilic, (ii) normal
(i) haemophilic, (ii) haemophilic
Read the given statements.
(i) Incomplete or mosaic inheritance is an example of pre-Mendelian concept of blending inheritance.
(ii) Test cross is a special type of back cross.
(iii) Chromosomal aberrations are commonly observed in cancer cells.
(iv) Thalassemia is a Mendelian disorder.
Which of the above statements are correct?
(i) and (ii) only
(ii), (iii) and (iv) only
(ii) and (iv) only
(i) and (iv) only
